Last visit was: 08 Aug 2026, 15:47

It is currently 08 Aug 2026, 15:47

Toolkit

Practice Tests

Data Insights Questions

Data Sufficiency (DS)

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more

Request Expert Reply

Confirm Cancel

Aug 03
Save Big on GMAT™ Prep
12:00 PM EDT
-
11:59 PM EDT
Starting 8/3, save up to $1,000 on select GMAT prep. Achieve your b-school goals this fall with Manhattan Prep.
Aug 05
Magoosh's Biggest Sale of the Year!
12:00 PM EDT
-
11:59 PM EDT
50% off all study plans with code ADVANCE - Expires Monday 8/10
Aug 07
$320 Off on GMAT Focus - Limited Period Offer
10:00 AM IST
-
11:00 PM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 745+ score.
Aug 08
Stuck at 645 for 3 GMAT Attempts... Here's How I Finally Scored 695 in 4 Weeks!
10:00 AM PDT
-
11:00 AM PDT
Many GMAT aspirants don't struggle because they lack ability—they struggle because they're trying to fix the wrong problems. Tejas experienced this firsthand. Despite taking the GMAT three times, he remained stuck at 645.
Aug 10
Live Teach with Top GMAT Expert Ben Resnick
08:00 PM EDT
-
10:00 PM EDT
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Mon/Wed August 10, 2026 - Oct. 14, 2026, 8:00pm-10:00pm EST
Aug 14
Serious score increases start here: OnDemand GMAT classes taught by Founder and Top GMAT Expert Scott Woodbury-Stewart
10:00 AM EDT
-
11:00 AM EDT
Top Scores Start with a Elite Online Prep Course. Enroll for 6 months of access to over 400 hours of GMAT video lessons AND 715+ Score Guarantee!
Aug 15
All GMAT Club Tests are free and open for India's Independence Day, on Saturday August 15th!
12:01 AM PDT
-
11:59 PM PDT
On the 15th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PST

Back to Forum

Create Topic

GMAT Club World Cup 2026 (Day 9): A courier traveled from Hillford to

1 2 3 4

heyaa

Joined: 19 Dec 2024

Last visit: 08 Aug 2026

Posts: 66

Own Kudos:

[1]

Given Kudos: 46

Location: India

Posts: 66

Kudos: 55

[1]

16 Jul 2026, 10:14

Kudos

Bookmarks

t = t1, t2, t3
d = 40t1, 60t2, 80t3
total d/total t??
S1: t1:t2:t3 = 3:2:1; 3x, 2x, x
do total d can be written as k.x, t will be 6x, x will cancel, solvable ACD remains
S2: d1:d2:d3 = 3:3:2, so we get t1:t2:t3, as we solved above, solvable. Answer (D)

okHedwig

Joined: 13 Apr 2022

Last visit: 08 Aug 2026

Posts: 105

Own Kudos:

[1]

Given Kudos: 70

Posts: 105

Kudos: 63

[1]

16 Jul 2026, 10:28

Kudos

Bookmarks

Since for 3 consecutive legs, avg speed is given : 40kmph, 60kmph, 80kmph
Avg speed for entire trip = Total dist/Total time
St1 : Let the time resp be 3x, 2x, x
Then Avg speed = (40.3x+ 60.2x+ 80. x)/ 6x = Sufficient
St2 : Let resp lengths = 3x, 3x, 2x
Then Avg speed = {8x/ (3x/40)+(3x/60) + (2x/80)} = Sufficient

Hence Each statement suficient alone .D is the ans

Bunuel

A courier traveled from Hillford to Lakeshore in three consecutive legs, with no stops between the legs. On the first leg, the courier’s average (arithmetic mean) speed was 40 kilometers per hour; on the second leg, the courier’s average (arithmetic mean) speed was 60 kilometers per hour; and on the third leg, the courier’s average (arithmetic mean) speed was 80 kilometers per hour. What was the courier’s average speed for the entire trip?

(1) The ratio of the times the courier spent on the first, second, and third legs, respectively, was 3:2:1.

(2) The ratio of the lengths of the first, second, and third legs, respectively, was 3:3:2.

