Information given:- 40 items are arranged in a rack: 5 rows x 8 columns
- Average price of items in each row: Xm (for m = 1 to 5)
- Average price of items in each column: Yn (for n = 1 to 8)
Question:- What is the average price of all 40 items on the rack?
Solution:- Total price: sum of prices of all items
- Average price: total price / 40
- Therefore, to calculate the average price, we need to know the total price
- Statement 1: X1 + X2 + X3 + X4 + X5 = 850
- Each Xm is a row average for 8 items
- Total price for each row: Row m = 8 * Xm
- Total = 8 * (X1 + X2 + X3 + X4 + X5) = 8 * 850 = 6800
- Average = 6800/40 = 170
- Therefore, statement 1 alone is sufficient
- Statement 2: Y1 + Y2 + Y3 + Y4 + Y5 = 1360
- Each Yn is a column average for 5 items
- Total price for each column: column n = 5 * Yn
- Total = 5 * (Y1 + Y2 + Y3 + Y4 + Y5) = 5 * 1360 = 6800
- Average = 6800/40 = 170
- Therefore, statement 2 alone is sufficient
Answer: D, each statement alone is sufficientBunuel
In a store, 40 items are arranged on a rack in 5 rows and 8 columns. The average (arithmetic mean) of the price of items in each row (m) is \(X_m\) [1 ≤ m ≤5]. The average of the price of items in each column (n) is \(Y_n\) [1 ≤ n ≤ 8]. What is the average price of all items on the rack?
(1) \(X_1 + X_2 + ... + X_5 = $850\)
(2) \(Y_1 + Y_2 + ... + Y_8 = $1,360\)