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Option C will be the answer.

As we know from the overlapping set formula

Total (a) = CyberSecurity (b) + Cloud Computing (c) - Both (b&c) + Neither (d)

So to be the number of participants who attended both the seminar we will do:

Both(b&c) = b + c + d - a, and from here we will be the number of participants who attended both the seminar.

Now we have to solve for the final part of the question which is, what fraction of participants joined both the seminar.

Fraction Value = Number of Participants who attended both seminar / Total number of Participants, which will be

(b+c+d-a)/a.

Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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To calculate the number of people who attended both sessions:
b = [number of people who attended "only" the cybersecurity session] + [ number of people who attended "both" sessions]
c = [number of people who attended "only" the cloud computing session] + [ number of people who attended "both" sessions]
d = [number of people who attended "neither" sessions]
Also, we know that :
a = [number of people who attended "only" the cybersecurity session] + [number of people who attended "only" the cloud computing session]
+ [number of people who attended "both" sessions] + [number of people who attended "neither" sessions]

So the difference between [b+c+d] and a is the number of people who attended "both" sessions
So the ratio of the number of people who attended "both" sessions to all participants is:

\(\frac{b + c + d - a}{a}\)

So the right answer is C.
Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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If 'b' denotes all the people who attented the session on cybersecurity,
And 'c' denotes all the people who attented the session on cloud computing,
and 'd' denotes all the people who attented neither,
Then total people would be given as b+c+d+(\(b \bigcap c\))=a
(\(b \bigcap c\)) = b+c+d-a.
And fraction would be given by \(\frac{b+c+d-a}{a}\)
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Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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The total participants who attended at least one session: a - d
The total participants who attended cybersecurity and cloud computing and both sessions is: b + c.
=> Participants who attended both is: b + c - (a - d) = b + c - a + d.

The answer: (C) \(\frac{b + c + d - a}{a}\)
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If we take people who attended both sessions as X,

we get : b + c - X = people who attended one session.

As d attended neither, total people who attended one session (at least) = a - d

Hence, b + c - X = a - d ; X = b + c - a + d

As a fraction, it equates to: X / a = b + c - a + d / a = option C
[hr]

Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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Let total no of student attend both session is k

for cyber sec = b

for cloud comp = c

none = d


only CS = b-k
only CC = c-k

Total = only CS + only CC + Both + None

a = b-k+c-k+k+d

k = b+c+d - a

Fraction of one who attended both = (b+c+d-a)/a
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We have to find fraction of participants who attend both.

Information given in the question:

Total Participants= a
Total Participants who attended Cyber-Crime Session= b (Incl who attended only cyb sec as well as who attended both session)
Total Participants who attended Cloud Computing= c (Incl who attended only cloud comp as well as who attended both session)
Total Participants who attended none of these sessions= d

With this we know this is an overlapping set question.

So we start by creating a table and have the given values

Cyber SecurityNot Cyber SecurityTotal
Cloud Computing?(a-b)-dc
Not Cloud Computing(a-c)-dd(a-c)
Totalb(a-b)a


So we can fill the question mark as

As per Row: ?= c-((a-b)-d) = c+b+d-a
As per Column: ?= b- ((a-c)-d) = b+c+d-a

We know total members who attended the tech seminar is a

Therefore, fraction who attended both to who attend seminar is

\(\frac{b + c + d - a}{a}\)

So, answer is C.
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Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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Let's consider that X is the number of student who attended both. So,

Total number of Students = b+c-x+d = a

so, x = b + c + d - a

now just see which answer gives fraction which is , x divided by a. Which is option (c)
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It's possible to solve using a table, but I think it's faster in this case to apply the rule TOTAL = A + B - BOTH + NEITHER and then rearrange BOTH = A + B + NEITHER - TOTAL.
Assign a variable like x to "BOTH".
a=b+c-x+d --> x=b+c+d-a
To find the fraction of participants who attended both sessions, simply divide by the total:(b+c+d-a)/a and the answer is C
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Well I personally didn't liked this question. There might be a possibility of there were other sessions apart from cybersecurity and cloud computing. But it's something you cannot say in actual exam.

Now, I am assuming there were only two sessions available, cyber security and cloud computing.
Total participants = a
Cyber security participants = b
Cloud computing participants = c
Participants attending neither sessions = d
lets assume people attending both the sessions be => e

so set equation can be given as:
b + c + d - e = a
e = b + c + d - a

fractions of people attending both the sessions can be given as e/a
or: \( \frac{( b + c + d - a )}{a} \)

so answer is C
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Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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Option C - as ppl attending either is a-d
hence its {(b+c+d)-a}/a
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Not sure if I feel too confident about this one, but the way I thought about it was:

The people who did not attend a sessions are taking out of the total, so A-E, then I figured that the people who attended both would be B+C

From there I set them equal and divided by the people who did not attend a session
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1st Read through: Before writing, recognize this is an overlapping set question with two variables.

Strategy:
Set up a 4-column, 4-row grid. For variables with the same letter, use the second letter.
Cybersecurity = "Y"; Cloud Computing = "L";
Grid notation: not = "n"; intersection of a column & row = "_"; blank cell = "-"
Rephrase the question: What is (Y_L)/a?
  • Skim answers and eliminate Answer E
1. Fill in grid headers
  • 1st row: -, Y, nY, Sum
  • 1st column: -, L, nL, Sum
2. Fill in grid with known values (2nd read through)
  • Sum_Sum = a, Sum_L = c, Sum_Y = b, nY_nL = d
3. Use algebra to determine unknown values
  • Sum_nY = (a) - (b)
  • Sum_nL = (a) - (c)
  • nY_L = (Sum_nY) - (nY_nL) = (a-b) - (d)
  • nL_Y = (a-c) - (d)
  • Y_L = (Sum_Y) - (Y_nL) = (b) - (a-c-d)
=b - a + c + d
4. (Y_L)/a = (b-a+c+d)/(a)
  • Rearrange to match answer choice

Answer: C
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Participants attended both the sessions \(=x\)

Total \(=X+Y-Both+Neither\)

\(a=b+c-x+d\)

\(x=b+c+d-a\)

fraction of the participants attended both sessions \(=\frac{x}{a}=\frac{b+c+d-a}{a}\)

Answer: C
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Bunuel
At a tech seminar with a total participants, b attended a session on cybersecurity, and c attended a session on cloud computing. If exactly d participants attended neither session, then in terms of a, b, c, and d, what fraction of the participants attended both sessions?

A. \(\frac{a - b - c + d}{a}\)

B. \(\frac{a - b - c - d}{a}\)

C. \(\frac{b + c + d - a}{a}\)

D. \(\frac{a - b - c + 2d}{a}\)

E. \(\frac{b + c - a + d}{a-d}\)


 


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So I first setup the equation a = b+c+d-duplicates. so to find duplicates fraction we move over and divide by a so (a-b-c-d)/a, but a-b-c-d= -duplicates, I made this mistake at first, but while writing this caught it. You need to flip signs (d+c+b-a)/a is what we want
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a = total participants
x = participants who attended both sessions

a = b+c-x+d -> x = b+c+d-a
fraction = x/a = (b+c+d-a)/a

IMO C
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Total people = a
Cybersecurity = b
Cloud = c
Neither = d

So the number who attended at least one session = a - d

But if we add b + c, that double counts those who went to both.

So,
-> b + c - (both) = a - d
-> both = b + c - (a - d) = b + c + d - a

Fraction of the participants attended both sessions : (b + c + d - a) / a

Answer is C.
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