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For ease of calculation, let’s assume some variable for the total number of invited guests.
we've 4/7 and 1/5 as fractions in the question, consider using a multiple of 35 (LCM of 7 and 5)

Total invited guests (T) = 70
donors = 4/7 of T = 40
press = 1/5 of T = 14
Remaining = 70-40-14 = 16
Divide them into below 4 groups:
volunteers entertainers, organizers and sponsors will each have 4 guests

Now, actual attendees:
donors = 40
press = 2*14 = 28
entertainers = 0
volunteers = 4/2 = 2
organizers = 4
sponsors = 4

Question: donors/actual attendees?
40/78 = 20/39
Option B

Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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Let total invited guests = 35 (LCM of 7 and 5 for easy calculation)
As per question :
Donors = 4/7 of 35 = 20 guests
Press = 1/5 of 35 = 7 guests
Volunteers + Entertainers + Organizers + Sponsors = 35 - 20 - 7 = 8 guests (these 8 guests are equally divided between Volunteers, Entertainers, Organizers and Sponsors as per question)
So,
Volunteers = 2 guests
Entertainers = 2 guests
Organizers = 2 guests
Sponsors = 2 guests

On the day of event following guests showed up :

Donors = 20 guests
Press = 2 x 7 = 14 guests
Volunteers = 2 x 1/2 = 1 guest
Entertainers = 0 guests
Organizers = 2 guests
Sponsors = 2 guests

Total : 39 guests showed up

Now, fraction of the actual attendees those were donors = 20/ 39

Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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Ans (B)

It is given that donors invited are 4/7 and Press invited is 1/5

taking their LCM we have donor = 20/35 and press = 7/35

Further, we have invited volunteer entertainers, organizers, and sponsors are 1/4 of the remaining, which is 2/35 (for all remaining four)

Now, actually 14/35 came from press and (2/35x2=1/35) volunteers showed up.

Thus, the total number of people actually there are 20/35+14/35+1/35+2/35+2/35=39/35

as per question No. of donors/ total

4/7x35/39= 20/39
Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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To solve these kinda questions where fractions are involved my go-to approach is to assume a number that is a multiple of both. Here, we are given 4/7 were donors, 1/5 were press so instead of assuming like x guests, or 100x guests (which we normally do) I assume 70x as my total number of guests. Now we are given that
4/7 were donors, that is equals to (4/7)* 70x = 40x guests
1/5 were press, that is equals to (1/5)*70x = 14x guests
and says the rest were divided equally so the remaining are 70x-40x-14x=16x guests; dividing into 4 equal portion we get 4x of guests in each category.
These were the invited guests.

Now, moving to the number of guests arrived.
We are given,
  • Twice of press guests arrived as were invited, i.e 28x press arrived.
  • only half of the invited volunteers attended, i.e 4x/2=2x volunteers arrived.
  • No entertainer hence 0
And the rest were same so
  • Donors =40x arrived
  • Organizers =4x arrived
  • Sponsors= 4x arrived.
We are ask to find the actual attendees were donors, so
firstly summing up all the attendees we get 28x +2x + 0 + 40x + 4x + 4x =78x
Donors were 40x
So 40x/78x = 20/39 . Hence, B is the correct answer
Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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Invited guests: 4/7 + 1/5 + others = 1
others = 1 - 27/35 = 8/35
V+E+O+S = 8/35
V=E=O=S = 2/35

Actual attendees: 4/7 + 2/5 + 1/35 + 0 + 2/35 + 2/35 = 39/35

fraction = D/Att = (4/7) / (39/35) = 20/35 * 35/39 = 20/39

Correct answer is B
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As I can see 4, 5 and 7 commonly in question I will assume something which divisible by three of them.

So lets total member be 140

Then,

Group-----------Day 1-----Day 2
Donors 80 80
Press 28 2*28= 56
Volunteers 8 Half of 8 = 4
Entertainer 8 0 (Boycott)
organizers 8 8
sponsors 8 8
Total of day 2 - 156

Hence fraction of donors to attendees is 80/156 = 20/39; Option B
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Imagine total guests invited where 35

1. - 20 donors
2 - 7 press
Rest of them = 8 (two each)

On the day

20 donors
14 press
8-3 rest of them

Fraction of donors = 20/39






Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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Let total number of invited guests = x.
Donors = 4x/7 = 20x/35
Press = x/5 = 7x/35
volunteers, entertainers, organisers, sponsors = 2x/35

Attendants:
press = 14(x/35)
volunteers = 1(x/35)
donors = 20(x/35)
organisers, sponsors = 4(x/35)

Fraction of donors: 20/14+1+20+4
=20/39

Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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Six groups: donors, press, volunteers, entertainers, organizers, or sponsors.
Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups
On the day of the event we see that, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and no entertainers. The donors, organizers, and sponsors showed up as expected

Since we know the initially 4/7 were donors, 1/5 were press
Lets say, Total invited guests = 35 (LCM of 7 and 5)