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

Nkathiyawadi

Joined: 08 Feb 2026

Last visit: 08 Aug 2026

Posts: 57

Own Kudos:

[1]

Given Kudos: 35

Location: India

Posts: 57

Kudos: 27

[1]

16 Jul 2026, 10:33

Kudos

Bookmarks

Average speed = (40t1 + 60t2 + 80t3)/(t1+t2+t3)

Statement 1 : Ratio of times spent on the first, second, and third legs, respectively, was 3:2:1 = 3x:2x: x
hence avg speed = ( 40*3x + 60*2x+80*x)/(3x + 2x + x) = (120 +120+80)/(3+2+1)
Hence, statement 1 is sufficient

Statement 2 : Ratio of the lengths of the first, second and third legs, respectively, was 3:3:2

i.e. 40t1:60t2:80t3 = 3:2:2 = 3x : 2x : 2x
i.e. t1 = 3x/40
t2 = 2x/60
t3 = 2x/80

avg speed = (3x + 2x + 2x)/(3x/40 + 2x/60 + 2x/80) = (3+2+2)/(3/40 + 2/60 +2/80)
Hence, Statement 2 is sufficient

Hence, each statement alone is sufficient. Answer = D

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

Vivek1707

Joined: 22 May 2020

Last visit: 08 Aug 2026

Posts: 313

Own Kudos:

132

[1]

Given Kudos: 150

Products:

Posts: 313

Kudos: 132

[1]

16 Jul 2026, 10:36

Kudos

Bookmarks

Avg speed is total distance/total time

Statement 1: Let the times be 3x, 2x and x

Hence avg speed is (40 *3x + 60 * 2x + 80*x)/(3x + 2x + x). All the x's will get cancelled. Sufficient

Statement 2:

Let distances equal 3x + 3x + 2x

Time would be 3x/40, 3x/60 and 2x/80

Again the x's will get cancelled Hence sufficient

I ll go with D

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

paragw

Joined: 17 May 2024

Last visit: 08 Aug 2026

Posts: 314

Own Kudos:

318

[1]

Given Kudos: 56

Products:

Posts: 314

Kudos: 318

[1]

16 Jul 2026, 10:59

Kudos

Bookmarks

Here's my solution for this question

Attachments

Screenshot_2026-07-16-23-28-34-40_40deb401b9ffe8e1df2f1cc5ba480b12.jpg [ 1.27 MiB | Viewed 104 times ]

yashsharma1

Joined: 18 Apr 2025

Last visit: 08 Aug 2026

Posts: 74

Own Kudos:

[1]

Given Kudos: 19

Location: India

Schools: IESE '26 (WL)

GMAT Focus 1: 645 Q81 V82 DI83 Verified score

Products:

Schools: IESE '26 (WL)

GMAT Focus 1: 645 Q81 V82 DI83 Verified score

Posts: 74

Kudos: 49

[1]

16 Jul 2026, 11:10

Kudos

Bookmarks

St1: Since the ratio of time taken is 3:2:1, we can assume the time to be 3x:2x:1x (total 6x) respectively (as shown in the attached photo). The distance will then be 120x, 120x and 80x (total 320x). Average speed = 320x / 6x = 53.33 kmph. SUFFICIENT

St2: Here, the ratio of distance travelled is given as 3:3:2. We can assume the distance to be 120x:120x:80x. This will give us speeds same as St 1 and final answer will be 53.33 kmph. SUFFICIENT

Final answer D

Attachments

Photo.png [ 18.74 KiB | Viewed 98 times ]

GulfTube

Joined: 13 Apr 2026

Last visit: 08 Aug 2026

Posts: 195

Own Kudos:

[1]

Given Kudos: 66

Posts: 195

Kudos: 68

[1]

16 Jul 2026, 11:15

Kudos

Bookmarks

i) treat as weighted average. when finding average of rate such as speed, the denominator of the rate is the weightage. which means the denominator of speed i.e. time is the weightage. and the given speeds of each leg is the statistic. we can easily find the average speed for entire trip.
40(3)+60(2)+80(1)/(3+2+1) = 320/6 = 160/3 = 53.3 km/h sufficient.

