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Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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17 Sep 2010, 03:20

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Both Robert and Alice leave from the same location at 7:00 a.m. driving in the same direction, but in separate cars. Robert drives 30 miles per hour while Alice drives 40 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?

Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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17 Sep 2010, 10:54

cano wrote:

Both Robert and Alice leave from the same location at 7:00 a.m. driving in the same direction, but in separate cars. Robert drives 30 miles per hour while Alice drives 40 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?

A. 1 p.m. B. 3 p.m. C. 4 p.m. D. 8 p.m. E. 9 p.m.

simply find the distance travelled by Alice it will 240 then we can find the time for Robert as we have distance and speed..!! \(d=s*t\)

Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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17 Sep 2010, 19:17

Extra miles that alice travelled is 10*6 miles = 60 miles. To cover 60 Bob will take 2 hrs more. So effective time he takes is 8 hrs to reach alice
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Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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06 Mar 2015, 18:54

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Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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27 Aug 2017, 15:20

This one does not need relative speed to be calculated. It is a straight forward approach once you find the total distance traveled by one of the cars (which is essentially the same for both cars)

Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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29 Aug 2017, 02:04

Distance travelled by alice in 6 hrs = Speed*time=40*6=240 miles Time taken by Alex to Travel 240 miles = 240/30 {Distance =Speed*Time}=8hrs Start at 7 a.m +8 hrs=1500 hrs (3.00p.m)

Both Robert and Alice leave from the same location at 7:00 a.m. driving in the same direction, but in separate cars. Robert drives 30 miles per hour while Alice drives 40 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?

A. 1 p.m. B. 3 p.m. C. 4 p.m. D. 8 p.m. E. 9 p.m.

We see that Alice drives a total of 40 x 6 = 240 miles in 6 hours. During that time, Robert drives 6 x 30 = 180 miles. So, he has to drive 60 more miles or in 60/30 = 2 more hours.

So, he will reach Alice’s car at 7 a.m. + 8 hours = 3 p.m.

Answer: B
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Re: Both Robert and Alice leave from the same location at 7:00 a.m. drivin [#permalink]

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02 Sep 2017, 08:07

This is a basic rate problem.

In six hours, Alice will have driven 60 more miles than Bob because Alice drives 10 miles faster than Bob for 6 hours. To cover the additional 60 miles that Alice has driven, Bob will have to travel two more hours given his rate at 30mph. In totality, Bob will have to drive 8 miles to arrive at the same spot that Alice stopped at. 7am plus 8 hours is 3pm. Answer is B.

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