=> For Initial guest list,
Donors = 35* (4/7) = 20
Press = 35* (1/5) = 7
Remaining divided among four groups = (35 - 20 - 7)/4 = 2 each for volunteers, entertainers, organizers, or sponsors

Now,
For actual attendance
Donors = 20
Press = 2* 7 = 14
Volunteers = 2*(1/2) = 1
Entertainers = 0
Organizers = 2
Sponsors = 2
=> Total attendees = 20+14+1++0+2+2 = 39

Fraction of attendees that were donors = 20/39

B. 20/39
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least common multiple of 7 and 5 = 35
Of the 35 invited guests:
35*4/7 = 20 are donors
35*1/5 = 7 are press

The remainder (8=35-27) were divided equally among the other four groups:
volunteers = 2
entertainers = 2
organizers = 2
sponsors = 2

Attendees:
20+14+1+0+2+2=39

fraction = donors/actual attendees = 20/39

Answer B
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At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?



Let's name each group using abbreviations as D,P,V,E,O and S.
Given info:
D -> 4/7
P -> 1/5
Remaining = 1-(4/7 + 1/5) = 1 - 27/35 = 8/35
Dividing this among remaining 4 groups gives 8/35 * 1/4 = 2/35. So,
V,E,O,S -> 2/35

On actual day:
P => Twice of planned came -> 2/5
V => half of planned came -> 1/35
E -> 0
D -> 4/7
O,S, -> 2/35

Now we need to find D as a fraction of total that actually came.
(4/7) / (2/5 + 1/35 + 2/5 + 0 + 4/7 + 2/35 + 2/35) = (4/7) *(35/39) = 20/39

Answer is B
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let, total invited guests = lcm of 7,5= 35
so donor = 35* 4/7= 20
press = 35*1/5=7
remaining guest = 35-(20+7)=8 which equally divided into remaining four guest types
means, V=E=O=S= 2
no. of attendies - d= 20, p=7*2, V=half of invited= 1,E=didn't come=0, O=2, S=2
so total attendees= 20+14+1+2+2=30

so fraction of donor to total attendees= 20/39

Bunuel
At a charity gala, each invited guest belonged to exactly one of six groups: donors, press, volunteers, entertainers, organizers, or sponsors. Among the invited guests, 4/7 were donors, 1/5 were press, and the remainder were divided equally among the other four groups. On the day of the event, however, twice as many press guests arrived as were invited, only half of the invited volunteers attended, and the entertainers did not attend due to a last-minute boycott. The donors, organizers, and sponsors showed up as expected. What fraction of the actual attendees were donors?

A. 4/7
B. 20/39
C. 4/9
D. 2/5
E. 10/39


 


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1. Determine the initial proportions of invited guests:

Donors: 4/7

Press: 1/5

Let's find a common denominator for 7 and 5, which is 35.

Donors: 4/7 = 20/35

Press: 1/5 = 7/35

Remainder: 1 (total) - 20/35 - 7/35 = 35/35 - 20/35 - 7/35 = 8/35

The remainder (8/35) is divided equally among the other four groups: volunteers, entertainers, organizers, and sponsors.

Each of these four groups represents: (8/35) / 4 = 2/35 of the invited guests.

So, the invited proportions are:

Donors: 20/35

Press: 7/35

Volunteers: 2/35

Entertainers: 2/35

Organizers: 2/35

Sponsors: 2/35

2. Calculate the proportions of actual attendees based on invited guests:

Let 'X' be the total number of invited guests. We can work with these fractions directly.

Donors: Showed up as expected. So, (20/35) of X attendees.

Press: Twice as many arrived as invited. So, 2 * (7/35) = 14/35 of X attendees.

Volunteers: Only half of invited attended. So, (1/2) * (2/35) = 1/35 of X attendees.

Entertainers: Did not attend. So, 0 attendees.

Organizers: Showed up as expected. So, (2/35) of X attendees.

Sponsors: Showed up as expected. So, (2/35) of X attendees.

3. Calculate the total fraction of actual attendees:

Add up the fractions for each group's actual attendance:
Total Actual Attendees = (20/35) + (14/35) + (1/35) + 0 + (2/35) + (2/35)
Total Actual Attendees = (20 + 14 + 1 + 2 + 2) / 35 = 39/35

This means that for every 35 invited guests, 39 actually attended (due to the increased press attendance). This is fine.

4. Determine the fraction of actual attendees who were donors:

Fraction of actual attendees who were donors = (Actual Donors) / (Total Actual Attendees)
Fraction = (20/35) / (39/35)

When dividing fractions, you can multiply by the reciprocal:
Fraction = (20/35) * (35/39)
Fraction = 20/39

The final answer is 20/39.
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Earlier
If total invitees are 350, then:
D=200, P=70, V=20, E=20, O=20, S=20

Now,
D=200, P=140, V=10, E=0, 0=20, S=20
Total = 390

Therefore, answer is 200/390 = 20/39
Option B
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