GMAT Club Around The World!!! If non-negative integers n and p are not

Question

If non-negative integers n and p are not both odd, which of the following must be odd?

A. np
B. np + 2
C. 2n + p
D. 2(n + p)
E. 2(n + p) + 1

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Deepakjhamb · Answer

If non-negative integers n and p are not both odd, which of the following must be odd?

A. np
B. np + 2
C. 2n + p
D. 2(n + p)
E. 2(n + p) + 1

now we can have o ,e , or e,e but not o ,o and we need to see MBT odd

so clear answer is e) 2(n+p) +1 which is e+ o = o

so answer is e )2(n+p)+1

ananya3 · Answer

IMO E

n,p > 0
n and p both not odd
case 1: n=odd, p=even
case 2: n=even, p=odd
case 3: n=even, p=even
 
A. np
for case 3, this will be even
n= even, p =even
even * even = even -  Incorrect

B. np + 2
for case 3 this will be even
n= even, p =even
even * even = even
even + even = even -  Incorrect

C. 2n + p
for cases 1 and 3 this will be even
2*number = even
even + even = even -  Incorrect

D. 2(n + p)
2*number = even -  Incorrect

E. 2(n + p) + 1
2*number = even
even + 1(odd) = odd
  Correct

rocky620 · Answer

Either one is even or both are even

A. np......can never be odd.  Eliminate. 
B. np + 2......can never be odd.  Eliminate. 
C. 2n + p........can be odd/even depending on the valur of  p .  Eliminate. 
D. 2(n + p)........can never be odd.  Eliminate. 
E. 2(n + p) + 1......even+odd = odd.  Correct

IMO Option E

TarunKumar1234 · Answer

Given, n and p are not both odd and non-negative integers.

A. np -> It is not odd always.
B. np + 2 -> It is not odd always. as if n or p=0.
C. 2n + p -> depends on P. So, not always odd.
D. 2(n + p) -> It is always even.
E. 2(n + p) + 1 -> It must be odd.

So, I think E.

Green2k1 · Answer

Correct Answer E

If non-negative integers n and p are not both odd, which of the following must be odd?

n and P are non-negative means either 0 or positive
n and p will have different nature if one is odd other will be even and vice versa

A. np
 = odd* Even = Even

B. np + 2
 odd* Even +2 = Even

C. 2n + p
 n= odd
even + even = even
n= even
even+ odd = odd

D. 2(n + p)
 even*even= even

E. 2(n + p) + 1
 even*even + odd= odd

manasi05 · Answer

n and p are non negative integers which mean n and p could be 0 and positive integers.
n and p ( not both are odd so one will be even and other will be odd)
np will be even as odd*even is always even
np + 2 will be even as even plus even (2 is even) is always even 
2n + p could be odd or even depending on the value of p
2(n+p) will be always even as any number multiplied by even number 2 will be even
2(n+p) + 1 will be always odd as its even + 1 which always results in odd number.

The correct answer is E

Fayzulla · Answer

N and P are positive numbers and they are both even numbers (non-negative = positive, not odd = even). Let's look into the answer variants.

A) Even * even = even 
B) Even * even + even = even 
C) 2* even + even = even 
D) 2 * (even + even) = even 
E) 2 * (even + even) +1 = odd

Correct answer is E.

GMAT Club Around The World!!! If non-negative integers n and p are not

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