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How many natural numbers that are less than 10,000 can be
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16 Jun 2012, 19:23
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How many natural numbers that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 & 8? A. 5000 B. 4096 C. 6560 D. 4095 E. 8000
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Re: How many natural numbers that are less than 10,000 can be
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17 Jun 2012, 01:50
cyberjadugar wrote: How many natural numbers that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 & 8?
A. 5000 B. 4096 C. 6560 D. 4095 E. 8000 The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?We are given 8 digits to form the numbers of a type ****. Now, each slot in **** can take 8 values, so total numbers would be 8*8*8*8=8^4, but we should exclude number 0 (since 0 is one of the digits given than 8^4 will include 0 too). So, the final answer would be 8^41. Now, the question becomes how to calculate this value. The units digit of 8^4 would be 6, so the units digit of 8^41 would be 5. Only answer choice D fits. Answer: D. Similar question to practice: howmanyfourdigitpositiveintegerscanbeformedbyusing133069.htmlhowmanypositiveintegersoffourdifferentdigitseach100898.htmlhowmanyevennumbersgreaterthan300canbeformedwith100578.htmlhowmanyeven4digitnumberscanbeformedsothatthe95371.htmlm0470602.htmlHope it helps.
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Re: How many natural numbers that are less than 10,000
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16 Jun 2012, 20:29
Answer D.
Solution:
We are missing digits 5 and 9 in the question. So we have 8 digits for each position (ones,tens,hundreds,thousands).
The numbers that can be constructed using 8 digits in 4 positions = (8 x 8 x 8 x 8)  1 (To disregard the case 0000) = 4096  1 = 4095
If you have use 10 digits (0 thru 9), you have (10 x 10 x 10 x 10)  1 = 9999 numbers.



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Re: How many natural numbers that are less than 10,000 can be
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17 Jun 2012, 01:54
Bunuel wrote: The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?
Hi, I am just curious, that what difference it would make if we say positive integers or natural numbers? Regards,



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Re: How many natural numbers that are less than 10,000 can be
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17 Jun 2012, 02:03
cyberjadugar wrote: Bunuel wrote: The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?
Hi, I am just curious, that what difference it would make if we say positive integers or natural numbers? Regards, Not much. Though notice that "there is no universal agreement about whether to include zero in the set of natural numbers: some define the natural numbers to be the positive integers {1, 2, 3, ...}, while for others the term designates the nonnegative integers {0, 1, 2, 3, ...}" so I've never seen the official GMAT question using "natural numbers". Hope it's clear.
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Re: How many natural numbers that are less than 10,000 can be
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17 Jun 2012, 02:36
Bunuel wrote: cyberjadugar wrote: Bunuel wrote: The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?
Hi, I am just curious, that what difference it would make if we say positive integers or natural numbers? Regards, Not much. Though notice that "there is no universal agreement about whether to include zero in the set of natural numbers: some define the natural numbers to be the positive integers {1, 2, 3, ...}, while for others the term designates the nonnegative integers {0, 1, 2, 3, ...}" so I've never seen the official GMAT question using "natural numbers". Hope it's clear. I always thought that Natural numbers = {1,2,3...} and Whole numbers = {0,1,2,3..} Never knew about this ambiguity. Thanks!..



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Re: How many natural numbers that are less than 10,000 can be
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24 Sep 2012, 05:54
According to what i have read  it is always better to assume natural numbers beginning from 01 onward (for the gmat) unless otherwise stated. Assuming that to be the case we can sub divide the problem into : A) Four digit Numbers : _ _ _ _ , The ones place  hundreds place can be filled by any one of the 8 numbers given (the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) the thousands place can be filled by any number except "0".. This gives us 7 x 8 x 8 x 8 = 3584 B) Three digit Numbers : _ _ _ , The ones place  tens Place can be filled by any one of the 8 numbers given ( the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) , the hundreds place can be filled by only 7 of the given 8 numbers (If we use "0" we will end up with a two digit number ). This gives us 7 x 8 x 8 = 448 C) Two digit numbers : _ _ , The ones place can be filled up by any one of the 8 numbers given , and the tens place by any 7 of the 8 ... This gives us 7 x 8 = 56 D) Assuming that zero is not a natural number , we have seven different possibilities for the one digit numbers . 7 Add A + B + C + D , This gives us 3584 + 448 + 56 + 7 = 4095 (D) Now let us assume that ZERO is a NATURAL number (as some mathematicians do) ... A thru C is not effected by this assumption as the resultant would have meant that a four number digit with a zero at the beginning would have effectively made it a three digit no. , and a 0 to begin a three digit number would make it a two digit number etc ... The only difference including ZERO to be a natural number would have made for D , in that it would have given it 8 possibilities instead of 7 ... Which would have added 1 to our total making it 4096. Simply by looking at the answer choices we can determine that the test maker wanted natural numbers to begin from 1 and not from 0 ( as per the answer choices) ..
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Re: How many natural numbers that are less than 10,000 can be
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13 Aug 2015, 01:13
cyberjadugar wrote: How many natural numbers that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 & 8?
A. 5000 B. 4096 C. 6560 D. 4095 E. 8000 the answer is D there are 7 single digit natural numbers . 0 is not a natural number. there are 7x8=56 two digit numbers there are 7x8x8=448 three digit numbers there are 7x8x8x8=3584 four digit numbers. Hence, there are 4095 numbers in all.



