Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

20 Oct 2015, 03:17

11

52

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

75% (02:15) correct 25% (02:29) wrong based on 1119 sessions

HideShow timer Statistics

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

20 Oct 2015, 04:20

9

4

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

Three of the sandwiches were evenly divided among the students i.e. Amount of Sandwiches with each students = 3/m

Amount of 4th Sandwich with remaining (m-4) students = 1/(m-4)

The amount of Sandwich that carol ate = 3/m + 1/(m-4) = (3m-12+m)/[m(m-4)] = (4m-12)/[m(m-4)]

Answer: option E
_________________

Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

20 Oct 2015, 04:22

Since first three sandwiches were equally divided among m students , Carol ate = 3/m Fourth sandwhich was divided equally among m-4 students , carol ate = 1/(m-4) Amount of sandwhich Carol ate = 3/ m + 1/(m-4) = 4m-12/m(m-4)

Answer E
_________________

When everything seems to be going against you, remember that the airplane takes off against the wind, not with it. - Henry Ford The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long +1 Kudos if you find this post helpful

Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

20 Oct 2015, 09:26

2

1

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

I feel most comfortable to plug in a number for m since the question does allow so.

We have 4 sandwiches to share among m students. m>4. Let m = 6.

3 of the 4 sandwiches are shared equally among 6 students. Therefore we have 3/4 of the 4 sandwiches to share among 6. \(\frac{3}{4}\)/6 = \(\frac{1}{8}\). So we know that one piece is 1/8 of the 4 sandwiches.

Finally, the fourth sandwich is divided among the remaining students. In our case this will be 2 students. We have \(\frac{1}{4}\)/2 = \(\frac{1}{8}\)

Now hungry Carol eats from each one piece. Hence she eats 1/4 of the 4 sandwiches which is a whole sandwich (1 = Target Value) in total.

Plug in 6 in the equations below. Answer D will provide you with a 1 as a result.
_________________

Saving was yesterday, heat up the gmatclub.forum's sentiment by spending KUDOS!

PS Please send me PM if I do not respond to your question within 24 hours.

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

23 Oct 2015, 22:05

reto wrote:

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

I feel most comfortable to plug in a number for m since the question does allow so.

We have 4 sandwiches to share among m students. m>4. Let m = 6.

3 of the 4 sandwiches are shared equally among 6 students. Therefore we have 3/4 of the 4 sandwiches to share among 6. \(\frac{3}{4}\)/6 = \(\frac{1}{8}\). So we know that one piece is 1/8 of the 4 sandwiches.

Finally, the fourth sandwich is divided among the remaining students. In our case this will be 2 students. We have \(\frac{1}{4}\)/2 = \(\frac{1}{8}\)

Now hungry Carol eats from each one piece. Hence she eats 1/4 of the 4 sandwiches which is a whole sandwich (1 = Target Value) in total.

Plug in 6 in the equations below. Answer D will provide you with a 1 as a result.

I think you are having some mistakes here. First of all, the first 3 sandwiches are shared equally among 6 students. So each one will eat: 3/6 = 0.5 (sandwich) Then 4 students do not eat the fourth one, so there are only two members eating including Carol so carol will eat: 1/2 = 0.5 (sandwich) So totally, Carol will eat exactly 1 sandwich, using m = 6, the answer must beE where as your answer D will be that Carol eats 4/3 sandwich (not correct) Using m as a variable or using a particular figure, the answer still must be E.

Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

12 Dec 2015, 03:53

the moment I see the answer choices ‘all variables’ I know I can plug in numbers

Let m=6 so a pie eaten by Carol from 3 sandwiches is 3/6= ½ A pie eaten by Carol from the fourth sandwich = ½ So she had 1 whole sandwich M(m-4)= 6*2=12 so we want 12 in the numerator only E gives the numerator of 12 as (4m-12)=(4*6-12)=12 Ans E
_________________

Please contact me for super inexpensive quality private tutoring

My journey V46 and 750 -> http://gmatclub.com/forum/my-journey-to-46-on-verbal-750overall-171722.html#p1367876

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

10 Jan 2016, 13:16

[quote="NoHalfMeasures"]the moment I see the answer choices ‘all variables’ I know I can plug in numbers

Let m=6 so a pie eaten by Carol from 3 sandwiches is 3/6= ½ A pie eaten by Carol from the fourth sandwich = ½ So she had 1 whole sandwich M(m-4)= 6*2=12 so we want 12 in the numerator only E gives the numerator of 12 as (4m-12)=(4*6-12)=12 Ans E[/quote

I have a question here... Here's my calculation. Please let me know what I'm doing wrong.

