GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Jan 2019, 19:59

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
  • The winning strategy for a high GRE score

     January 17, 2019

     January 17, 2019

     08:00 AM PST

     09:00 AM PST

    Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
  • Free GMAT Strategy Webinar

     January 19, 2019

     January 19, 2019

     07:00 AM PST

     09:00 AM PST

    Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

Committees X, Y and Z have at least three members each. No two of thes

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Director
Director
User avatar
P
Status: Learning stage
Joined: 01 Oct 2017
Posts: 950
WE: Supply Chain Management (Energy and Utilities)
Premium Member
Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 11 Aug 2018, 03:51
5
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

34% (02:33) correct 66% (02:08) wrong based on 73 sessions

HideShow timer Statistics

Committees X, Y and Z have at least three members each. No two of these committees, have any common members. The average (arithmetic mean) ages of the members of X, Y and Z are 30 years, 35 years and 40 years respectively. The average age of the members of X, Y and Z together is 35 years. Does X have more members than Y?
(1) The average age of the members of Y and Z together is at least 38 years
(2) The average age of the members of X and Y together is at most 33 years.

Source:- Time4education
Retired Moderator
avatar
D
Joined: 25 Feb 2013
Posts: 1220
Location: India
GPA: 3.82
GMAT ToolKit User Premium Member Reviews Badge
Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 11 Aug 2018, 04:26
1
PKN wrote:
Committees X, Y and Z have at least three members each. No two of these committees, have any common members. The average (arithmetic mean) ages of the members of X, Y and Z are 30 years, 35 years and 40 years respectively. The average age of the members of X, Y and Z together is 35 years. Does X have more members than Y?
(1) The average age of the members of Y and Z together is at least 38 years
(2) The average age of the members of X and Y together is at most 33 years.

Source:- Time4education


let the number of members in Committees X, Y & Z be \(x, y\) & \(z\) respectively. need to find whether \(x>y\)

given \(30x+35y+40z=35(x+y+z) =>30x+35y+40z=35x+35y+35z\)

\(=>x=z\)

Statement 1: implies \(35y+40z ≥ 38(y+z)=>2z≥3y\) and as \(x=z\), this implies

\(=>x≥\frac{3}{2}y\). Hence \(x>y\). Sufficient

Statement 2: implies \(30x+35y≤33(x+y)\)

\(=>2y≤3x => x≥\frac{2}{3}y\). So \(x>y\) or \(x<y\). Insufficient

Option A
Manager
Manager
User avatar
S
Joined: 21 Jun 2017
Posts: 202
Concentration: Finance, Economics
WE: Corporate Finance (Commercial Banking)
CAT Tests
Re: Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 10 Nov 2018, 23:00
niks18 wrote:
PKN wrote:
Committees X, Y and Z have at least three members each. No two of these committees, have any common members. The average (arithmetic mean) ages of the members of X, Y and Z are 30 years, 35 years and 40 years respectively. The average age of the members of X, Y and Z together is 35 years. Does X have more members than Y?
(1) The average age of the members of Y and Z together is at least 38 years
(2) The average age of the members of X and Y together is at most 33 years.

Source:- Time4education


let the number of members in Committees X, Y & Z be \(x, y\) & \(z\) respectively. need to find whether \(x>y\)

given \(30x+35y+40z=35(x+y+z) =>30x+35y+40z=35x+35y+35z\)

\(=>x=z\)

Statement 1: implies \(35y+40x ≥ 38(y+z)=>2z≥3y\)

\(=>x≥\frac{3}{2}y\). Hence \(x>y\). Sufficient

Statement 2: implies \(30x+35y≤33(x+y)\)

\(=>2y≤3x => x≥\frac{2}{3}y\). So \(x>y\) or \(x<y\). Insufficient

Option A


Hi niks18

Loved your approach ! I analyzed it instead and took me three minutes.

Can you please explain to me how in statement 1 you were sure that x>y while in statement 2 x<y or x>y
I have missed a lot of questions because of this.

This is what i havae always applied (is probably wrong) , in an equality x=5y . x>y since y needs to be multiplied by a larger number to balance out the x.
For inequalities this does not work at all. This was quite evident with this one. Please guide !!!

TIA
_________________

Even if it takes me 30 attempts, I am determined enough to score 740+ in my 31st attempt. This is it, this is what I have been waiting for, now is the time to get up and fight, for my life is 100% my responsibility.

Dil ye Ziddi hai !!!