ii) ratio of distances = 3:3:2 = 8
average speed = total distance/total time
Let total distance = d
if we can get total time in terms of d, we can find the average speed.
leg 1 time = (3d/8)(1/40) = 3d/320
leg 2 time= (3d/8)(1/60) = d/160
leg 3 time= (d/4)(1/80) = d/320
total time = 6d/320 = 3d/160

average speed = d/(3d/160) = 160/3 = 53.3 km/h sufficient.
D

BongBideshini

Joined: 25 May 2021

Last visit: 08 Aug 2026

Posts: 378

Own Kudos:

232

[1]

Given Kudos: 133

Location: India

Concentration: Entrepreneurship, Marketing

Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27

GPA: 3.8

WE:Engineering (Government)

Products:

Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27

Posts: 378

Kudos: 232

[1]

16 Jul 2026, 11:22

Kudos

Bookmarks

	speed	time	Distance
L1	40
L2	60
L3	80

Statement-1

	S	T	D
L1	40	3t	120t
L2	60	2t	120t
L3	80	t	80t

Avg speed = 320t/6t = 320/6
sufficient
Statement II
Ratio of Distance = 3:3:2 , So taking the same values as the previous statement, d1=120t, d2=120t, d3=80t
Avg speed = 320t/6t = 320/6
sufficient
Ans D

sonit1987

Joined: 29 Jul 2025

Last visit: 07 Aug 2026

Posts: 61

Own Kudos:

[1]

Location: India

Concentration: Operations, Sustainability

WE:Operations (Energy)

Posts: 61

Kudos: 51

[1]

16 Jul 2026, 11:28

Kudos

Bookmarks

given: courier travelled in 3 legs without stop
1st leg- avg speed 40km/h
2nd leg- avg speed 60 km/h
3rd leg- avg speed 80 km/h

We have to find if we can find courier's average speed for entire trip?

Lets check both statement one by one.

Statement-1: Ratio of times courier spent on 1st, 2nd and 3rd leg are 3:2:1

Say total time is t

then, 1st leg time is 3/6(t) ; distance travelled for 1st leg=3/6(t)* 40= 20t
2nd leg time is 2/6(t) ; distance travelled for 2nd leg= 2/6(t)*60= 20t
3rd leg time is 1/6(t) ; distance travelled for 3rd leg= 1/6(t)*80= 40/3(t)

total distance travelled = 20t+20t+ 40/3(t)= 160/3(t)

Average speed foe entire trip = total distance travelled/ total time taken = 160/3(t)/t= 160/3 km/h

Statement found sufficient

Statement-2: Ratio of lengths of first, 2nd and 3rd leg are 3:3:2

lets assume total distance as d.

distance for 1st leg= 3/8(d) ; time for 1st leg = (3/8)*(d)/40 = (3/320)*(d)
distance for 2nd leg= 3/8(d) ; time for 2nd leg= (3/8)* (d)/60 = (1/160)*(d)
distance for 3rd leg= 2/8(d) ; time for 3rd leg= (2/8)*(d)/80 = (1/320)*(d)

total time taken = (3/320)*(d)+ (1/160)*(d)+ (1/320)*(d)= (6/320)*(d)

average speed for entire journey= total distance travelled/total time taken= d/(6/320)*(d)= 320/6= 160/3 km/h

Statement-2 is also sufficient

so each statement alone seems sufficient.

My answer choice is -D

AviNFC

Joined: 31 May 2023

Last visit: 07 Aug 2026

Posts: 365

Own Kudos:

421

[1]

Given Kudos: 5

Posts: 365

Kudos: 421

[1]

16 Jul 2026, 11:31

Kudos

Bookmarks

1. t1:t2:t3=3:2:1
t1=3x, t2=2x, t3=x
d1=40*3x, d2=60*2x, d3=80*x
D=d1+d2+d3=320x
T=t1+t2+t3=6x

