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There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.­


each team in Group A played each of the other teams exactly n times => each team played n*(n-1) games
Total number of games = n*n*(n-1)/2 [Since each game will include 2 teams]

(1) The number of games played by each team in Group A is more than 10 but fewer than 25. => 10 < n*(n-1) < 25 => n = 4 or 5, INSUFF

(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.­
=> n*(n-1) = (n*n*(n-1))/4 => n = 4 [n can't 0 and 1 since there are "n teams" => plural => more than 1]
Hence SUFF

Answer = (B)
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Given: There are n teams in Group A, and each team in Group A played each of the other teams exactly n times.
Asked: What was the total number of games played by the teams in Group A?

The number of games played by each team in Group A = n(n-1)
Total games played by all the teams in Group A = n * n(n-1)/2

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
10 < n(n-1) < 25
10 < n^2 - n < 25
3 < n < 6
n = {4, 5}
Total games played by all the teams in group A = {24, 50}
NOT SUFFICIENT

(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.
n(n-1) = n*n(n-1)/4; n = 4
Total games played by all the teams in Group A = n^2(n-1)/2 = 24
SUFFICIENT

IMO B
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Total number of ways to choose 2 teams out of n \( = \frac{n (n-1)}{2}\)

When each of these pairs plays n times, total number of games, G \(= n * \frac{n (n-1)}{2}\)
\(G = \frac{n^2  (n-1)}{2}\)

Number of games played by each team (g)
each team plays (n-1) other teams n times, 
g = n (n-1)

Statement 1
The number of games played by each team in Group A is more than 10 but fewer than 25.

says that g is more than 10 but less than 25. 
By trial and error we see that this is possible for n=4 as well as n=5
when n=4, g = 12
when n=5, g = 20

hence not sufficient.

Statement 1
The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.

says that G/g = 2

i.e \(\frac{\frac{n^2  (n-1)}{2}}{n (n-1)} = 2\)

 ­n = 4

hence sufficient.

Correct answer B
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Bunuel
There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

 


This question was provided by GMAT Club
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­
­N teams in Group A, and each team in Group A player with each of other teams exactly n times
Total number of games played by team in Group A??

Option 1: The number of games played by each team in Group A is more than 10 but fewer than 25.
if we got n team and they play with one another once , total number of games become nC2
if each team plays with others once, number of games each team plays = (n-1)
so 10< n(n-1) < 25
so n could be 4 and 5
we do not get unique value

Option 2:The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.
lets say each team plays with one another once
so (n-1)=  nC2/2
(n-1) = n(n-1)/4
so n = 4

if they play twice 
2(n-1) = 2* nC2/2
2(n-1)= n(n-1)/2
n= 4

if they play thrice
3(n-1) = 3* nC2/2
(n-1) = n (n-1)/4
n= 4

ntimes * (n-1)  = ntime * nC2/2
n = 4

so we have 4 teams playing 4 times. and total number of games played = 4C2 * 4 = 24

B is the answer



 
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Bunuel
There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

­
­Each team plays \(n-1\) other teams and they play each other team n times. That means that each team plays \(n(n-1)\) games.

Statement 1

\(10 < n(n-1) < 25\)

Let's assume values of n, starting with 4:

\(10 < 4*3 < 25\) -> \(10 < 12 < 25\) -> valid

Now if n = 5:

\(10 < 5*4 < 25\) -> \(10 < 20 < 25\) -> valid

This means we can have multiple answers, so this is not sufficient.

-> Statement 1 alone is not sufficient.

Statement 2

\(n(n-1)\) games per team and n teams total so:

Total games = \(\frac{n*n(n-1)}{2}\) (note that we must divide by 2 because each game is counted twice otherwise)

We are told in the statement that \(n(n-1)\) is half the number of total games so:

\(n(n-1) = \frac{1}{2} * \frac{n*n(n-1)}{2}\)

\(4*n(n-1) = n*n(n-1)\)

\(4 = n\)

That means that n is 4 and if we plug it back into \(\frac{n*n(n-1)}{2}\), we get total games played = 24.

-> Statement 2 alone is sufficient.

The answer is B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.­
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There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

Let teams in Group A be denoted as
team a      [who played                  n    games with b,c....n]
team [b]b
     [who played remaining   n-1 games with c,d....n]
team [b]c
     [who played remaining   n-2 games with d,e,....n]
.
.
.
team [b]n-1
   [who played remaining  {n-(n-1)}=1 game with n]
team [b]n
       [who played remaining   {n-n)}=0 game]

Total games in Group A= (n) + (n-1) + (n-2) + .....3 + 2 + 1 

[b]Total games in Group A=n(n+1)/2............(i)


(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
10<n<25.
Insufficient to solve (i) to find Total games in Group A


(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.­

n=[n(n+1)/2]/2
n=n(n+1)/4
4n=n^2+n
n^2-3n=0
n(n-3)=0
n=3 or n=0 (Impossible as Number of matches cant be zero)

Sufficient to solve (i) to find Total games in Group A­
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Given that there are n teams in Group A and each team in Group A played each of the other teams exactly n times.

We need to find the total number of games played by all the teams in Group A.

Each team plays n games against each of the other n−1 teams. So, each team plays n × (n−1) games.

Since each game involves two teams, if each team plays n × (n−1) games, then the total number of games, considering both teams for each game, would be: [n^2×(n−1)]/ 2​

Let's analyse each statement now:

(1) 10<n×(n−1)<25

Let's find possible integer values of n that satisfy this inequality:

For n=1: 1×(1−1)=0
For n=2: 2×(2−1)=2
For n=3: 3×(3−1)=6
For n=4: 4×(4−1)=12 (satisfies 10<12<25)
For n=5: 5×(5−1)=20 (satisfies 10<20<25)
For n=6: 6×(6−1)=30 (does not satisfy 10<30<25)

From this, n could be 4 or 5. However, this range does not give us a unique value for n.

