Last visit was: 10 Jul 2025, 03:26 It is currently 10 Jul 2025, 03:26
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
parkhydel
Joined: 03 Jun 2019
Last visit: 27 Mar 2025
Posts: 224
Own Kudos:
Given Kudos: 60
Posts: 224
Kudos: 17,257
 [205]
9
Kudos
Add Kudos
195
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
GMATCoachBen
Joined: 21 Mar 2017
Last visit: 09 Jul 2025
Posts: 424
Own Kudos:
2,260
 [54]
Given Kudos: 206
Status:Professional GMAT Trainer
Affiliations: GMAT Coach
Location: United States (WA)
GMAT 1: 760 Q50 V44
GMAT 2: 770 Q51 V44
GMAT 3: 770 Q50 V44
GMAT 4: 770 Q50 V45 (Online)
GMAT 5: 780 Q51 V48
Expert
Expert reply
GMAT 5: 780 Q51 V48
Posts: 424
Kudos: 2,260
 [54]
41
Kudos
Add Kudos
13
Bookmarks
Bookmark this Post
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 09 Jul 2025
Posts: 16,101
Own Kudos:
74,236
 [17]
Given Kudos: 475
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,101
Kudos: 74,236
 [17]
11
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
General Discussion
User avatar
Sixcarbs
Joined: 11 Feb 2024
Last visit: 23 Dec 2024
Posts: 2
Own Kudos:
2
 [1]
Posts: 2
Kudos: 2
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATCoachBen
Video solution here (3:38):


It's essential to read carefully, to fully understand the graph and what it's asking for. We must find the specific definition of "4°F less than seasonal" in the passage.
 
­I watched your video. GMAC is giving different answers.

They say it is 0.18 and .03.

I think it is easier than you make it out to be.

4 to the left is a bar with a height of 18, and 8 to the right is a bar with a height of 3. (You counted left for the second one, the second one is actually more not less.)

 ­
User avatar
GMATCoachBen
Joined: 21 Mar 2017
Last visit: 09 Jul 2025
Posts: 424
Own Kudos:
Given Kudos: 206
Status:Professional GMAT Trainer
Affiliations: GMAT Coach
Location: United States (WA)
GMAT 1: 760 Q50 V44
GMAT 2: 770 Q51 V44
GMAT 3: 770 Q50 V44
GMAT 4: 770 Q50 V45 (Online)
GMAT 5: 780 Q51 V48
Expert
Expert reply
GMAT 5: 780 Q51 V48
Posts: 424
Kudos: 2,260
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sixcarbs
GMATCoachBen
Video solution here (3:38):


It's essential to read carefully, to fully understand the graph and what it's asking for. We must find the specific definition of "4°F less than seasonal" in the passage.



 
­I watched your video. GMAC is giving different answers.

They say it is 0.18 and .03.

I think it is easier than you make it out to be.

4 to the left is a bar with a height of 18, and 8 to the right is a bar with a height of 3. (You counted left for the second one, the second one is actually more not less.)

 ­
Where is GMAC giving different answers? Do you have a screenshot? 

Here's a screenshot of the question on exam 1 (taken on 6/16/23), with the same answers as above.

The reason we are counting to the left is that the stem says: "more than 8°F LESS than seasonal". And the passage gives the definition of "LESS than seasonal": "A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0"

@Sajjad1994 One little detail I notice in the screenshot below is that "less than seasonal" and "greater than seasonal" are italicized; this could be nice to add to the question above, since it's helpful in finding the definition efficiently. Italics are reasonably common on DI and can help save time.
Attachments

2024-02-22 20_30_19-Data Insights 9 of 20.png
2024-02-22 20_30_19-Data Insights 9 of 20.png [ 363.92 KiB | Viewed 31141 times ]

User avatar
egmat
User avatar
e-GMAT Representative
Joined: 02 Nov 2011
Last visit: 10 Jul 2025
Posts: 4,601
Own Kudos:
32,346
 [4]
Given Kudos: 686
GMAT Date: 08-19-2020
Expert
Expert reply
Posts: 4,601
Kudos: 32,346
 [4]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
There are at least 2 different versions of this question.  I believe the datasets for these versions are the same.  The difference stems from the question statement. 
  1. So, when you are solving questions and watching solutions, please ensure that you are watching the solution of the appropriate question stem.
  2. Secondly, should different versions be posted as separate threads that are linked, or should they all be in the same thread since the dataset analysis will be common for all? @Sajjad1994. 
Version 1:  Question in the main post in this thread and in the solution posted by GMATCoachBen