D/T=320/6....SUFFICIENT

2. d1:d2:d3=3:3:2
d1=3x, d2=3x, d3=2x
t1=3x/40, t2=3x/60, t3=2x/80
T=t1+t2+t3= 3x/40 + 3x/60 + 2x/80
D=d1+d2+d3=8x

both D & T in terms of x..so, D/T is unique value.. SUFFICIENT

Ans D

RudrAkshat7

Joined: 10 Jul 2020

Last visit: 07 Aug 2026

Posts: 24

Own Kudos:

[1]

Given Kudos: 39

Location: India

Concentration: General Management, Entrepreneurship

Schools: ISB '27 Sloan '27 Haas '27 INSEAD Aug '27 IIM

Products:

Schools: ISB '27 Sloan '27 Haas '27 INSEAD Aug '27 IIM

Posts: 24

Kudos: 11

[1]

16 Jul 2026, 12:00

Kudos

Bookmarks

Let the total length is L and total time is T. Then average speed = L/T
Now, let leg 1,2 & 3 distance and times be L1, L2, L3 and T1, T2 and T3 respectively.
So, Av Speed Leg 1 = L1/T1 = 40, or L1 = 40T1, or T1 = L1/40. Similarly for leg 2 and 3, L2=60T2, T2=L2/60 & L3=80T3, T3=L3/80. --- eq 1

Since, average speed = (L1+L2+L3)/ (T1+T2+T3) --- eq -2
now consider the statements
A) T1:T2:T3 = 3:2:1
so, T1 = 3x, T2= 2x and T3=x
putting the values in our eq 1 and 2, we get av speed = (40T1+60T2+80T3)/(T1+T2+T3)
we can solve it to get a definitive answer. So A is sufficient.

B) L1:L2:L3 = 3:3:2
so, L1 = 3y, L2 = 3y, L3 = 2y
again, putting the values in eq 1 & 2, we can get a final answer wihtout any variable. Hence this is also sufficient.

Since both A & B are sufficient, hence answer is D.

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

remdelectus

Joined: 01 Sep 2025

Last visit: 08 Aug 2026

Posts: 120

Own Kudos:

112

[1]

Given Kudos: 6

Products:

Posts: 120

Kudos: 112

[1]

16 Jul 2026, 12:14

Kudos

Bookmarks

Average speed=total distance/total time
three legs speed= 40km/h, 60km/h, 80km/h
Statement 1
time ratio=3:2:1
time= 3t, 2t, t
distance
1st leg, 40(3t) =120t
2nd leg, 60(2t) =120t
3rd leg 80(t)=80t
ttl d=120t+120t+80t=320t
ttl t=3t+2t+t=6t
320t/6t=160/3=53.3333 km/h sufficient

Statement 2
distance ratio 3:3:2
d=3d, 3d, 2d
time 3d/40, 3d/60, 2d/80
ttl time: 3d/40+3d/60+2d/80=(9d+6d+3d)/120=18d/120=3d/20
ttl d: 3d+3d+2d=8d
average speed= 8d/(3d/20)=160/3=53.3333km/h sufficient
ANS: D.

Shlok02

Joined: 08 Jan 2024

Last visit: 07 Aug 2026

Posts: 64

Own Kudos:

[1]

Given Kudos: 6

Products:

Posts: 64

Kudos: 41

[1]

16 Jul 2026, 12:21

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

Statement 1 - t1:t2:t3 = 3:2:1
let total time of the courier = 6t,
t1 = 3t, t2 = 2t and t3 = t
speed = dist/time
40 = d1/3t => d1 = 120t
60 = d2/2t => d2 = 120t
80 = d3/t => d3 = 80t
Average speed = total dist / total time
avg speed = d1 + d2 + d3 / t1 + t2 + t3
= 120t + 120t + 80t / 6t
= 320t /6t = 320/6 km/hr
SUFFICENT

Staement 2 - d1:d2:d3 = 3:3:2
Total distance = 8d
d1 = 3d, d2=3d, d3 =2d
40 = 3d/t1 => t1 = 3d/40
60 = 3d/t2 => t2 = 3d/60
80 = 2d/t3 => t3 = 2d/80

Avg speed = 8d / (3d/40) + (3d/60) + (2d/80)
SUFFICIENT

Answer - D

Rishab2409

Joined: 11 May 2026

Last visit: 08 Aug 2026

Posts: 106

Own Kudos:

[1]

Given Kudos: 116

Products:

Posts: 106

Kudos: 26

[1]

16 Jul 2026, 13:17

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

Correct Answer (D)

Avg Speed = Distance/ Time

Statement 1: We have ratio of time - 3t, 2t, t.

