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Re: For any non-zero a and b that satisfy |ab|=ab and |a|=-a [#permalink]
Thanks Bunnel...very good explanation
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Re: For any non-zero a and b that satisfy |ab|=ab and |a|=-a [#permalink]
Thanks! It is clear now
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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

Theory on Abolute Values: math-absolute-value-modulus-86462.html

DS Abolute Values Questions to practice: search.php?search_id=tag&tag_id=37
PS Abolute Values Questions to practice: search.php?search_id=tag&tag_id=58

Hard set on Abolute Values: inequality-and-absolute-value-questions-from-my-collection-86939.html
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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
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gmatfrenzy750 wrote:
For any non-zero a and b that satisfy |ab| = ab and |a| = -a, |b-4| + |ab-b| =

A. ab-4
B. 2b-ab-4
C. ab+4
D. ab-2b+4
E. 4-ab


We can also plug in values in this question

Given that |a|=-a so we we know a<0 and also |ab|=ab means b<0 because if b>0 then |ab|=-ab

take any negative value of a and b and check which option gives the same value as the above Mod eqn

a=-3, b=-2

|b-4| + |ab-b|

|-6|+ |6- (-2)|------> 6+8=14

a=-1 b =-5

|-9| + |5 - (-5)|= 19

Only Option D satisfies and hence is the answer


Thanks :)
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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
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gmatfrenzy750 wrote:
For any non-zero a and b that satisfy |ab| = ab and |a| = -a, |b-4| + |ab-b| =

A. ab-4
B. 2b-ab-4
C. ab+4
D. ab-2b+4
E. 4-ab


1.We need to find whether ab and b are -ve or +ve
2. Since |ab|=ab, ab is +ve
3. Since |a|=-a, a is -ve.
4. From (2) and (3), b is -ve.
5.Since b is -ve b-4 is -ve and so |b-4| becomes -(b-4)
6. Since ab is +ve and b is -ve, ab-b is +ve and |ab-b| becomes ab-b
7. (5) + (6) = -b+4+ab-b= ab-2b+4
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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
For any non-zero a and b that satisfy |ab| = ab and |a| = -a, |b-4| + |ab-b| =

|ab| = ab and |a| = -a, |b-4| + |ab-b| =

From |a| = -a we get that a is negative because:
|a| = -a and -a must be positive as it is set to an absolute value so:
|a| = -(-a)
a=a

If a is negative then from |ab| = ab we get that b must be negative as well because:
|ab| = (-a)b
(-a)b must be positive as it is set to an absolute value
|ab| = (-a)(-b)
ab=ab

So, both a and b are negative.
|b-4| + |ab-b| =

b is negative and ab is positive. Also, because b is negative we know that (ab-b) = (ab-[-b]) = (ab+b)

-(b-4) + (ab-b) =
-b+4 + ab-b

ab-2b+4

(D)
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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: For any non-zero a and b that satisfy |ab| = ab and |a| = -a [#permalink]
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