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17 Aug 2019, 22:46
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Difficulty:
35%
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79% (02:05) correct
21%
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How many numbers between 200 and 800 are divisible by both 5 and 7?
(A) 16
(B) 17
(C) 19
(D) 34
(E) 35
Posted from my mobile device
(A) 16
(B) 17
(C) 19
(D) 34
(E) 35
Posted from my mobile device
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vaibhav1221
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17 Aug 2019, 23:59
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Numbers that are divisible by both 5 and 7 have to be divisible 35.
35 x 17 is 595 which is less than the numbers between 200 and 800, however, the smallest number between 200 and 800 divisible by 35 is 210. When we add 595 to 210, the resulting figure is greater than 800. This means that the the last number, which is the 18th number would lie outside the range, hence there are only 17 numbers between 200 and 800 that are divisible by both 5 & 7.
35 x 17 is 595 which is less than the numbers between 200 and 800, however, the smallest number between 200 and 800 divisible by 35 is 210. When we add 595 to 210, the resulting figure is greater than 800. This means that the the last number, which is the 18th number would lie outside the range, hence there are only 17 numbers between 200 and 800 that are divisible by both 5 & 7.
Jashan25
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18 Aug 2019, 00:28
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I solved it with a simple logical approach -
1) What will be the first number that satisfies the condition ..... answer is 35*6 i.e 210
2) What will be the last number that satisfies the condition .......answer is 35*22 i.e 770
total count of such number will => 22-6+1 = 17
IMO 17
P.S This is the first time I am posting a solution, excuse me if I am not following any standard norms to post a solution and also educate me about the same.
1) What will be the first number that satisfies the condition ..... answer is 35*6 i.e 210
2) What will be the last number that satisfies the condition .......answer is 35*22 i.e 770
total count of such number will => 22-6+1 = 17
IMO 17
P.S This is the first time I am posting a solution, excuse me if I am not following any standard norms to post a solution and also educate me about the same.