Avg Speed= (40*3T+ 60*2T + 80*T) / (3T + 2T + T) which equals 53.33 km/hr. Sufficient.

Statement 2: We have ratio of distance 3d, 3d, 2d

Avg Speed = (3d + 3d + 2d) / (3d/40 + 3d/60 + 2d/80) which equals to 53.33 km/hr. Sufficient.

GurpreetMahli

Joined: 06 Aug 2023

Last visit: 08 Aug 2026

Posts: 28

Own Kudos:

[1]

Given Kudos: 91

Location: United States

Products:

Posts: 28

Kudos: 11

[1]

16 Jul 2026, 14:23

Kudos

Bookmarks

Answer = Each statement alone is sufficient

Given

Hillford

40km/hr

60 km/hr

80 km/hr

Lakeshore

Average speed = Total distance (D) / Total Time (T)

Three separate distances T(1)*40=D1, T(2)*60=D2, T(3)*80=D3

Statement 1:
Use ratio multiplier (3x:2x:1x)
40*3x=D1
60*2x=D2
80*1x=D3

Total Distance D1+D2+D3= 320x
Total Time=6x
Average speed 320x/6x

Sufficient

Statement: 2
Use ratio multiplier (3y:3y:2y)
40(T1)=3y
T1=(3y)/40

60(T2)=3y
T2=(3y)/60

80(T3)=2y
T3=(2y)//80

Total Time= T1+T2+T3
Total Distance= 8y
Average speed= 8y / ((3y)/40+(3y)/60+2y/(80)) = 320y/6y

Sufficient

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

obedear

Joined: 05 Sep 2024

Last visit: 08 Aug 2026

Posts: 99

Own Kudos:

[1]

Given Kudos: 14

Products:

Posts: 99

Kudos: 72

[1]

16 Jul 2026, 16:16

Kudos

Bookmarks

Answer is D - each statement alone.

This is a question testing our conceptual understanding of rate, distance and time. Let's use a logical approach.

1) We know the rates / speeds for each segment. What we do not know is the distance of each segment, nor do we know how much time he spent on each segment. If we know the ratio of the time spent for each of the segments, even though we do not know the actual amount of time, it doesn't matter because we know how long was spent at each speed per segment relative to each other segment. This allows us to know the total average speed. Another way to see it is if we know the avg. speed formula, that is:

Avg. Speed = Total Distance / Total Time
and; Distance = Time * Rate

We would have (T1*R1+T2*R2+T3*R3)/T1+T2+T3
Through knowing the ratio we essentially know the weight average and can find the answer.

S2) Since we are given the ratios of the distance of each segment, this is also enough to answer the question because we know the rates at which each segment is traveled, and that combined with the ratio of distance is enough to calculate average speed. This is because no matter the scale of the distance the same proportion of time would have to be spent traveling each one, i.e., the same average speed.

Answer A.

mehtyas

Joined: 27 May 2025

Last visit: 08 Aug 2026

Posts: 74

Own Kudos:

[1]

Given Kudos: 666

Location: India

Concentration: Finance, Strategy

Posts: 74

Kudos: 61

[1]

16 Jul 2026, 18:02

Kudos

Bookmarks

IMO - Answer should be Option D

The speeds for the 3 legs of the trip are 4km/h, 60km/h and 80km/h, respectively.

We need the overall average speed, which is = Total Distance / Total Time

S1 -> The time being spent on the 2 legs is in the ratio = 3:2:1

Let the times be 3t, 2t and t.

Then the distances are:

40 * 3t = 120t
60 * 2t = 120t
80 * t = 80t

Total distance = 320t and Total Time = 6t

Average speed = 320t/6t =53 1/3 km/h

S1 is sufficient

S2 -> The distances are in the ratio = 3:3:2. Let the actual distances be 3d, 3d and 2d.

