Cyclist A leaves point X at 12 noon and travels at constant velocity

Question

Cyclist A leaves point X at 12 noon and travels at constant velocity in a straight path. Cyclist B leaves point X at 2 p.m. travels the same path at constant velocity, and overtakes A at 4p.m. What was the speed of B?
 
(1) Cyclist A weighs twice as much as cyclist B.
(2) When Cyclist B overtook cyclist A, both had traveled 75 miles.

askul2389 · Answer

we need to find either of following parameters :
1. distance travelled
2. speed of A

weight is irrelevent

only statement 2 is sufficient.

kunalsinghNS · Answer

Statement 2 is sufficient since the distance travelled is provided and we know the time hence, one can calculate using the formula S=D/T

hence, statement 2 is sufficient.

eddy8700 · Answer

Cyclist A leaves point X at 12 noon and travels at constant velocity in a straight path. Cyclist B leaves point X at 2 p.m. travels the same path at constant velocity, and overtakes A at 4p.m. What was the speed of B?

(1) Cyclist A weighs twice as much as cyclist B.
(2) When Cyclist B overtook cyclist A, both had traveled 75 miles.

if combined distance travelled by them is 75 miles
then answer is E

if individual distance is 75 miles then the answer should be B

gmathopeful19 · Answer

B) 75/2hr is B's speed

Sent from my iPhone using GMAT Club Forum

TheKingInTheNorth · Answer

(2) When Cyclist B overtook cyclist A, both had traveled 75 miles.

B+A= 75 
OR
B=75 , A=75

?
Confusing statement

gmathopeful19 · Answer

It's not confusing at all. They each went 75miles. You don't even need to know about A

Posted from my mobile device

longhaul123 · Answer

But here are we not assuming that the total distance to be traveled is just 75 km?? VeritasPrepKarishma  Mam can you please explain this to me?? Thank you

KarishmaB · Answer

You know that both A and B start from point X. The point where B "overtakes" A, they both are at the same point. 
Stmnt 2 tells us that 
"When Cyclist B overtook cyclist A, both had traveled 75 miles."

So they both would have been 75 miles away from point X. Perhaps to clarify, it would be a good idea to write "both had travelled 75 miles each". If their total distance would have been 75 miles, the stmnt would have said "both had travelled 75 miles together".

Anyway, here it doesn't matter. It is a DS question. Even if they had travelled 75 miles together, you would know that each had travelled 37.5 miles because they had travelled equal distances. Still information would be sufficient to answer the question using stmnt 2 alone.

Tango3 · Answer

A starts at 12 noon
B starts at 2 noon

(1) Cyclist A weighs twice as much as cyclist B.
(2) When Cyclist B overtook cyclist A, both had traveled 75 miles.

Statement 1 is irrelevant

As per statement 2 B overtakes A at 4p.m so total time elapsed is

A - 4 hours
B- 2 hours

D = s x t
DA = sa X 4 ---- A
DB = sb x 2 ---- B

Statement 2 alone is sufficient.

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Cyclist A leaves point X at 12 noon and travels at constant velocity

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