sayansarkar
For nonnegative integers a, b, and c, what is the value of the product abc?
(1) ab=bc
(2) a≠c
I cannot understand the explanation given by veritas prep. Need help on this one. will post the explanation
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
There are 3 variables and 0 equation. Thus the answer E is most likely.
Condition 1)
\(ab = bc\) is equivalent to \(ab - bc = 0\) or \(b(a-c) = 0\).
Thus \(b = 0\) or \(a = c\).
If \(b = 0\), then we have \(abc = 0\).
However, if \(b \ne 0\) and \(a = c\), we have the case \(a = b = c = 1\) with \(abc = 1\).
Since the answer is not unique, this is not sufficient.
Condition 2)
If \(a = 1\), \(b = 1\), \(c = 2\), then \(abc = 2\).
If \(a = 1\), \(b = 2\), \(c = 3\), then \(abc = 6\).
Since the answer is not unique, this is not sufficient either.
Conditions 1) & 2)
From the condition 1), \(ab = bc\) is equivalent to \(ab - bc = 0\) or \(b(a-c) = 0\).
Thus \(b = 0\) or \(a = c\).
However, \(b = 0\), since \(a \ne c\) by the condition 2)
Thus \(abc = 0\).
Therefore, C is the answer.
For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80 % chance that E is the answer, while C has 15% chance and A, B or D has 5% chance. Since E is most likely to be the answer using 1) and 2) together according to DS definition. Obviously there may be cases where the answer is A, B, C or D.