Version 2:  Question in Mock 4 that I believe is being referenced by Sixcarbs


 ­
Attachment:
GMAT-Club-Forum-qa2ieu71.png
GMAT-Club-Forum-qa2ieu71.png [ 39.6 KiB | Viewed 3961 times ]
Attachment:
GMAT-Club-Forum-709et04q.png
GMAT-Club-Forum-709et04q.png [ 106.09 KiB | Viewed 3958 times ]
User avatar
MS61
Joined: 05 Jun 2022
Last visit: 26 Jun 2025
Posts: 103
Own Kudos:
41
 [1]
Given Kudos: 124
Location: India
GMAT Focus 1: 605 Q84 V76 DI80
GMAT 1: 540 Q45 V27
GMAT Focus 1: 605 Q84 V76 DI80
GMAT 1: 540 Q45 V27
Posts: 103
Kudos: 41
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This statement " "more than 8°F LESS than seasonal". And the passage gives the definition of "LESS than seasonal": "A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0""
is very difficult to comprehend in such less time. I almost guessed this que because I found it very time consuming to comprehend. Any opinion on this ques wrt time and same experience?
User avatar
egmat
User avatar
e-GMAT Representative
Joined: 02 Nov 2011
Last visit: 10 Jul 2025
Posts: 4,601
Own Kudos:
32,346
 [10]
Given Kudos: 686
GMAT Date: 08-19-2020
Expert
Expert reply
Posts: 4,601
Kudos: 32,346
 [10]
10
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is a difficult GI question – from multiple aspects.
  1. The chart – a histogram – not your typical line or bar chart. Since we don’t handle histograms as much as we handle line or bar charts, the chart itself adds the layer of complexity.
  2. The translation required to understand the histogram – For this one needs to visualize one of the datapoints.
  3. Two definitions – faily complex in the dataset. If one does not use strategic pausing to understand these definitions, then solving this question will be very challenging.
  4. The question statement – that uses the definition is also complex to understand.



The only thing that is not complex in this question is the calculation of probability. That is the simplest aspect of the solution.

So, as you watch this solution, pay close attention to each of the above pointers and work towards building your skill set in ‘owning the dataset’.
­
User avatar
Gemmie
Joined: 19 Dec 2021
Last visit: 27 May 2025
Posts: 501
Own Kudos:
350
 [1]
Given Kudos: 76
Location: Viet Nam
Concentration: Technology, Economics
GMAT Focus 1: 695 Q87 V84 DI83
GPA: 3.55
GMAT Focus 1: 695 Q87 V84 DI83
Posts: 501
Kudos: 350
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
­For a randomly selected day in this 100-day period, the probability that the high temperature was more than 4°F less than seasonal is [0.14] and the probability that the high temperature was more than 8°F less than seasonal is [0.02]

4°F less => - 4
more than 4°F less than seasonal => first two columns in the left: 2 + 12 = 14 => 0.14

8°F less => -8
more than 8°F less than seasonal => first column in the left: 2
=> 0.02
User avatar
pranjalshah
Joined: 11 Dec 2023
Last visit: 05 Jul 2025
Posts: 99
Own Kudos:
116
 [1]
Given Kudos: 202
Location: India
Concentration: Operations, General Management
Schools: ISB '27 (D)
GMAT Focus 1: 735 Q90 V87 DI82
Schools: ISB '27 (D)
GMAT Focus 1: 735 Q90 V87 DI82
Posts: 99
Kudos: 116
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is a silly question but can someone clarify why we cannot perceive the statement "the high temperature was more than 4°F less than seasonal" as (the high temperature was more than) (4°F less than seasonal), instead of (the high temperature was more than 4°F) (less than seasonal).­