Therefore, Statement (1) alone is not sufficient.
 

(2) Total number of games for all teams: [n^2×(n−1)]/ 2​

According to Statement (2): n × (n−1) = 1/2 × [n^2×(n−1)]/2​

n × (n−1) = [n^2×(n−1)]/4​

n=4

Thus, Statement (2) gives us a unique value for n.

Therefore, Statement (2) alone is sufficient.

Hence, the answer is option (B)
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­There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.

Solution: Given that,
  • There are 'n' teams in Group A
  • Each team plays each of the other teams exactly 'n' times
The total number of games played by each team against every other team = n(n - 1)
Since each game involves two teams, the total number of games, say X played by all teams can be calculated as:
X = \(\frac{n}{2}\) * n(n -1)

X = \(\frac{n^2(n - 1)}{2}\)

We need to determine the value of X

Statement 1: The number of games played by each team in Group A is more than 10 but fewer than 25
This means, 10 < n(n -1) < 25
if n = 3
n(n - 1) = 6 which is not > 10

if n = 4
n(n - 1) = 12 which lies between 10 and 25

if n = 5
n(n - 1) = 20 which lies between 10 and 25
Thus we are not getting a unique value of 'n' and cannot calculate X.
INSUFFICIENT

Statement 2: The number of games played by each team in Group A is half the total number of games played by all the teams in Group A
This means, n(n -1) = \(\frac{1}{2}\) * \(\frac{n^2(n - 1)}{2}\)
On solving, we get n = 4
Thus, we can determine the value of X
SUFFICIENT

The correct answer is Option B


 ­
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­Okay, we're almost at the end.
I will miss this competition, for sure.
The orange team looks invincible but we will fight until the end.
Let's start with our explanation of this topic:

Glance - the Question:
Question: We are dealing with a combination and permutation problem.
We can solve this question by the formulate or by understanding.
I think it is better to understand it. 

Rephrase - Reading and Understanding the question:
Given:
Group A
It has n teams.
Each team play against each other n times. 
Let's understand it: We can take for example:
n=3, so 3 teams. played 3 games with each other. 
Team X play with Team Y  - 3 games
Team X play with Team Z  - 3 games
Team Y play with Team Z  - 3 games
So we have total of 9 games.
Each team played 6 games
With that in mind:

Plan
Let continue with the examples:
n=4, so 4 teams. plays 4 games with each other. 
Team X play with Team Y  - 4 games
Team X play with Team Z  - 4 games
Team X play with Team T  - 4 games
Team Y play with Team Z  - 4 games
Team Y play with Team T  - 4 games
Team Z play with Team T  - 4 games
so total of 4x6 = 24 times
Each team played 12 times 

n=5, Total of 50 times.
Each team played 20 times

Solve:
(1)  10 < the number played by each < 25
so n can be 4 or 5 
n=4 each team played 12 times   
n=5 each team played 20 times
There Insufficient - We have to possible answers. n=4 or n=5

(2) Half of the total games played by each team
We can infer that n=4. Why?
When n=4.  the total games is 24 and each team played 12 games.
When n=5.  the total games is 50 and each team played 20 games. it's not half of 50.
Also we tried n=3 and we can see the pattern here, it increases each time, after 4 we cross the half. 
Thus, Sufficient 

Our Answer is B


THE END
I hope you liked the explanation, I have tried my best here.
Let me know if you have any questions about this question or my explanation.
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­Games played by each team \(= N\), games played total \(= N^2\).

(1)
\(N>10\) and \(N<25\), which can be pretty much any integer there. Eliminate.

(2)
\(N = \frac{N^2 }{ 2}\)
So \(2N = N^2\) and \(N=2\)
Sufficient.

Therefore, the answer is B.­
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Bunuel
There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

(1) The number of games played by each team in Group A is more than 10 but fewer than 25.
(2) The number of games played by each team in Group A is half the total number of games played by all the teams in Group A.

 
Games played by each team = \(n*(n-1)\)
Total number of games played by the teams = \(\frac{n^2*(n-1)}{2}\)

­Statement 1:
two possible values ­
n = 4, 5 which lead to 12 and 20 games by each team

Statement 2:
\(\frac{n^2*(n-1)}{4} = n*(n-1)\) 
3 possible values of n = 0, 1, 4
n cannot be 0 as there will be no teams to play.
n cannot be 1 since there will be no teams to play 1 game against.

Only possible value n = 4
Sufficient.

B­
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­There are n teams in Group A, and each team in Group A played each of the other teams exactly n times. What was the total number of games played by the teams in Group A?

No of games played by each team once with other team \(=n-1\)

No of games played by each team n times with each other team \(=n*(n-1)\)

Total no of games played when played once with each other team \(=\frac{n*(n-1)}{2}\)

Total no of games played when played n times with each other team \(=\frac{n*(n-1)}{2}*n\)­

Statment 1: The number of games played by each team in Group A is more than 10 but fewer than 25.

\(10<n*(n-1)<25\)

when \(n=4\), \(n*(n-1)=12\)

when \(n=5\), \(n*(n-1)=20\)

when \(n=6\), \(n*(n-1)=30\)

\(n\) could be 4 or 5

NOT SUFFICIENT 


Statement 2: The number of games played by each team in Group A is half the total number of games played by all the teams in Group A

\(n*(n-1)=\frac{n*(n-1)}{2}*\frac{n}{2}\)

\(4*n*(n-1)=n^2*(n-1)\)

\(n=4\)

SUFFICIENT

Answer is B
­
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