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12 Aug 2020, 01:06
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
47% (01:25) correct
53%
(01:30)
wrong
based on 89
sessions
History
Date
Time
Result
Not Attempted Yet
12 Aug 2020, 01:25
Kudos
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Question Stem: Does x + y = 11 ?
Statement 1:
x^2 + y^2 = 101
(i) if x = 10, y = 1 ---- YES
(ii) if x = 9, y = \(\sqrt{20}\) ---- NO
=> Statement 1 is insufficient
Statement 2:
xy = 10
(i) if x = 10, y = 1 --- YES
(ii) if x =2, y = 5 --- NO
=> Statement 2 is insufficient
Statement 1 & Statement 2:
\((x+y)^{2}\) = \(x^{2} \) + \(y^{2}\) + 2xy
\((x+y)^{2}\) = 101 + 20
\((x+y)^{2}\) = 121
=> x+y = 11 (10,1) ---- YES
or x + y = -11 (-10,-1) ----- NO
=> Statement 1 & Statement 2 are together insufficient
Answer: E
Statement 1:
x^2 + y^2 = 101
(i) if x = 10, y = 1 ---- YES
(ii) if x = 9, y = \(\sqrt{20}\) ---- NO
=> Statement 1 is insufficient
Statement 2:
xy = 10
(i) if x = 10, y = 1 --- YES
(ii) if x =2, y = 5 --- NO
=> Statement 2 is insufficient
Statement 1 & Statement 2:
\((x+y)^{2}\) = \(x^{2} \) + \(y^{2}\) + 2xy
\((x+y)^{2}\) = 101 + 20
\((x+y)^{2}\) = 121
=> x+y = 11 (10,1) ---- YES
or x + y = -11 (-10,-1) ----- NO
=> Statement 1 & Statement 2 are together insufficient
Answer: E
12 Aug 2020, 01:55
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Is x+y=11
(1) x^2+y^2=101
(x+y)^2=101
x^2+y^2+2xy=101
Not Sufficient
(2) xy=10
Not Sufficient
(1) & (2)
x^2+2xy+y^2=101
x^2+20+y^2=101
(x+y)^2=81
x+y=9
Sufficient.
C
(1) x^2+y^2=101
(x+y)^2=101
x^2+y^2+2xy=101
Not Sufficient
(2) xy=10
Not Sufficient
(1) & (2)
x^2+2xy+y^2=101
x^2+20+y^2=101
(x+y)^2=81
x+y=9
Sufficient.
C