Like for example, if I say "the temperature is more than 10°C less than room temperature".
If the Room Temp. is 25°C, then the temp is more than (10°C less than room temperature)
So, the temp is more than 15°C.
User avatar
GMATCoachBen
Joined: 21 Mar 2017
Last visit: 09 Jul 2025
Posts: 424
Own Kudos:
2,260
 [1]
Given Kudos: 206
Status:Professional GMAT Trainer
Affiliations: GMAT Coach
Location: United States (WA)
GMAT 1: 760 Q50 V44
GMAT 2: 770 Q51 V44
GMAT 3: 770 Q50 V44
GMAT 4: 770 Q50 V45 (Online)
GMAT 5: 780 Q51 V48
Expert
Expert reply
GMAT 5: 780 Q51 V48
Posts: 424
Kudos: 2,260
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
 
pranjalshah
This is a silly question but can someone clarify why we cannot perceive the statement "the high temperature was more than 4°F less than seasonal" as (the high temperature was more than) (4°F less than seasonal), instead of (the high temperature was more than 4°F) (less than seasonal).­

Like for example, if I say "the temperature is more than 10°C less than room temperature".
If the Room Temp. is 25°C, then the temp is more than (10°C less than room temperature)
So, the temp is more than 15°C.
pranjalshah Interesting question. For the meaning you wrote above, "the temp is more than (10°C less than room temperature)", we would normally use the word HIGHER or ABOVE instead of "more".

Then, the meaning becomes: "the temp is higher than 15°C", or "the temp is above 15°C".
User avatar
Oppenheimer1945
Joined: 16 Jul 2019
Last visit: 09 Jul 2025
Posts: 795
Own Kudos:
Given Kudos: 223
Location: India
GMAT Focus 1: 645 Q90 V76 DI80
GPA: 7.81
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I really have hard time understanding the meaning of more than less in mathematical terms. Otherwise this is a fairly simple ques of 605 level.

a smart way would be : Try to see both sides of histogram and calculate the probability pair for both cases as the ques is asked for same side of graph (left or right of histogram)

Pair would be either (0.14, 0.02) or (0.18 , 0.03).

First ones goes right .­
Attachments

image_2024-08-01_121300085.png
image_2024-08-01_121300085.png [ 120.43 KiB | Viewed 20427 times ]

User avatar
callingTardis
Joined: 09 Nov 2019
Last visit: 03 Jul 2025
Posts: 31
Own Kudos:
Given Kudos: 176
Posts: 31
Kudos: 22
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Q1:
high temperature was more than 4°F less than seasonal
i.e deviation was more than -4°F
i.e it could be -5°F or -7°F
so it should be 2 days + 12 days + some more days (perhaps 18/2)
so I marked 0.24


Q2:
high temperature was more than 8°F less than seasonal
i.e deviation was more than -8°F
i.e it could be -9°F or -10°F
so it should be 2 days + some more days (perhaps 12/2)
so I marked 0.05


What am I missing? KarishmaB

KarishmaB
parkhydel
Attachment:
12.jpg

For a given city, the graph represents the daily deviation, in degrees Fahrenheit (°F), of the high temperature from the expected high temperature for each day in a 100-day period. Data is grouped into disjoint classes of deviations: for each value of T marked on the horizontal axis, the class centered at T includes all observed deviations greater than or equal to (T-2)°F but less than (T+2)°F. The height of each bar represents the number of deviations in the corresponding class. A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0, and the high temperature is x°F greater than seasonal if it is x°F greater than the right endpoint of the class centered at 0.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

For a randomly selected day in this 100-day period, the probability that the high temperature was more than 4°F less than seasonal is and the probability that the high temperature was more than 8°F less than seasonal is
­
How to read the graph:

- for each value of T marked on the horizontal axis, the class centered at T includes all observed deviations greater than or equal to (T-2)°F but less than (T+2)°F.

This means that the bar centred at 0 goes from -2 to 2 (obvious from the graph) but the values it includes are -2 <= x < 2

- The height of each bar represents the number of deviations in the corresponding class.

The height of this bar centred at 0 is 34 so there were 34 days when the daily deviation was -2 to 2.

- A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0, and the high temperature is x°F greater than seasonal if it is x°F greater than the right endpoint of the class centered at 0.

The left endpoint of class centred at 0 is -2 and right endpoint is 2.
A given day's high temperature is x°F less than seasonal if it is x°F less than -2
A given day's high temperature is x°F greater than seasonal if it is x°F greater than 2.