Let m=6. so each of the student gets 3/6 or 1/2 of the sandwich. 4th sandwich is shared by only 2 students equaling 1/2 sandwich each. Carol's bite from sandwiches is (1/2)*3+1/4=2.

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

11 Apr 2016, 22:08

Flexxice wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) [m + 4][/m(m - 4)]

B) [2m - 4][/m(m-4)]

C) [4m - 4][/m(m - 4)]

D) [4m - 8][/m(m - 4)]

E) [4m - 12][/m(m - 4)]

I get what I have to do and more or less know how to do it, but in the solution, the OG makes a really weird calculation. Unfortunately, this weird step is needed and I hope someone can explain this step to me.

Carol ate [3][/m] of the first three sandwiches and [1][/m - 4] of the last sandwich. Thus, I have to add both fractions. The following is the OG's way:

I have no idea what has been done in the second step. Could someone please explain this to me? The rest is clear.

Thanks a lot in advance!

it took me some time to understand the solution,but can help you little bit.

there are 4 sandwiches and no of students m , whatever the value may be.

3 sandwiches divided amount student each will get 3/m part. now the 4th sandwich is divided amount m-4 student because 4 student dont want to eat now no of students pending is m-4

carol is among those student who was in both groups so first group got 3/m + second grp got 1/m-4 , becauase only 1 sanwich is left to divide among m-4 students add and calculate.

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

27 Apr 2016, 20:33

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

i put m=6. 3 sandwiches were divided among 6 people. thus, each ate half. last one - 4 refused, and 2 ate half of the fourth. so last 2 ate in total 1 "whole" (by size) sandwich

since we have same denominator, we must find a value for numerator to be equal with it. m(m-4)=6*2=12. so numerator must be 12. only E works.

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

28 Apr 2016, 06:57

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

We are originally given that 4 sandwiches were ordered and that 3 of those sandwiches were divided by m students. Thus, each student had 3/m sandwiches.

However, since 4 students did not want any of the 4th sandwich, the 4th sandwich was actually divided amongst the remaining students, or m – 4 students. Thus, each of the remaining students received 1/(m-4) sandwiches.

We are given that Carol actually ate one piece from each of the four sandwiches. Thus, Carol ate:

3/m + 1/(m- 4)

Getting a common denominator of m(m-4) we have:

(3m-12)/[m(m-4)] + m/[m(m-4)] = (4m-12)/[m(m-4)]

Since a whole sandwich is equal to 1, Carol had (4m-12)/[m(m-4)] of a full sandwich.

Answer: E
_________________

Jeffery Miller Head of GMAT Instruction

GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

06 Jul 2016, 08:02

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

3 sandwiches divided among m students. Hence each student gets 3/m sandwiches

For the last one, 4 students do not want to eat, hence remaining students = m - 4 Each student gets 1/ (m-4) sandwiches

Total sandwiches eaten by Carol = 3/m + 1/(m-4) = 3m - 12 + m / m(m-4) = 4m-12/m(m-4)

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

25 Mar 2017, 06:46

took me a little longer because of tuff wording: smart numbers technique let's 6 be the total number of students students ordered 4 sandwiches, 3 ones were divideded between 6 students, each got 3/6 then the left sandwich were divided between 2 (6-4) students. hence 1/2 got each student

that chick Carol ate one piece in each party: 3/6+1/2=1 question asks what was her fraction of a sandwich: 1/1=1

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

28 Mar 2017, 00:29

JeffTargetTestPrep wrote:

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

We are originally given that 4 sandwiches were ordered and that 3 of those sandwiches were divided by m students. Thus, each student had 3/m sandwiches.

However, since 4 students did not want any of the 4th sandwich, the 4th sandwich was actually divided amongst the remaining students, or m – 4 students. Thus, each of the remaining students received 1/(m-4) sandwiches.

We are given that Carol actually ate one piece from each of the four sandwiches. Thus, Carol ate:

3/m + 1/(m- 4)

Getting a common denominator of m(m-4) we have:

(3m-12)/[m(m-4)] + m/[m(m-4)] = (4m-12)/[m(m-4)]

Since a whole sandwich is equal to 1, Carol had (4m-12)/[m(m-4)] of a full sandwich.

Answer: E

can you please explain, all the students would have had 4m-12/(m(m-4)) pieces except 4 students who refused? because if each student gets 3/m portion - it is similar to 1/m + 1/m + 1/m am i right?

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

28 Mar 2017, 01:02

Avinash_R1 wrote:

can you please explain, all the students would have had 4m-12/(m(m-4)) pieces except 4 students who refused? because if each student gets 3/m portion - it is similar to 1/m + 1/m + 1/m am i right?

