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Company M has two divisions - X and Y. Each division

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Company M has two divisions - X and Y. Each division  [#permalink]

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New post 15 Jul 2017, 08:38
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  55% (hard)

Question Stats:

57% (01:40) correct 43% (02:02) wrong based on 77 sessions

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Company M has two divisions - X and Y. Each division has exactly two types of employees - clerks and managers. Is the ratio of clerks to managers greater for division X than that for division Y?

(1) Division X has 20% managers.
(2) Company M has 15% managers.

Source: ExpertsGlobal

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Re: Company M has two divisions - X and Y. Each division  [#permalink]

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New post 15 Jul 2017, 09:23
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nguyendinhtuong wrote:
Company M has two divisions - X and Y. Each division has exactly two types of employees - clerks and managers. Is the ratio of clerks to managers greater for division X than that for division Y?

(1) Division X has 20% managers.
(2) Company M has 15% managers.

Source: ExpertsGlobal


Hi...

Q is... Is \(\frac{c_x}{m_x}>\frac{c_y}{m_y}\) ?
Individually each statement is insufficient..

It may seem that combined also it is insufficient as details of y is not given.
But if M consists of only x and y, and the ratio of C:m is 20:80 in x or 1:4 AND overall it is 15:85..
Y will have even lower Ratio than overall to bring down ratio in x of 20/80 to 15/85..
Hence sufficient

C
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Company M has two divisions - X and Y. Each division  [#permalink]

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New post 15 Jul 2017, 09:56
1. Division X has 20% managers to the 80% clerks,
the ratio of managers to clerks in division X is \(\frac{1}{4}\)
Since we do not have any idea about the Division Y, this statement is not sufficient

2. It has been said the managers in the company are 15%, making the clerks 85%
The overall ratio of managers to clerks is \(\frac{3}{17}\).
Again, without the information in both the divisions,
we can't clearly tell which division has a higher ratio of managers to clerks.(Insufficient)

On combining the information we can clearly tell that,
Division Y has a lower ratio(Sufficient) (Option C)
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Re: Company M has two divisions - X and Y. Each division  [#permalink]

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New post 15 Jul 2017, 10:23
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My thought process was:

(1) Ok, we know the ratio of clerks/managers for division x, but know nothing about division y's ratio (NS)
(2) Now we know the company's ratio of clerks/managers, but know nothing about the proportion at each division (NS)

Together the statements tell us that the ratio of clerks/managers for division x is below the company's ratio, meaning that division y must have more clerks/managers

Answer: C
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Re: Company M has two divisions - X and Y. Each division  [#permalink]

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New post 14 Feb 2019, 09:42
chetan2u wrote:
nguyendinhtuong wrote:
Company M has two divisions - X and Y. Each division has exactly two types of employees - clerks and managers. Is the ratio of clerks to managers greater for division X than that for division Y?

(1) Division X has 20% managers.
(2) Company M has 15% managers.

Source: ExpertsGlobal


Hi...

Q is... Is \(\frac{c_x}{m_x}>\frac{c_y}{m_y}\) ?
Individually each statement is insufficient..

It may seem that combined also it is insufficient as details of y is not given.
But if M consists of only x and y, and the ratio of C:m is 20:80 in x or 1:4 AND overall it is 15:85..
Y will have even lower Ratio than overall to bring down ratio in x of 20/80 to 15/85..
Hence sufficient

C


How ? i used variables x and y , kept getting stuck. Can you please help with the algebraic approach?


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Re: Company M has two divisions - X and Y. Each division   [#permalink] 14 Feb 2019, 09:42
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