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Eddie purchased baked goods for his brunch. The store sold chocolate

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Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 23 Feb 2017, 12:09
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  25% (medium)

Question Stats:

81% (01:26) correct 19% (01:53) wrong based on 199 sessions

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Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14

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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 23 Feb 2017, 13:23
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Answer : A

Given, 1.99C + 13.99D = 27.92
or, C + (1399/199) *D = 2792/199
or C + 7D = 14 (divisions done with approximation)

Now C= 7 and D=1 are preferred choices as both are presumably purchased.
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 23 Feb 2017, 21:12
Bunuel wrote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14


Eddie cannot buy more than 1 dozen of glazed donuts, since 2*13.99 >27.92
so Amount left with Eddie after buying 1 dozen of glazed donuts = 27.92 - 13.99 = 13.93
Number of chocolate eclairs Eddie purchased = 13.93/1.99 = 14/2 (approximately) = 7

Hence option A is correct
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 21 Mar 2017, 17:01
Since $1.99 is 1 cent below $2, let's check the maximum quantity chocolate eclairs that Eddie can buy. $
28/2 = 14 => but we know that $1.99 is 1 cent below $2, so 14 x 1 cent = 14 => $28 - 14 cents = $27.86 => therefore Eddie must have bought at least one box of one dozen for $13.99
therefore, $27.92-$13.99 = $13.93
$13.93 is 7 cents below $14 => Eddie bought 7 chocolate eclairs
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 22 Mar 2017, 07:31
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Bunuel wrote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14


\(1.99*c + 13.99*d = 27.92\)

13.99 * 2 = 27.98

So, Eddie purchased a maximum of 1 box of donut..

Now, \(1.99*c + 13.99*1 = 27.92\)

Or, \(1.99*c = 27.92 - 13.99\)

Or, \(c = 7\)

Thus, answer must be (A) 7
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 21 Apr 2017, 15:53
Bunuel wrote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14


it clearly couldn't buy 2 boxes of donuts...as 2 boxes cost 27.98
so...27.92 - 13.99 = 13.93.
if eclairs cost 2$, then we need 12$ to buy 6, and 14 to buy 7.
since we approximated up by 0.01 each eclair, 14.00-0.07 = 13.93 = exactly what we need.

therefore, he bought 7 eclairs for sure!
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Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 21 Apr 2017, 21:12
Easiest way to solve this problem is process elimination.
Let's start with A
A is 7
Let a represent chocolate
Let b represent donuts

1.99a + 13.99b = 27.92
(2a - 0.01a) + (14b - 0.01b) = 27.92
(2(7) - 0.01(7)) + (14b - 0.01b) = 27.92
(14 - 0.07) + (14b - 0.01b) = 27.92
13.93 + (14b - 0.01b) = 27.92

b has to be 1 to get 27.92
PROOF

27.92 - 13.93 = 13.99

Answer is A :-D
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 23 Apr 2017, 00:14
Bunuel wrote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14


We know that Eddie cannot buy more than 1 glazed donut because that exceeds the sum of 27.92

The shortcut for solving this problem is plug in a value and use method below

7($2.00) - 7(.01) + $13.99
[$14.00-$.07] + $13.99
[$13.93] + $13.99 = 27.92
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 12 May 2017, 03:14
Quote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?


Sorry maybe this is a stupid question, but how do we know that Eddie purchased both donuts and eclairs for $27.92? from the question info we know that store sells two types of products, and that Eddie spent some money there. We know nothing about his preferences to buy both donuts and eclairs for his brunch. please correct me if i'm wrong..
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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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New post 12 May 2017, 04:13
1
Bunuel wrote:
Eddie purchased baked goods for his brunch. The store sold chocolate eclairs at $1.99 each and glazed donuts in boxes of one dozen for $13.99. If Eddie spent $27.92, how many chocolate eclairs did Eddie purchase?

A. 7
B. 8
C. 12
D. 13
E. 14


13.99 x 2 = 27.98 > 27.92
So Eddie can't buy 2 boxes of glazed donuts..
hence Eddie must have bought 1 glazed donuts.. Remaining value is used for chocolate eclairs & is equal to 27.92 - 13.99 = 13.93

The no. of chocolates Eddie purchased = 13.93 / 1.99 = 7

Answer A.

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Re: Eddie purchased baked goods for his brunch. The store sold chocolate  [#permalink]

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