Last visit was: 19 Nov 2025, 11:41 It is currently 19 Nov 2025, 11:41
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
778,326
 [17]
Given Kudos: 99,977
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,326
 [17]
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 13 Aug 2018, 03:45
Kudos
Add Kudos
17
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

65% (hard)

Question Stats:

56% (01:57) correct 44% (01:41) wrong based on 327 sessions

History

Date
Time
Result
Not Attempted Yet
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1
ShowHide Answer
Official Answer
E
User avatar
PKN
User avatar
Joined: 01 Oct 2017
Last visit: 11 Oct 2025
Posts: 814
Own Kudos:
1,587
 [1]
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 814
Kudos: 1,587
 [1]
Given that x ≠ 0, is x^(1/3) > x^(1/5)? Updated on: 13 Aug 2018, 08:28
Originally posted by PKN on 13 Aug 2018, 06:24.
Last edited by PKN on 13 Aug 2018, 08:28, edited 1 time in total.
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1
Show more

Question stem:- Is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

St1:- x < 1
a) when x=1/2, answer to question stem is No.
b) When, x=-1/2, answer to question stem is Yes.
c) When, x=-1, answer to question stem is No.
d) For any value of x less than -1, answer to question stem is No.

Question stem is inconsistent.

St2:- x > –1
]a) When, x=-1/2, answer to question stem is Yes.
b) when x=1/2, answer to question stem is No.
c) When, x=1, answer to question stem is No.
d) For any value of x greater than 1, answer to question stem is yes.

Question stem is inconsistent.
Insufficient.

Combined, we have -1<x<1.
Refer the highlighted points of x, Question stem is still inconsistent.
Insufficient.

Ans. (E)
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 Nov 2025
Posts: 6,839
Own Kudos:
16,354
 [2]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,839
Kudos: 16,354
 [2]
Given that x ≠ 0, is x^(1/3) > x^(1/5)? Updated on: 03 Dec 2018, 00:14
Originally posted by GMATinsight on 13 Aug 2018, 06:57.
Last edited by GMATinsight on 03 Dec 2018, 00:14, edited 1 time in total.
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1
Show more

Question : is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

\(\sqrt[3]{x} > \sqrt[5]{x}\)? only if x is either greater than 1 or less than -1

Statement 1: x < 1

x may be 0.5 or -5 hence

NOT SUFFICIENT

Statement 2: x > -1

x may be -0.5 or 5 hence

NOT SUFFICIENT

Combining the two statements

-1 < x < 1

Hence answer to the question is NO for -0.5 and yes for 0.5 hence

NOT SUFFICIENT

Answer: Option E
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 Nov 2025
Posts: 6,839
Own Kudos:
16,354
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,839
Kudos: 16,354
 [1]
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 13 Aug 2018, 07:10
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PKN
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1

Question stem:- Is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

Let \(\sqrt[3]{x} > \sqrt[5]{x}\)
Or, \(\frac{1}{x^3}-\frac{1}{x^5}>0\)
Or, \(\frac{x^2-1}{x^5}>0\)
Or, \(\frac{\left(x+1\right)\left(x-1\right)}{x^5}>0\)
So, -1<x<0 or, x>1-----------(1)

St1:- x < 1
Question stem is inconsistent. (consistent in the range -1<x<0 and inconsistent in the range (0,1))
Insufficient.

St2:- x > –1
Question stem is inconsistent. (consistent in the range -1<x<0 or, x>1 and inconsistent in the range (0,1))
Insufficient.
Combined, we have -1<x<1.----------(2)
Question stem is inconsistent. (consistent in the range -1<x<0 or, x>1 and inconsistent in the range (0,1))
Insufficient.

Ans. (E)
Show more


\(\sqrt[3]{x}\) does NOT mean 1/x^3 instead that means x^(1/3)
User avatar
PKN
User avatar
Joined: 01 Oct 2017
Last visit: 11 Oct 2025
Posts: 814
Own Kudos:
1,587
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 814
Kudos: 1,587
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 13 Aug 2018, 07:21
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATinsight
PKN
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1

Question stem:- Is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

Let \(\sqrt[3]{x} > \sqrt[5]{x}\)
Or, \(\frac{1}{x^3}-\frac{1}{x^5}>0\)
Or, \(\frac{x^2-1}{x^5}>0\)
Or, \(\frac{\left(x+1\right)\left(x-1\right)}{x^5}>0\)
So, -1<x<0 or, x>1-----------(1)

St1:- x < 1
Question stem is inconsistent. (consistent in the range -1<x<0 and inconsistent in the range (0,1))
Insufficient.

St2:- x > –1
Question stem is inconsistent. (consistent in the range -1<x<0 or, x>1 and inconsistent in the range (0,1))
Insufficient.
Combined, we have -1<x<1.----------(2)
Question stem is inconsistent. (consistent in the range -1<x<0 or, x>1 and inconsistent in the range (0,1))
Insufficient.

