For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8

Question

For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?

(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3

Bunuel · Accepted Answer

Given set in ascending order is {n, n+1,  n+2 , n+4, n+8}.

Mean=\frac{n+(n + 1)+(n + 2)+(n + 4)+(n + 8)}{5}=n+3 ;

Median=middle \ term=n+2 ;

Difference=(n+3)-(n+2)=1 .

Answer: B.

avigutman · Answer

Video solution from Quant Reasoning: Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1 https://www.youtube.com/watch?v=LOqY3mkvaRQ

BrentGMATPrepNow · Answer

To calculate the median, arrange the numbers in ascending order: {n, n + 1,   n + 2  , n + 4, n + 8}
Since we have an ODD number of values, the median is the middlemost term
Median =   n + 2

The mean =  /5
= (5n + 15)/5 
=   n + 3

The mean is how much greater than the median?  
Difference = (  n + 3  ) - (  n + 2  )
= 1

Answer: B

Cheers,
Brent

BrainLab · Answer

Let's say n=2 than the set looks like this (2,3,4,6,10). The Average = 25/5=5 and the median is equal to 4 --> 5-4=1 (B)

GMatAspirerCA · Answer

I did it similar to BrainLab .

plug in numbers, 1 for n.

mean = 1+2+3+5+9/5 = 20/5 = 4

median = 3

difference = 1

Plugin 2 for n

mean = 2+3+4+6+10/5 = 25/5 = 5

median = 4

difference = 1.

luckyme17187 · Answer

if n=1 then 1, 2, 3, 5, 9

3 = median

mean = 20 / 5 = 4

difference =1

PareshGmat · Answer

Mean = \frac{5n+15}{3} = n+3

Median = n+2

Difference = 1

Answer = B

ScottTargetTestPrep · Answer

Let’s first calculate the mean (arithmetic average).

mean = sum/quantity

mean = (n + n + 1 + n + 2 + n + 4 + n + 8)/5

mean = (5n + 15)/5

mean = n + 3

Next, we determine the median. The median is the middle value when the terms are ordered from least to greatest. The terms ordered from least to greatest are as follows:

n, n + 1, n + 2, n + 4, n + 8

The median is n + 2.

Finally we are asked how much greater the mean is than the median. To determine the difference we can subtract the smaller value (the median) from the larger value (the mean) and we get:

n + 3 – (n + 2) = n + 3 – n – 2 = 1

The answer is B.

Shiv2016 · Answer

Add all the terms and the answer is 5n+15
Mean= /5= n+3

Median is the 3rd terms (n+2)

Mean-Median= n+3-n-2=1

Abhishek009 · Answer

Plug in some value for  n , say  n = 1

Thus, the numbers in the sequence are :  1 , 2 , 3 , 5 , 9

Median is 3

Mean = \frac{1 + 2 +3 + 5 + 9}{5}  =  4

So, We have Mean > Mean by 1 , Answer must be (B)

MHIKER · Answer

The ascending order of the number is:  n, n+1, n+2, n+4, n+8

The median  = n+2

The average:  \frac{n+ n+1+n+2+n+4+n+8}{5}=\frac{5n+15}{5}=\frac{5(n+3)}{5}=n+3

The difference  =n+3-n-2=1

The answer is  B

GMATinsight · Answer

Answer: Option B

Step-by-Step Video solution by  GMATinsight

https://www.youtube.com/watch?v=TEPzm4ke9eo

ArnauG · Answer

To find the mean and median for the given sequence of positive numbers, let's calculate them:

Mean = (n + n + 1 + n + 2 + n + 4 + n + 8) / 5 = (5n + 15) / 5 = n + 3.

Now let's arrange the numbers in ascending order:

n, n + 1, n + 2, n + 4, n + 8.

To find the median, we need to determine the middle value. Since there are five numbers in the sequence, the middle value will be the third number, which is n + 2.

The difference between the mean and the median is:

Mean - Median = (n + 3) - (n + 2) = n + 3 - n - 2 = 1.

Therefore, the mean is 1 greater than the median.

Hence, the correct answer is (B) 1.

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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8

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