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How many hours did it take Helen to drive from her house to her parent [#permalink]
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26 Mar 2010, 17:00
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How many hours did it take Helen to drive from her house to her parent's house? (1) Helen's average speed on this trip was 72 kilometers per hour (2) If Helen's average speed on this trip had been 8 kilometers per hour greater , it would have taken her 1 hour less.
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How many hours did it take Helen to drive from her house to her parent [#permalink]
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26 Mar 2010, 17:10



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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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27 Mar 2010, 08:52
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changhiskhan wrote: How many hours did it take Helen to drive from her house to her parents house?
1) Helen’s average speed on this trip was 72 kilometers per hour. 2) If Helen’s average speed on this trip had been 8 kilometers per hour greater, it would have taken her 1 hour less.
Thanks in advance! 1: Not sufficient, easy to spot 2: distance is d av speed: a then time is t av speed: a1 then time is t1 d/a = d/a+8 + 1 can't solve alone insufficient. Combining, d/72 = d/80 + 1 solving d = 80 then t can be calculated hence C.



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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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27 Apr 2010, 05:57
zz0vlb wrote: How many hours did it take Helen to drive from her house to her parents's house? (1) Helen's average speed on this trip was 72 km/hr. (2) If Helen's average speed on this trip has been 8 km/hr greater, it would have taken her 1 hour less. Source: GMAT Prep Can someone explain this clearly. Hi, Its C. You need to calculate the distance, let that be D. Now from 1 you just get the speed. To know D you need time and speed both. so 1 is insufficient Using 2 you just get the difference in speed and the time, again no concrete values. so 2 is insufficient. However if you combine 1 and 2 you get 2 speeds and the difference in time. Here is how the solution would be Earlier speed = 72. time taken at 72 km/hr = t1 t1 = D/72 Later speed = 72+8 = 80 km/hr Time taken at 80 km/hr = t2 t2 = D/80 Now t1t2 = 1 D/72 D/80 = 1 Solve this and you get D = 720 km.
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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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15 Mar 2011, 23:39
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changhiskhan wrote: How many hours did it take Helen to drive from her house to her parents house?
1) Helen’s average speed on this trip was 72 kilometers per hour. 2) If Helen’s average speed on this trip had been 8 kilometers per hour greater, it would have taken her 1 hour less.
Thanks in advance! C after 3:40 minutes
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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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16 Mar 2011, 19:37
Let distance from her house to her parents house = D, average speed v, and time taken be t (1) is insufficient, we only have t = D/72 From (2), D/(v+8) = D/v  1 So this is not sufficient either, but if we combine (1) and (2), v = 72 and hence we can find out both. So the answer is C.
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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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18 Mar 2011, 02:10
basically, we are provided with two equations in 1statement 1 and 2. having two equations it is possible to solve equality with two uknowns. hence it is C. 30 seconds.
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Re: Time taken [#permalink]
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kotela wrote: How many hours did it take helen to drive from her house to her parent's house?
1. Helen's average speed on this trip was 72 Km/hr
2. If Helen's average speed on this trip had been 8 Km/hr greater it would have taken 1 hr less
can anyone explain? let time req. be t. let distance covered be d. 1. d/t=72. Insufficient 2. d/(t1)=80 Insufficient 1+2 d=72t d=80(t1) 72t=80(t1) Sufficient
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Originally posted by blink005 on 26 Oct 2011, 03:07.
Last edited by blink005 on 26 Oct 2011, 07:15, edited 1 time in total.



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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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26 Nov 2012, 07:38
Could you also solve this problem by thinking of it as a ratio? One of MGMAT's strategies for DS ratio questions is that if a DS question asks for the concrete value of one element of a ratio, you will need both the concrete value of another element and the relative value of 2 elements of the ratio. When you combine the two statements, you get a concrete value from statement 1 and two relative values from statement 2. Is that a logical way to solve this problem, once you already know that the two statements individually are insufficient?
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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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01 Aug 2013, 11:52
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How many hours did it take Helen to drive from her house to her parents house?
1) Helen’s average speed on this trip was 72 kilometers per hour. We know nothing about distance. If the distance was 72km then it would have taken one hour. If the distance was 720km then it would have taken 10 hours, etc. All we know is r=72 INSUFFICIENT
2) If Helen’s average speed on this trip had been 8 kilometers per hour greater, it would have taken her 1 hour less. Time=distance/speed T1 = d/(s+8) This does not provide enough information to solve for the question. INSUFFICIENT
1+2) average speed (r) = 72, t1 = d/(s+8) t1 = d/(72+8) t1 = d/80 This is where it gets tricky. At first I said that this isn't enough information to solve so I put down (E). However, d=r*t. If I plug in for d then I can cancel out t leaving r. t1 = r*t/(72+8) t1 = 72*t/(80) 80t80 = 72t 8t = 80 t=10
A couple things to remember:  If in doubt and unable to solve, try and substitute in a formula (like=r*t) to cancel out variables.  remember to plug in any applicable numbers for all variables. For example, after plugging in r*t for d, I forgot to plug in 72 for r*t. SUFFICIENT
(C)



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Re: How many hours did it take Helen to drive from her house to her parent [#permalink]
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17 Nov 2014, 11:29
PTK wrote: basically, we are provided with two equations in 1statement 1 and 2. having two equations it is possible to solve equality with two uknowns.
hence it is C.
30 seconds. Well, I thought that we were provided with 3 equations and 3 variables. The answer is the same (C) but I think my reasoning is slightly different. Question stem: RT = D (3 variables, 1 equation). We need 2 more equations in the statements to solve this problem. Remember, whenever you are dealing with distance, you already have an equation (RT = D). The same goes for Work Problems (RT = W) St 1: R = 72. Insufficient. St 1 just gives us 1 more equation. St. 2: (R + 8)(T  1) = D. Insufficient. St 2 just gives us 1 more equation. St 1 + 2: we now have 2 more equations apart from the one given in the question stem. We now have 3 equations and 3 unknowns. We can solve for this stuff: no need to do the calculations. Hope it makes sense.
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