The corresponding times are:

3d/40
3d/60
2d/80 = d/40

Total time = 3d/40 +3d/60 + d/40

Total distance = 8d

Average speed = 8d / (3d/20) = 160/3 = 53 1/3 km/h

S2 is sufficient

Answer: Option D - Each statement is alone sufficient.

harshitaa45

Joined: 20 Feb 2021

Last visit: 08 Aug 2026

Posts: 48

Own Kudos:

[1]

Given Kudos: 8

Products:

Posts: 48

Kudos: 30

[1]

16 Jul 2026, 18:27

Kudos

Bookmarks

Let the first leg distance be d1 and speed traveled is 40 kmph
The second leg distance is d2 and the speed with which it traveled is 60 kmph
The last leg distance is d3 and the speed with which it traveled is 80 kmph
If the avg speed of the travel is = total distance / total time
St1: Time spent in each leg is 3:2:1
d1/40=3t; d2/60=2t and d3/80=t => d1=120t d2=120t and d3= 80t
so Avg speed= d1d2+d3/(3t+2t+t)=120t+120t+80t / 6t = 53.33 kmph
So sufficient
St2:
d1:d2:d3=3:3:2
d1+d2+d3/ tot time= 3d+3d+2d/(3d/40+3d/60+2d/80)=> 8d/(3d/40+d/20+d/40) =53.33 kmph
St 2 is sufficient
So option D

metrogloomin

Joined: 16 Mar 2026

Last visit: 08 Aug 2026

Posts: 33

Own Kudos:

[1]

Given Kudos: 84

Location: United States (NY)

Schools: CBS '27 Booth '27 Wharton '27 Stern '27 Sloan '27 Stanford '27 HBS '27

GPA: 7.05

Products:

Schools: CBS '27 Booth '27 Wharton '27 Stern '27 Sloan '27 Stanford '27 HBS '27

Posts: 33

Kudos: 31

[1]

16 Jul 2026, 19:10

Kudos

Bookmarks

We have to find the average speed for the entire trip, so we need total distance/total time.
Leg 1 average speed = 40 kmph
Leg 2 average speed = 60 kmph
Leg 3 average speed = 80 kmph

(1)
Let the time spent on Leg 1, 2, 3 be 3x, 2x, x hours respectively.
Leg 1 distance = 40*3x = 120x km
Leg 2 distance = 60*2x = 120x km
Leg 3 distance = 80*x = 80x km
Total distance = 320x km
Total time = 6x hours
Average speed = 320x/6x kmph = 160/3 kmph
Sufficient.

(2)
Let the distance of Leg 1, 2, 3 be 3x, 3x, 2x km respectively.
Leg 1 time = 3x/40 hours
Leg 2 time = 3x/60 = x/20 hours
Leg 3 time = 2x/80 = x/40 hours
Total distance = 8x km
Total time = 3x/20 hours
Average speed = 8x/(3x/20) = 160/3 kmph
Sufficient.

(D)

alamin8

Joined: 24 May 2025

Last visit: 07 Aug 2026

Posts: 166

Own Kudos:

[1]

Given Kudos: 26

Location: Bangladesh

Concentration: Accounting, Technology

Schools: HEC Sept '27 INSEAD Aug '27 UNC '27

GPA: 3.89

Schools: HEC Sept '27 INSEAD Aug '27 UNC '27

Posts: 166

Kudos: 78

[1]

16 Jul 2026, 21:35

Kudos

Bookmarks

Average speed of the courier = d/t

St. 1
The given ratio = 3:2:1 = 3t:2t:1t = 6t (total time)
distance covered = 40*3t + 60*2t + 80*t = 320t
Average speed = 320t/6t
Sufficient

St. 2
length ratio = 3:3:2 = 3d:3d:2d = 8d (total distance)
Time generated = 3d/40 + 3d/60 + 2d/80
= d(3/40 + 3/60 + 1/40)
= d*(6/40) = 3d/20

Speed = 8d/(3d/20) = 160/3 Sufficient

Answer (D) Each statement alone is sufficient.