Intern
Intern
avatar
B
Joined: 29 Apr 2017
Posts: 30
Location: India
Concentration: Finance, Accounting
Re: Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 11 Nov 2018, 02:21
A is sufficient to answer, B - atmost can go either ways
Retired Moderator
avatar
D
Joined: 25 Feb 2013
Posts: 1220
Location: India
GPA: 3.82
GMAT ToolKit User Premium Member Reviews Badge
Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 11 Nov 2018, 04:35
ShankSouljaBoi wrote:
niks18 wrote:
PKN wrote:
Committees X, Y and Z have at least three members each. No two of these committees, have any common members. The average (arithmetic mean) ages of the members of X, Y and Z are 30 years, 35 years and 40 years respectively. The average age of the members of X, Y and Z together is 35 years. Does X have more members than Y?
(1) The average age of the members of Y and Z together is at least 38 years
(2) The average age of the members of X and Y together is at most 33 years.

Source:- Time4education


let the number of members in Committees X, Y & Z be \(x, y\) & \(z\) respectively. need to find whether \(x>y\)

given \(30x+35y+40z=35(x+y+z) =>30x+35y+40z=35x+35y+35z\)

\(=>x=z\)

Statement 1: implies \(35y+40x ≥ 38(y+z)=>2z≥3y\)

\(=>x≥\frac{3}{2}y\). Hence \(x>y\). Sufficient

Statement 2: implies \(30x+35y≤33(x+y)\)

\(=>2y≤3x => x≥\frac{2}{3}y\). So \(x>y\) or \(x<y\). Insufficient

Option A


Hi niks18

Loved your approach ! I analyzed it instead and took me three minutes.

Can you please explain to me how in statement 1 you were sure that x>y while in statement 2 x<y or x>y
I have missed a lot of questions because of this.

This is what i havae always applied (is probably wrong) , in an equality x=5y . x>y since y needs to be multiplied by a larger number to balance out the x.
For inequalities this does not work at all. This was quite evident with this one. Please guide !!!

TIA


Hi ShankSouljaBoi

if you follow the steps then from statement 1 it is evident that \(=>x≥\frac{3}{2}y => x≥1.5y\). Here x, y & z are all positive. so whatever the value of y will be x will be greater than or equal to 1.5 times y. so clearly x>y

similar approach was applied in statement 2.

let me know if this helps or you have any other confusion.
SVP
SVP
User avatar
D
Joined: 26 Mar 2013
Posts: 1998
Reviews Badge CAT Tests
Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 25 Dec 2018, 09:03
niks18 wrote:
[

let the number of members in Committees X, Y & Z be \(x, y\) & \(z\) respectively. need to find whether \(x>y\)

given \(30x+35y+40z=35(x+y+z) =>30x+35y+40z=35x+35y+35z\)

\(=>x=z\)

Statement 1: implies \(35y+40x ≥ 38(y+z)=>2z≥3y\)

\(=>x≥\frac{3}{2}y\). Hence \(x>y\). Sufficient

Statement 2: implies \(30x+35y≤33(x+y)\)

\(=>2y≤3x => x≥\frac{2}{3}y\). So \(x>y\) or \(x<y\). Insufficient

Option A


Hi niks18,
Great way. Small typo highlighted in statement 1. It should be 'z'.
Retired Moderator
avatar
D
Joined: 25 Feb 2013
Posts: 1220
Location: India
GPA: 3.82
GMAT ToolKit User Premium Member Reviews Badge
Re: Committees X, Y and Z have at least three members each. No two of thes  [#permalink]

Show Tags

New post 25 Dec 2018, 10:41
Mo2men wrote:
niks18 wrote:
[

let the number of members in Committees X, Y & Z be \(x, y\) & \(z\) respectively. need to find whether \(x>y\)

given \(30x+35y+40z=35(x+y+z) =>30x+35y+40z=35x+35y+35z\)

\(=>x=z\)

Statement 1: implies \(35y+40x ≥ 38(y+z)=>2z≥3y\)

\(=>x≥\frac{3}{2}y\). Hence \(x>y\). Sufficient

Statement 2: implies \(30x+35y≤33(x+y)\)

\(=>2y≤3x => x≥\frac{2}{3}y\). So \(x>y\) or \(x<y\). Insufficient

Option A


Hi niks18,
Great way. Small typo highlighted in statement 1. It should be 'z'.


Hi Mo2men,

Thanks for highlighting. Edited it
GMAT Club Bot
Re: Committees X, Y and Z have at least three members each. No two of thes &nbs [#permalink] 25 Dec 2018, 10:41
Display posts from previous: Sort by

Committees X, Y and Z have at least three members each. No two of thes

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.