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Bunuel
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X2= X3*(X4)^3
X1= X2*(X3)^3

X1= (X3)^4 * (X4)^3

X3=1
X1= (X4)^3
X4=2,X1=8

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Let x1,x2,x,3,x4 be a,b,c,d. a=bc^3, c=1, a=b,

a=b=d^3

a=d^3. only a=8, d=2 satisfies
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What if x1 = (x4)^3 = 0?
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Emily1122
What if x1 = (x4)^3 = 0?
­Hi, 
0 is not a positive number. Question mentions +ve num only.
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