Example, for a day, the high temperature was more than 4°F less than seasonal when it was less than -6.
and for a day, the high temperature was more than 4°F greater than seasonal when it was more than 6.


Question: For a randomly selected day in this 100-day period, the probability that the high temperature was more than 4°F less than seasonal is ___ and the probability that the high temperature was more than 8°F less than seasonal is ___

There are 100 days.
4°F less than seasonal is values to the left of -6. There are 12 + 2 = 14 such values.
Probability = 14/100 = 0.14

8°F less than seasonal is values to the left of -10. There are 2 such values.
Probability = 2/100 = 0.02

ANSWER: 0.14, 0.02­
User avatar
cheshire
User avatar
DI Forum Moderator
Joined: 26 Jun 2025
Last visit: 09 Jul 2025
Posts: 69
Own Kudos:
56
 [1]
Given Kudos: 24
Posts: 69
Kudos: 56
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
When you actually go to compute those probabilities, you don’t “add some more days” – you just take the full counts shown in the bars and divide by 100.

For “more than 4 °F below seasonal” you want every day with deviation < −4. That is exactly the two left-most bars (centered at −8 and −12) with counts 12 and 2. So:
P(deviation < −4) = \(\frac{12+2}{100}\) = 0.14

For “more than 8 °F below seasonal” you want every day with deviation < −8. That’s only the bar at −12, count = 2, so:
P(deviation < −8) = \(\frac{2}{100}\) = .02
callingTardis
Q1:
high temperature was more than 4°F less than seasonal
i.e deviation was more than -4°F
i.e it could be -5°F or -7°F
so it should be 2 days + 12 days + some more days (perhaps 18/2)
so I marked 0.24


Q2:
high temperature was more than 8°F less than seasonal
i.e deviation was more than -8°F
i.e it could be -9°F or -10°F
so it should be 2 days + some more days (perhaps 12/2)
so I marked 0.05


What am I missing? KarishmaB

KarishmaB
parkhydel
Attachment:
12.jpg

For a given city, the graph represents the daily deviation, in degrees Fahrenheit (°F), of the high temperature from the expected high temperature for each day in a 100-day period. Data is grouped into disjoint classes of deviations: for each value of T marked on the horizontal axis, the class centered at T includes all observed deviations greater than or equal to (T-2)°F but less than (T+2)°F. The height of each bar represents the number of deviations in the corresponding class. A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0, and the high temperature is x°F greater than seasonal if it is x°F greater than the right endpoint of the class centered at 0.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

For a randomly selected day in this 100-day period, the probability that the high temperature was more than 4°F less than seasonal is and the probability that the high temperature was more than 8°F less than seasonal is
­
How to read the graph:

- for each value of T marked on the horizontal axis, the class centered at T includes all observed deviations greater than or equal to (T-2)°F but less than (T+2)°F.

This means that the bar centred at 0 goes from -2 to 2 (obvious from the graph) but the values it includes are -2 <= x < 2

- The height of each bar represents the number of deviations in the corresponding class.

The height of this bar centred at 0 is 34 so there were 34 days when the daily deviation was -2 to 2.

- A given day's high temperature is x°F less than seasonal if it is x°F less than the left endpoint of the class centered at 0, and the high temperature is x°F greater than seasonal if it is x°F greater than the right endpoint of the class centered at 0.

The left endpoint of class centred at 0 is -2 and right endpoint is 2.
A given day's high temperature is x°F less than seasonal if it is x°F less than -2
A given day's high temperature is x°F greater than seasonal if it is x°F greater than 2.

Example, for a day, the high temperature was more than 4°F less than seasonal when it was less than -6.
and for a day, the high temperature was more than 4°F greater than seasonal when it was more than 6.


Question: For a randomly selected day in this 100-day period, the probability that the high temperature was more than 4°F less than seasonal is ___ and the probability that the high temperature was more than 8°F less than seasonal is ___

There are 100 days.
4°F less than seasonal is values to the left of -6. There are 12 + 2 = 14 such values.
Probability = 14/100 = 0.14

8°F less than seasonal is values to the left of -10. There are 2 such values.
Probability = 2/100 = 0.02

ANSWER: 0.14, 0.02­
Moderator:
Math Expert
102612 posts