Ans. (E)


\(\sqrt[3]{x}\) does NOT mean 1/x^3 instead that means x^(1/3)
Show more

I completely misread the question. Thanks for noticing GMATinsight.
User avatar
GyMrAT
User avatar
Joined: 14 Dec 2017
Last visit: 03 Nov 2020
Posts: 412
Own Kudos:
509
 [1]
Given Kudos: 173
Location: India
Posts: 412
Kudos: 509
 [1]
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 13 Aug 2018, 13:00
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1
Show more

Given: \(\sqrt[3]{x} > \sqrt[5]{x}\)

We can raise the inequality to an odd power, hence we have \(x^{5/3} > x\)

Statement 1: \(x < 1\)

For x = 1/8, we get \(x^{5/3} = (1/8)^{5/3}\) = \((1/2)^{5}\) \(< 1/8\)......Hence NO

For x = -1/8, we get \(x^{5/3} = (-1/8)^{5/3}\) = \((-1/2)^{5}\) \(> -1/8\)......Hence YES

Statement 1 is Not Sufficient.


Statement 2: \(x > –1\)

We can use same examples as above & can show Statement 2 is Not Sufficient.


Combining both statements we get \(-1 < x < 1\)

We can use same same examples as above & can show that combining is also Not Sufficient.


Answer E.


Thanks,
GyM
User avatar
Mo2men
User avatar
Joined: 26 Mar 2013
Last visit: 09 May 2023
Posts: 2,439
Own Kudos:
1,478
Given Kudos: 641
Concentration: Operations, Strategy
Schools: Erasmus (II)
Products:
My Reviews
Schools: Erasmus (II)
Posts: 2,439
Kudos: 1,478
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 02 Dec 2018, 11:11
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATinsight
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1

Question : is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

\(\sqrt[3]{x} > \sqrt[5]{x}\)? only if x is either greater than 1 or less than -1

Statement 1: x < 1

x may be 0.5 or -5 hence

NOT SUFFICIENT

Statement 2: x > -1

x may be -0.5 or 5 hence

NOT SUFFICIENT

Combining the two statements

-1 < x < 1

Hence answer to the question is always NO hence

SUFFICIENT

Answer: Option C
Show more

Dear GMATinsight

The highlighted is not the same.

Also, 0.5 & -0.5 satisfies both cases, giving different answer to the question.

0.5 gives no \(\sqrt[3]{0.5}\)=0.79 & \(\sqrt[5]{0.5}\)=0.83

-0.5 gives yes \(\sqrt[3]{-0.5}\)=-0.79 & \(\sqrt[5]{-0.5}\)=-0.83

Answer: E
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 Nov 2025
Posts: 6,839
Own Kudos:
16,354
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,839
Kudos: 16,354
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 03 Dec 2018, 00:15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Mo2men
GMATinsight
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1

Question : is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

\(\sqrt[3]{x} > \sqrt[5]{x}\)? only if x is either greater than 1 or less than -1

Statement 1: x < 1

x may be 0.5 or -5 hence

NOT SUFFICIENT

Statement 2: x > -1

x may be -0.5 or 5 hence

NOT SUFFICIENT

Combining the two statements

-1 < x < 1

Hence answer to the question is always NO hence

SUFFICIENT

Answer: Option C

Dear GMATinsight

The highlighted is not the same.

Also, 0.5 & -0.5 satisfies both cases, giving different answer to the question.

0.5 gives no \(\sqrt[3]{0.5}\)=0.79 & \(\sqrt[5]{0.5}\)=0.83

-0.5 gives yes \(\sqrt[3]{-0.5}\)=-0.79 & \(\sqrt[5]{-0.5}\)=-0.83

Answer: E
Show more

Thank you... made correction.. I don't know how I made this mistake while same values are taken in statement 2... :)
User avatar
SatvikVedala
User avatar
Joined: 03 Oct 2022
Last visit: 03 May 2025
Posts: 177
Own Kudos:
121
Given Kudos: 51
Posts: 177
Kudos: 121
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 31 Aug 2024, 09:19
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Given that x ≠ 0, is \(\sqrt[3]{x} > \sqrt[5]{x}\)?

(1) x < 1

(2) x > –1
Show more
­A number line analysis here

if x>1
1 ------ \(\sqrt[5]{x}\)­ ------ \(\sqrt[3]{x}\) ------ inf

0<x<1
0 ------ \(\sqrt[3]{x}\) ------ \(\sqrt[5]{x}\) ------ 1

-1<x<0
-1 ------ \(\sqrt[5]{x}\) ------ \(\sqrt[3]{x}\) ------ 0

x<-1
-inf ------ \(\sqrt[3]{x}\)­ ------ \(\sqrt[5]{x}\) ------ -1

Case 1 fails as we have 3 cases 0<x<1, -1<x<0 and x<-1
Case 2 fails as we have 3 cases again -1<x<0, 0<x<1, x>1
Combining case 1 + case 2 also fails since we have 0<x<1 & -1<x<0
User avatar
Shafkat26
User avatar
Joined: 18 May 2024
Last visit: 26 Jun 2025
Posts: 8
Own Kudos:
4
Given Kudos: 56
Location: Bangladesh
Posts: 8
Kudos: 4
Given that x ≠ 0, is x^(1/3) > x^(1/5)? 01 Sep 2024, 21:42
Kudos
Add Kudos
Bookmarks
Bookmark this Post
­A good thing to remember while answering these types of questions is that when it comes to root, the more the power increase, the closer it is to 1. For example, for x = 0.5, (x)^1/5 is closer to 1 than (x)^1/3. For X = -0.5, (X)^(1/5) is closer to -1 than (X)^1/3
Moderators:
Bunuel
Math Expert
105390 posts
kingbucky
496 posts