A.

No of cups leaked during the trip = 2 cups.
No of cups Harry drank = 7 cups.
No of cups harry drank during the first 5 miles = 4.
drink / mile = 4/5

HMTG.

10 cups at beginning.

1 cup remaining at end so total 9 cups of water lost

1 cup per hour leakage , so in 2 hrs 2 cups of water lost

9-2 = 7

last 1 mile he drank 3 cups , so for first 5 miles total water used = 7-3 = 4

so per mile 4/5

I read all of the explanations above and i wasn't convinced on one thing. I had the below reasoning while solving this question and never reached the correct answer. Plz tell me whats wrong with this:

The question asked about the first 5 miles of the trip. So, IMO, the quantity of water that was lost due to because of the leak should also be calculated for the first 5 miles and not for the complete trip. Thus the water lost would be less than 2.

Here's what i calculated:
Total water initially = 10 cups
Total water used (including leak) in 6 miles = 9 cups
Total water used (including leak) in first 5 miles = 9-3 = 6 cups

Problem starts here (all say 2 cups leaked and subtract it from 6 to get 4, i differ)

Time taken to cover first 5 miles: \(\frac{5}{3}\) hours (speed is 3 mph)
Water leaked in 5/3 hours: \(\frac{5}{3}\) cups (leak speed is 1 cup per hr)
Total water he drank during the first 5 miles: \(6-\frac{5}{3}\) cups
= \(\frac{13}{3}\) cups
Water drank per mile during the first 5 miles: \(\frac{13}{15}\)

Why am i wrong?
_________________