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Re: How many natural numbers that are less than 10,000 can be
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01 Jan 2016, 22:28
The question has to be corrected to read 'positive' instead of natural then? Please correct it.



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Re: How many natural numbers that are less than 10,000 can be
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02 Jan 2016, 07:22
Bunuel, The question did not say 4 digit integers, is it right here to consider only 4 digit numbers here. Regards, Praveen Bunuel wrote: cyberjadugar wrote: How many natural numbers that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 & 8?
A. 5000 B. 4096 C. 6560 D. 4095 E. 8000 The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?We are given 8 digits to form the numbers of a type ****. Now, each slot in **** can take 8 values, so total numbers would be 8*8*8*8=8^4, but we should exclude number 0 (since 0 is one of the digits given than 8^4 will include 0 too). So, the final answer would be 8^41. Now, the question becomes how to calculate this value. The units digit of 8^4 would be 6, so the units digit of 8^41 would be 5. Only answer choice D fits. Answer: D. Similar question to practice: howmanyfourdigitpositiveintegerscanbeformedbyusing133069.htmlhowmanypositiveintegersoffourdifferentdigitseach100898.htmlhowmanyevennumbersgreaterthan300canbeformedwith100578.htmlhowmanyeven4digitnumberscanbeformedsothatthe95371.htmlm0470602.htmlHope it helps.



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Re: How many natural numbers that are less than 10,000 can be
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03 Jan 2016, 10:09
Praveengeol wrote: Bunuel, The question did not say 4 digit integers, is it right here to consider only 4 digit numbers here. Regards, Praveen Bunuel wrote: cyberjadugar wrote: How many natural numbers that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 & 8?
A. 5000 B. 4096 C. 6560 D. 4095 E. 8000 The question should read: How many positive integers less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 7 and 8?We are given 8 digits to form the numbers of a type ****. Now, each slot in **** can take 8 values, so total numbers would be 8*8*8*8=8^4, but we should exclude number 0 (since 0 is one of the digits given than 8^4 will include 0 too). So, the final answer would be 8^41. Now, the question becomes how to calculate this value. The units digit of 8^4 would be 6, so the units digit of 8^41 would be 5. Only answer choice D fits. Answer: D. Similar question to practice: howmanyfourdigitpositiveintegerscanbeformedbyusing133069.htmlhowmanypositiveintegersoffourdifferentdigitseach100898.htmlhowmanyevennumbersgreaterthan300canbeformedwith100578.htmlhowmanyeven4digitnumberscanbeformedsothatthe95371.htmlm0470602.htmlHope it helps. Positive integers less than 10,000 include singledigit integers, 2digit integers, 3digit integers and 4digit integers. 8^4 gives all of them. For example, if we choose 0 for the first 3 *'s we get singledigit integers and if we choose 0 for the first 2 *'s we get 2digit integers. Hope it's clear.
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How many natural numbers that are less than 10,000 can be
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01 Jun 2016, 07:14
I chose the following approach to solving this question: Total numbers to choose from: 8 Scope: 0  9999 1digit numbers: 7 (all except 0) 2digit numbers: 7 x 8 = 56 3digit numbers: 7 x 8 x 8 = 448 4digit numbers: 7 x 8 x 8 x 8 = 56 x 64 = 3584 Total: 7 + 56 + 448 + 3584 = 4095 Note: Don't make the careless mistake that I made: I first added 1 to 4095 and picked 4096 because I thought 10,000 should be included. But the question asks for less than 10,000!
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Re: How many natural numbers that are less than 10,000 can be
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28 Aug 2018, 12:13
vomhorizon wrote: According to what i have read  it is always better to assume natural numbers beginning from 01 onward (for the gmat) unless otherwise stated. Assuming that to be the case we can sub divide the problem into :
A) Four digit Numbers : _ _ _ _ , The ones place  hundreds place can be filled by any one of the 8 numbers given (the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) the thousands place can be filled by any number except "0".. This gives us 7 x 8 x 8 x 8 = 3584
B) Three digit Numbers : _ _ _ , The ones place  tens Place can be filled by any one of the 8 numbers given ( the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) , the hundreds place can be filled by only 7 of the given 8 numbers (If we use "0" we will end up with a two digit number ). This gives us 7 x 8 x 8 = 448
C) Two digit numbers : _ _ , The ones place can be filled up by any one of the 8 numbers given , and the tens place by any 7 of the 8 ... This gives us 7 x 8 = 56
D) Assuming that zero is not a natural number , we have seven different possibilities for the one digit numbers . 7
Add A + B + C + D , This gives us 3584 + 448 + 56 + 7 = 4095 (D)
Now let us assume that ZERO is a NATURAL number (as some mathematicians do) ... A thru C is not effected by this assumption as the resultant would have meant that a four number digit with a zero at the beginning would have effectively made it a three digit no. , and a 0 to begin a three digit number would make it a two digit number etc ... The only difference including ZERO to be a natural number would have made for D , in that it would have given it 8 possibilities instead of 7 ... Which would have added 1 to our total making it 4096. Simply by looking at the answer choices we can determine that the test maker wanted natural numbers to begin from 1 and not from 0 ( as per the answer choices) .. You have earned this kudos, thank you for a comprehensive explanation.
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