Okay, we're almost at the end.
I will miss this competition, for sure.
The orange team looks invincible but we will fight until the end.
Let's start with our explanation of this topic:
Glance - the Question:Question: We are dealing with a combination and permutation problem.
We can solve this question by the formulate or by understanding.
I think it is better to understand it.
Rephrase - Reading and Understanding the question:Given:Group A
It has n teams.
Each team play against each other n times.
Let's understand it: We can take for example:
n=3, so 3 teams. played 3 games with each other.
Team X play with Team Y - 3 games
Team X play with Team Z - 3 games
Team Y play with Team Z - 3 games
So we have total of 9 games.
Each team played 6 games
With that in mind:
PlanLet continue with the examples:
n=4, so 4 teams. plays 4 games with each other.
Team X play with Team Y - 4 games
Team X play with Team Z - 4 games
Team X play with Team T - 4 games
Team Y play with Team Z - 4 games
Team Y play with Team T - 4 games
Team Z play with Team T - 4 games
so total of 4x6 = 24 times
Each team played 12 times
n=5, Total of 50 times.
Each team played 20 times
Solve:(1) 10 < the number played by each < 25
so n can be 4 or 5
n=4 each team played 12 times
n=5 each team played 20 times
There
Insufficient - We have to possible answers. n=4 or n=5
(2) Half of the total games played by each team
We can infer that n=4. Why?
When n=4. the total games is 24 and each team played 12 games.
When n=5. the total games is 50 and each team played 20 games. it's not half of 50.
Also we tried n=3 and we can see the pattern here, it increases each time, after 4 we cross the half.
Thus,
Sufficient Our Answer is BTHE ENDI hope you liked the explanation, I have tried my best here.
Let me know if you have any questions about this question or my explanation.