AKG1593 wrote:

I don't understand the explanation.How do we arrive at the equation:\(n+C(n,3)=8\)?

If we take 8 different types of single flower bouquet then only we can have each table unique.

On the other hand,if we take 4 different types of flowers and decorate 4 tables with single flowers and the other four with different combinations of the 4 types of flowers won't the latter 4 tables essentially be familiar as the type of flowers remain the same irrespective of how we arrange them?

Bunuel,could you take on this one please?

Suppose you take n different type of flowers, so you can have n single flower bouquets.

C(n, 3) means number of unique combinations of 3 from n objects.

So, if n = 4, C (4, 3) = 4!/((4-3)!*3!) = 4

Also, we can have 4 unique combination of 3 flowers, hence all these 4 bouquets will be different from each other.

and with 4 different flowers we can make 4 different single flower bouquets

So, all together we will have 8 different type of bouquets

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Kudos if the answer helped