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17 Jul 2026, 06:50
Kudos
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First Leg: \(\frac{D1}{T1} =\frac{40km}{h}\)
Second Leg:\(\frac{ D2}{T2} =\frac{ 60 km}{h}\)
Third Leg: \(\frac{D3}{T3} = \frac{80Km}{H}\)
IMO
Second Leg:\(\frac{ D2}{T2} =\frac{ 60 km}{h}\)
Third Leg: \(\frac{D3}{T3} = \frac{80Km}{H}\)
- Statement 1: T1 = 3K , T2 =2k , T3 =1K total time of travel = 6K
\(D1=40*3k D2=60*2k D3=80*1k \)
\(Total distance= \frac{320K}{6K}\)
Statement 1 = Sufficient
- Statement 2: D1= 3K D2= 3K D3= 2K
\(T1=\frac{3K}{40} T2=\frac{3K}{60 }T3=\frac{2K}{80}\)We know total distance and total time of travel so we can calculate avg. speed no need to do whole calculationStatement 2 = Sufficient
IMO
17 Jul 2026, 06:55
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first leg: 40 km/h
second leg: 60 km/h
third leg: 80 km/h
average = (total length)/(total time)
(1)
time ratio 3:2:1
total time = 3k+2k+k = 6k
total length = 40*3k + 60*2k + 80*k = 120k + 120k + 80k = 320k
average = 320k/6k = 160/3
Sufficient
(2)
length ratio 3:3:2
total length = 3k+3k+2k = 8k
total time = 3k/40 + 3k/60 + 2k/80 = (18k + 12k + 6k)/240 = 36k/240 = 3k/20
average = 8k/(3k/20) = 160/3
Sufficient
IMO D
second leg: 60 km/h
third leg: 80 km/h
average = (total length)/(total time)
(1)
time ratio 3:2:1
total time = 3k+2k+k = 6k
total length = 40*3k + 60*2k + 80*k = 120k + 120k + 80k = 320k
average = 320k/6k = 160/3
Sufficient
(2)
length ratio 3:3:2
total length = 3k+3k+2k = 8k
total time = 3k/40 + 3k/60 + 2k/80 = (18k + 12k + 6k)/240 = 36k/240 = 3k/20
average = 8k/(3k/20) = 160/3
Sufficient
IMO D
17 Jul 2026, 07:02
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IMO D
both statements are sufficient
I )
1st leg == 40 km/ hr
2nd = 60
3rd = 80
d1+d2+d3 / t1+t2+t3 = avg speed
t1:t2: t3 = 3:2:1
d1 40. 3k
d2 = 60 .2k
d3 = 80 . k
avg = 320 k / 6k --- unique
statement 2
d1: d2:d3 = 3:3:2
t1 = 3x/40
t2= 3x/ 60
t3 = 2x / 80
avg speed = 8x / 3x/20 = 160 / 3
unique
both statements are sufficient
I )
1st leg == 40 km/ hr
2nd = 60
3rd = 80
d1+d2+d3 / t1+t2+t3 = avg speed
t1:t2: t3 = 3:2:1
d1 40. 3k
d2 = 60 .2k
d3 = 80 . k
avg = 320 k / 6k --- unique
statement 2
d1: d2:d3 = 3:3:2
t1 = 3x/40
t2= 3x/ 60
t3 = 2x / 80
avg speed = 8x / 3x/20 = 160 / 3
unique
