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16 Jul 2026, 08:00
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D
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Difficulty:
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Question Stats:
78% (01:48) correct
22%
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wrong
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A courier traveled from Hillford to Lakeshore in three consecutive legs, with no stops between the legs. On the first leg, the courier’s average (arithmetic mean) speed was 40 kilometers per hour; on the second leg, the courier’s average (arithmetic mean) speed was 60 kilometers per hour; and on the third leg, the courier’s average (arithmetic mean) speed was 80 kilometers per hour. What was the courier’s average speed for the entire trip?
(1) The ratio of the times the courier spent on the first, second, and third legs, respectively, was 3:2:1.
(2) The ratio of the lengths of the first, second, and third legs, respectively, was 3:3:2.
(1) The ratio of the times the courier spent on the first, second, and third legs, respectively, was 3:2:1.
(2) The ratio of the lengths of the first, second, and third legs, respectively, was 3:3:2.
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M46-57
16 Jul 2026, 09:00
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GMAT Club Official Solution:
A courier traveled from Hillford to Lakeshore in three consecutive legs, with no stops between the legs. On the first leg, the courier’s average (arithmetic mean) speed was 40 kilometers per hour; on the second leg, the courier’s average (arithmetic mean) speed was 60 kilometers per hour; and on the third leg, the courier’s average (arithmetic mean) speed was 80 kilometers per hour. What was the courier’s average speed for the entire trip?
The average speed for the entire trip is:
total distance / total time
(1) The ratio of the times the courier spent on the first, second, and third legs, respectively, was 3:2:1.
Let the times spent on the first, second, and third legs be 3t, 2t, and t, respectively.
Then the distances were:
• First leg: 40 * 3t = 120t
• Second leg: 60 * 2t = 120t
• Third leg: 80 * t = 80t
So the total distance was:
120t + 120t + 80t = 320t
The total time was:
3t + 2t + t = 6t
Therefore, the average speed for the entire trip was:
320t/(6t) = 160/3 kilometers per hour
Sufficient.
(2) The ratio of the lengths of the first, second, and third legs was 3:3:2.
Let the lengths of the first, second, and third legs be 3d, 3d, and 2d, respectively.
Then the times were:
• First leg: 3d/40
• Second leg: 3d/60
• Third leg: 2d/80
So the total distance was:
3d + 3d + 2d = 8d
The total time was:
3d/40 + 3d/60 + 2d/80 = 3d/20
Therefore, the average speed for the entire trip was:
8d/(3d/20) = 160/3 kilometers per hour
Sufficient.
Answer: D.
A courier traveled from Hillford to Lakeshore in three consecutive legs, with no stops between the legs. On the first leg, the courier’s average (arithmetic mean) speed was 40 kilometers per hour; on the second leg, the courier’s average (arithmetic mean) speed was 60 kilometers per hour; and on the third leg, the courier’s average (arithmetic mean) speed was 80 kilometers per hour. What was the courier’s average speed for the entire trip?
The average speed for the entire trip is:
total distance / total time
(1) The ratio of the times the courier spent on the first, second, and third legs, respectively, was 3:2:1.
Let the times spent on the first, second, and third legs be 3t, 2t, and t, respectively.
Then the distances were:
• First leg: 40 * 3t = 120t
• Second leg: 60 * 2t = 120t
• Third leg: 80 * t = 80t
So the total distance was:
120t + 120t + 80t = 320t
The total time was:
3t + 2t + t = 6t
Therefore, the average speed for the entire trip was:
320t/(6t) = 160/3 kilometers per hour
Sufficient.
(2) The ratio of the lengths of the first, second, and third legs was 3:3:2.
Let the lengths of the first, second, and third legs be 3d, 3d, and 2d, respectively.
Then the times were:
• First leg: 3d/40
• Second leg: 3d/60
• Third leg: 2d/80
So the total distance was:
3d + 3d + 2d = 8d
The total time was:
3d/40 + 3d/60 + 2d/80 = 3d/20
Therefore, the average speed for the entire trip was:
8d/(3d/20) = 160/3 kilometers per hour
Sufficient.
Answer: D.
General Discussion
16 Jul 2026, 08:26
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i am going with the option d.
avg speed = total distance/total time
A - time ratio 3:2:1, speed 40, 60, 80.
thus can find distance of each leg. this will give a unique total distance and total time. thus suff.
B - distance ratio 3:3:2 and the speeds, so can find the time for each leg, leaves a unique total time and a unique average speed, thus suff.
avg speed = total distance/total time
A - time ratio 3:2:1, speed 40, 60, 80.
thus can find distance of each leg. this will give a unique total distance and total time. thus suff.
B - distance ratio 3:3:2 and the speeds, so can find the time for each leg, leaves a unique total time and a unique average speed, thus suff.
