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605-655 (Medium)|   Algebra|      
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chetan2u
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What is the value of 16xy^2+32x^2y? 24 Feb 2017, 08:44
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E
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45% (medium)

Question Stats:

66% (02:11) correct 34% (01:45) wrong based on 306 sessions

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What is the value of \(32xy^2+16x^2y\)?

(1) \((x+2y)^2=64\)
(2) x=2y

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E
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What is the value of 16xy^2+32x^2y? 24 Feb 2017, 09:13
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chetan2u
What is the value of \(32xy^2+16x^2y\)?

(1) \((x+2y)^2=64\)
(2) x=2y

Show more

Great question!

Target question: What is the value of 32xy² + 16x²y?
After scanning the two statements, I see that we might benefit from rephrasing the target question.
32xy² + 16x²y = 16xy(2y + x)
So.....
REPHRASED target question: What is the value of 16xy(2y + x)?

Statement 1: (x+2y)² = 64
This tells us 2 things: EITHER x+2y = 8 OR x+2y = -8
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 0 and y = 8, in which case 16xy(2y + x) = 0
Case b: x = 1 and y = 7, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x = 2y
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 0 and y = 0, in which case 16xy(2y + x) = 0
Case b: x = 2 and y = 1, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that EITHER x+2y = 8 OR x+2y = -8
Statement 2 tells us that x = 2y

So, we have two possible systems of equations:
x+2y = 8
x = 2y

AND
x+2y = -8
x = 2y

If we solve the first system, we get: x = 4 and y = 2, in which case 16xy(2y + x) = 16(4)(2)[2(2) + (4)] = some POSITIVE number
If we solve the second system, we get: x = -4 and y = -2, in which case 16xy(2y + x) = 16(-4)(-2)[2(-2) + (-4)] = some NEGATIVE number
Since we cannot answer the REPHRASED target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E
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What is the value of 16xy^2+32x^2y? 16 Jul 2017, 14:35
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What is the value of \(32xy^2+16x^2y\)?

\(32xy^2+16x^2y\)

\(= 16xy(2y+x)\)

(1) \((x+2y)^2=64\)

This gives value of \((x+2y)^2\), however, we are not having value for \(xy\)

Hence, (1) ===== is NOT SUFFICIENT

(2) \(x=2y\)

Once again this gives us an equation in "\(y\)" and as we are not having the value of \(y\), we will not be able to determine the value.

Hence, (2) ===== is NOT SUFFICIENT

Combining (1) & (2)

EVen after combining we cannot determine the value of the equation = \(= 16xy(2y+x)\)

Hence, (1) & (2) ===== is NOT SUFFICIENT

Hence, Answer is E

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What is the value of 16xy^2+32x^2y? 20 Dec 2017, 07:14
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chetan2u
What is the value of \(32xy^2+16x^2y\)?

(1) \((x+2y)^2=64\)
(2) x=2y


Great question!

Target question: What is the value of 32xy² + 16x²y?
After scanning the two statements, I see that we might benefit from rephrasing the target question.
32xy² + 16x²y = 16xy(2y + x)
So.....
REPHRASED target question: What is the value of 16xy(2y + x)?

Statement 1: (x+2y)² = 64
This tells us 2 things: EITHER x+2y = 8 OR x+2y = -8
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 0 and y = 8, in which case 16xy(2y + x) = 0
Case b: x = 1 and y = 7, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x = 2y
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 0 and y = 0, in which case 16xy(2y + x) = 0
Case b: x = 2 and y = 1, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that EITHER x+2y = 8 OR x+2y = -8
Statement 2 tells us that x = 2y

So, we have two possible systems of equations:
x+2y = 8
x = 2y

AND
x+2y = -8
x = 2y

If we solve the first system, we get: x = 4 and y = 2, in which case 16xy(2y + x) = 16(4)(2)[2(2) + (4)] = some POSITIVE number
If we solve the second system, we get: x = -4 and y = -2, in which case 16xy(2y + x) = 16(-4)(-2)[2(-2) + (-4)] = some NEGATIVE number
Since we cannot answer the REPHRASED target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E
Show more

I thought that in GMAT, any squared root takes only the positive value not the negative.

(x+2y)^2=64 Take square root of both sides we get
x+2y=8

Why you included -8 here?
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What is the value of 16xy^2+32x^2y? 20 Dec 2017, 07:23
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chetan2u
What is the value of \(32xy^2+16x^2y\)?

(1) \((x+2y)^2=64\)
(2) x=2y


Great question!

Target question: What is the value of 32xy² + 16x²y?
After scanning the two statements, I see that we might benefit from rephrasing the target question.
32xy² + 16x²y = 16xy(2y + x)
So.....
REPHRASED target question: What is the value of 16xy(2y + x)?

Statement 1: (x+2y)² = 64
This tells us 2 things: EITHER x+2y = 8 OR x+2y = -8
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 0 and y = 8, in which case 16xy(2y + x) = 0
Case b: x = 1 and y = 7, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x = 2y
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 0 and y = 0, in which case 16xy(2y + x) = 0
Case b: x = 2 and y = 1, in which case 16xy(2y + x) = some value other than 0
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that EITHER x+2y = 8 OR x+2y = -8
Statement 2 tells us that x = 2y

So, we have two possible systems of equations:
x+2y = 8
x = 2y

AND
x+2y = -8
x = 2y

If we solve the first system, we get: x = 4 and y = 2, in which case 16xy(2y + x) = 16(4)(2)[2(2) + (4)] = some POSITIVE number
If we solve the second system, we get: x = -4 and y = -2, in which case 16xy(2y + x) = 16(-4)(-2)[2(-2) + (-4)] = some NEGATIVE number
Since we cannot answer the REPHRASED target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

I thought that in GMAT, any squared root takes only the positive value not the negative.

(x+2y)^2=64 Take square root of both sides we get
x+2y=8

Why you included -8 here?
Show more


there are two different things....
\(\sqrt{64}\) will laways be positive and will be 8..
but \(x^2=64\) will have two values of x since \(8^2=(-8)^2=64\)
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What is the value of 16xy^2+32x^2y? 20 Jan 2024, 04:46
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