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Bunuel
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Given that (a + b) > (c + d), is a > c? (1) a < (c + d) (2) b < d 24 Jul 2018, 02:20
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B
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72% (01:32) correct 28% (01:49) wrong based on 216 sessions

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Given that (a + b) > (c + d), is a > c?

(1) a < (c + d)

(2) b < d
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B
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GMAT Focus 1: 735 Q90 V89 DI81
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Given that (a + b) > (c + d), is a > c? (1) a < (c + d) (2) b < d 24 Jul 2018, 03:29
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Given that (a + b) > (c + d), is a > c?

(1) a < (c + d)
We cannot comment on a>c since we do not know the value of d...
Insufficient

(2) b < d
Now a+b>c+d....
we are adding a lower number to a as compared to c,
a+lower number>c+bigger number.....
a>c+bigger number-lower number...
a>c+(some positive value)....
Hence a>c
Sufficient

B
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Given that (a + b) > (c + d), is a > c? (1) a < (c + d) (2) b < d 24 Jul 2018, 04:13
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Ans: B

given : a+b > c+d
stat:1) a< c+d
from stem data: a> c+d-b ;
clearly even using these two will not give us the exact relation between a and c [Not suff]

Stat:2) b<d
from stem : a+b>c+d (because we know b<d : so for given stat to be true a has to be greater than c [Suff]

Bunuel
Given that (a + b) > (c + d), is a > c?

(1) a < (c + d)

(2) b < d
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Given that (a + b) > (c + d), is a > c? (1) a < (c + d) (2) b < d 08 Jan 2021, 12:45
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My brain is not a linear optimizer, so sometimes it is hard for me to just pick apart the question stem and solve using algebra.
I don't know who it was, but I really appreciated learning that just using algebra to solve inequalities can work in many problems.
Obviously, sometimes intuition is more powerful, but for this question, this approach helped me. These questions feel like a game to me now.


We are given that \((a + b) > (c + d)\)

(1) \(a < (c + d)\)

This means that

\((a + b) > (c + d) > a \)

OR

\(c + d - b < a < (c + d)\)

From here, there is no way to isolate a and c. So, I'd be highly suspicious.
Furthermore, we don't know what d is. Having \(d\) would help.

(2) \(b < d\)

Using the same line of thinking. I can just plug in the inequalities.
I can either isolate \(b\)

\(c + d - a < b < d\) ====== > \(c + d - a < d\)

OR I can isolate d

\(b < d < a + b - c\) ====== > \(b < a + b - c\)

Either one simplifies down to our target, so 2 is sufficient alone.

\(c < a\)
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Given that (a + b) > (c + d), is a > c? (1) a < (c + d) (2) b < d 18 May 2022, 04:22
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