Hi,

I think you haven't understood the question correctly. Since Carol ate a piece from all the 4 cakes she belongs to the category of people who did not refuse to eat the 4th cake.

In the first 3 cakes she could eat 3/m In the 4th cake she ate 1/(m - 4)

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

18 Apr 2017, 01:16

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

This is my 2 cents. I plugged m = 12 Then, 3 breads / 12 equally gives = 1/4 As 4 didn't want anymore, 1 bread / 8 gives = 1/8 So, Carol ate (1/4) + (1/8) = 3/8. (3/8) of bread divide by 4 breads gives = 3/24 <--this is the fraction of the bread Carol ate.

What this means is that the numerator needs to be a factor of 3. Only E is --> (4*12)-12 = 36

Re: Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

16 Nov 2017, 16:48

Method - 1 (number picking).

Let us pick a number which is more than 4 and gets divided by 4. The first such number is 8, so let m = 8

so Carol will have \(\frac{1}{8}\) from 1st sandwich, \(\frac{1}{8}\)from 2nd sandwich, and \(\frac{1}{8}\) from 3rd sandwich - total = \(\frac{3}{8}\)

The 4th sandwich will be divided into 4 less part; so it will be divided into 4 parts, of which Carol will have 1/4

So Carol will have a total of \(\frac{3}{8}\) + \(\frac{1}{4}\)= \(\frac{3}{8}\)+ \(\frac{2}{8}\) = \(\frac{5}{8}\)

Now let us apply m = 8 in each of the 5 options to see, which one gives us \(\frac{5}{8}\), the answer will be option E

Method - 2 (algebra).

Carol will have \(\frac{1}{m}\) of a sandwich from 1st, 2nd, and 3rd sandwich, and \(\frac{1}{(m-4)}\) from the 4th sandwich

So Carol will have a total of 3 * \(\frac{1}{m}\) + \(\frac{1}{(m-4)}\), which will lead to option E

Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

08 May 2018, 10:23

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

hey everyone here is my solution, nothing UNordinary this time just a boring algebra:)

Let number of students be \(m\)

Three of the sandwiches were evenly divided among the students. \(\frac{3}{m}\)

Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. \(\frac{1}{m-4}\)

Now sum up \(\frac{3}{m}\) + \(\frac{1}{m-4}\) = \(\frac{3m-12+m}{m(m-4)}\) = \(\frac{4m-12}{m(m-4)}\)

hey niks18 this was my aproach, but what i dont understand is this question

If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

how can this answer \(\frac{4m-12}{m(m-4)}\) represent the amount of sandwich that she ate i mean If Carol ate one piece from each of the four sandwiches

\(\frac{4m-12}{m(m-4)}\) this answer rather represents all four pizzas distrubuted among all students ... please explain i got correct answer but this Carol makes things complicated

Four extra-large sandwiches of exactly the same size were ordered for
[#permalink]

Show Tags

08 May 2018, 11:34

1

dave13 wrote:

Bunuel wrote:

Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

A) (m+4)/[m(m-4)]

B) (2m-4)/[m(m-4)]

C) (4m-4)/[m(m-4)]

D) (4m-8)/[m(m-4)]

E) (4m-12)/[m(m-4)]

Kudos for a correct solution.

hey everyone here is my solution, nothing UNordinary this time just a boring algebra:)

Let number of students be \(m\)

Three of the sandwiches were evenly divided among the students. \(\frac{3}{m}\)

Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. \(\frac{1}{m-4}\)

Now sum up \(\frac{3}{m}\) + \(\frac{1}{m-4}\) = \(\frac{3m-12+m}{m(m-4)}\) = \(\frac{4m-12}{m(m-4)}\)

hey niks18 this was my aproach, but what i dont understand is this question

If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?

how can this answer \(\frac{4m-12}{m(m-4)}\) represent the amount of sandwich that she ate i mean If Carol ate one piece from each of the four sandwiches

\(\frac{4m-12}{m(m-4)}\) this answer rather represents all four pizzas distrubuted among all students ... please explain i got correct answer but this Carol makes things complicated

As per the question Carol ate one piece from each of the four pizzas. Now 3 pizzas were divided equally among m students. Hence each piece from one pizza equals =1/m

the fourth pizza was divided equally among (m-4) students. hence each piece of the 4th pizza equals = 1/(m-4)

So in total Carol ate 1/m+1/m+1/m+1/(m-4) = \(\frac{4m-12}{m(m-4)}\), This is the number of pieces eaten by all those students who ate one piece from all the 4 pizzas.

Other simplified method will be through substitution. Refer solutions above to understand how substitution can solve this problem easily.

gmatclubot

Four extra-large sandwiches of exactly the same size were ordered for &nbs
[#permalink]
08 May 2018, 11:34