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08 Jul 2019, 02:25
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D
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Difficulty:
25%
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Question Stats:
60% (00:44) correct
40%
(00:40)
wrong
based on 44
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Five stand-by passengers are waiting for 3 open seats on an airplane flight. In how many different ways can 3 passengers be arranged in these seats?
(A) 10
(B) 15
(C) 20
(D) 60
(E) 125
(A) 10
(B) 15
(C) 20
(D) 60
(E) 125
08 Jul 2019, 02:29
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Bunuel
Five stand-by passengers are waiting for 3 open seats on an airplane flight. In how many different ways can 3 passengers be arranged in these seats?
(A) 10
(B) 15
(C) 20
(D) 60
(E) 125
(A) 10
(B) 15
(C) 20
(D) 60
(E) 125
Arrangements—> Permutations
= 5p3 = 5*4*3 = 60
IMO Option D
Pls Hit kudos if you like the solution
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vinayakvaish
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08 Jul 2019, 02:32
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3 passengers can be selected in 5C3 ways. ie. 10 ways.
The selected passengers can be arranged in 3! ways ie. 6 ways
Together the job can be done in 10*6= 60 ways
Hit Kudos if you found this helpful!!
The selected passengers can be arranged in 3! ways ie. 6 ways
Together the job can be done in 10*6= 60 ways
Hit Kudos if you found this helpful!!
