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# Company Y employs c women and d men. Do the women at Company Y earn an

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Math Expert
Joined: 02 Sep 2009
Posts: 62291
Company Y employs c women and d men. Do the women at Company Y earn an  [#permalink]

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25 Nov 2019, 01:39
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45% (medium)

Question Stats:

65% (01:55) correct 35% (01:52) wrong based on 68 sessions

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Company Y employs c women and d men. Do the women at Company Y earn an average (arithmetic mean) annual salary greater than \$25,000?

(1) Company Y pays its employees a total of \$30,000(c + d) in salaries annually.
(2) The men at Company Y earn an average (arithmetic mean) annual salary of \$34,000.

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Joined: 02 Aug 2009
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Re: Company Y employs c women and d men. Do the women at Company Y earn an  [#permalink]

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29 Nov 2019, 20:18
Company Y employs c women and d men. Do the women at Company Y earn an average (arithmetic mean) annual salary greater than \$25,000?

(1) Company Y pays its employees a total of \$30,000(c + d) in salaries annually.
This tells us that the average for all is 30000

(2) The men at Company Y earn an average (arithmetic mean) annual salary of \$34000

Combined
We do not know the value or RATIO of c and d.
Say there is only 1 male and 10 females..34000+10x=30000*11.....x=29600>25000
But say male are 9 and female 1....34000*5+x=30000*6......x=180000-170000=10000<25000

E
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Re: Company Y employs c women and d men. Do the women at Company Y earn an  [#permalink]

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01 Dec 2019, 01:19
Im confused

when the statement says that company Y pays 30000(C+D) annual salary
Can you not expand the equation into 30000C + 30000D
That means that the women get 30000C salary annually. So the average will be 30000C / C which gives 30K which is greater than 25K

Where am i going wrong in the logic?
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Re: Company Y employs c women and d men. Do the women at Company Y earn an  [#permalink]

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01 Dec 2019, 05:38
1
Quote:
Im confused

when the statement says that company Y pays 30000(C+D) annual salary
Can you not expand the equation into 30000C + 30000D
That means that the women get 30000C salary annually. So the average will be 30000C / C which gives 30K which is greater than 25K

Where am i going wrong in the logic?

devavrat, let's use contr-example
Let's say, c=1 and d=1, so (c+d)=2 and the total they earn = \$30,000*(c+d) = \$30,000*2 = \$60,000

Could it be the case that woman earns \$20,000 and man earns \$40,000?
\$20,000*c + \$40,000*d = \$20,000*1 + \$40,000*1 = \$60,000

This example shows that even if the total can be represented in the form \$30,000*(c+d), it does not nesessary lead to the fact that both, women and men, has the same mean salary of \$30,000.
Hope it helps a bit.
Re: Company Y employs c women and d men. Do the women at Company Y earn an   [#permalink] 01 Dec 2019, 05:38
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