GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 14 Oct 2019, 17:03

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# How many unique rectangles are possible that have a perimeter of not m

Author Message
TAGS:

### Hide Tags

Intern
Joined: 14 Apr 2012
Posts: 13
How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

08 Mar 2015, 10:41
4
1
15
00:00

Difficulty:

95% (hard)

Question Stats:

34% (02:22) correct 66% (02:09) wrong based on 198 sessions

### HideShow timer Statistics

How many unique rectangles are possible that have a perimeter of not more than 258cm and integers for length of each side?

A. 65
B. 129
C. 4158
D. 4160
E. 130
Manager
Status: Gmat Prep
Joined: 22 Jul 2011
Posts: 73
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

08 Mar 2015, 22:53
8
2

1,1; 1,2;1,3.....1,128(128 combinations)
2,2;2,3;2,4....2,127(126 combinations)
3,3;3,4;3,5....3,126(124 combinations)
4,4;4,5;4,6....4,125(122 combinations)

62,62;62,63;62,64;62,65;62,66;62,67(6 combinations)
63,63;63,64;63,65;63,66,(4 combinations)
64,64; 64,65......(2 combinations)

sum= n(a1+an)/2
n= 128/2=64
a1=2
an=128
sum= 64*(128+2)/2= 4160 hence answer is D

Kudos if this helps
##### General Discussion
Director
Joined: 07 Aug 2011
Posts: 502
GMAT 1: 630 Q49 V27
How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

Updated on: 04 Apr 2015, 17:44
How many unique rectangles can be formed such that their perimeter of not more than 258 and integers for the length of each sides ?

a) 129
b) 65
c) 4158
d) 4160
e) None of the above.

Apologies, adding exact question and correct options.

Originally posted by Lucky2783 on 04 Apr 2015, 07:07.
Last edited by Lucky2783 on 04 Apr 2015, 17:44, edited 2 times in total.
Retired Moderator
Joined: 06 Jul 2014
Posts: 1220
Location: Ukraine
Concentration: Entrepreneurship, Technology
GMAT 1: 660 Q48 V33
GMAT 2: 740 Q50 V40
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 08:26
Lucky2783 wrote:
How many rectangles can be formed such that their perimeter is less than 258 ?

a) 178
b) 284
c) 1094
d) 4160
e) 4095

Author of this task say nothing about integers, but I think it is only possible variant that sides can't be decimals.

So our max perimeter should be 256 and sum of two opposite sizes should be 256 / 2 = 128

Let's take some first variant and look for pattern
one side - 1 and with this side we can make 127 another variants: 1-1, 1-2, 1-3 and so on up to 1-127
one side - 2 and with this side we can make 126 another variants: 2-1, 2-2, 2-3 and so on up to 2-126. But we already have rectangular 2-1 so we should subtract this variant and we have 125 possible variants
one side - 3 and we have 123 another possible variants

so now we can make a formula for calculating possible variants for side n: variants = 129 - 2n
Our max size for side before repetion wil be equal
129 / 2 = 64.5. (we can use ony 64) And side 64 will be have 1 variant. 129 - 2*64 = 1

And now we should calculate sum of all this variants from 127 to 1
Formula for calcualting sum of sequence ((1 number + last number) / 2) * quantity of numbers
((127 + 1) / 2) * 64 = 4096

And we don't have such answer in our variants, so it'll be really interesting to know where I have made mistake.
_________________
Math Expert
Joined: 02 Aug 2009
Posts: 7954
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 10:15
Lucky2783 wrote:
How many rectangles can be formed such that their perimeter is less than 258 ?

a) 178
b) 284
c) 1094
d) 4160
e) 4095

hi Harley1980 and Lucky2783,
i too think answer is 4096..
although it is necessary that the question mentions that the sides are integers to get a finite numbers, otherwise the answer can be infinite with a pair of sides .1 or .001, etc

now if we consider that sides are integer, lets look at the solution..
perimeter has to be an even number so largest perimeter is 256
the possible perimeters are 4,6,8,...256..
if perimeter is 4.. sides are 1 and 1.. possibility 1
if perimeter is 6.. sides are 2 and 1..possibility 1
if perimeter is 8.. sides are 2 and 2 or 1 and 3..possibilities 2
and so on.. it follows a pattern.. each succeeding pair has one extra possiblity..
so total=1+1+2+2+3+3+.....63+63+64=2(1+2+3+...+63)+64=2*64*63/2+64=64*63+64=64*64=4096...

if the perimeter is equal to less than 258 then 258 will also add up and it will have 64 posssiblities and the answer than will be 4160 D
_________________
Director
Joined: 07 Aug 2011
Posts: 502
GMAT 1: 630 Q49 V27
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 10:34
chetan2u wrote:
Lucky2783 wrote:
How many rectangles can be formed such that their perimeter is less than 258 ?

a) 178
b) 284
c) 1094
d) 4160
e) 4095

hi Harley1980 and Lucky2783,
i too think answer is 4096..
although it is necessary that the question mentions that the sides are integers to get a finite numbers, otherwise the answer can be infinite with a pair of sides .1 or .001, etc

now if we consider that sides are integer, lets look at the solution..
perimeter has to be an even number so largest perimeter is 256
the possible perimeters are 4,6,8,...256..
if perimeter is 4.. sides are 1 and 1.. possibility 1
if perimeter is 6.. sides are 2 and 1..possibility 1
if perimeter is 8.. sides are 2 and 2 or 1 and 3..possibilities 2
and so on.. it follows a pattern.. each succeeding pair has one extra possiblity..
so total=1+1+2+2+3+3+.....63+63+64=2(1+2+3+...+63)+64=2*64*63/2+64=64*63+64=64*64=4096...

if the perimeter is equal to less than 258 then 258 will also add up and it will have 64 posssiblities and the answer than will be 4160 D

apologies for the confusion , i have not properly worded the question .
edited the question with correct answer options and question stem .
Retired Moderator
Joined: 06 Jul 2014
Posts: 1220
Location: Ukraine
Concentration: Entrepreneurship, Technology
GMAT 1: 660 Q48 V33
GMAT 2: 740 Q50 V40
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 13:28
1
Lucky2783 wrote:
chetan2u wrote:
Lucky2783 wrote:
How many rectangles can be formed such that their perimeter is less than 258 ?

a) 178
b) 284
c) 1094
d) 4160
e) 4095

hi Harley1980 and Lucky2783,
i too think answer is 4096..
although it is necessary that the question mentions that the sides are integers to get a finite numbers, otherwise the answer can be infinite with a pair of sides .1 or .001, etc

now if we consider that sides are integer, lets look at the solution..
perimeter has to be an even number so largest perimeter is 256
the possible perimeters are 4,6,8,...256..
if perimeter is 4.. sides are 1 and 1.. possibility 1
if perimeter is 6.. sides are 2 and 1..possibility 1
if perimeter is 8.. sides are 2 and 2 or 1 and 3..possibilities 2
and so on.. it follows a pattern.. each succeeding pair has one extra possiblity..
so total=1+1+2+2+3+3+.....63+63+64=2(1+2+3+...+63)+64=2*64*63/2+64=64*63+64=64*64=4096...

if the perimeter is equal to less than 258 then 258 will also add up and it will have 64 posssiblities and the answer than will be 4160 D

apologies for the confusion , i have not properly worded the question .
edited the question with correct answer options and question stem .

_________________
Intern
Joined: 20 Mar 2015
Posts: 3
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 14:35
Director
Joined: 07 Aug 2011
Posts: 502
GMAT 1: 630 Q49 V27
How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 17:42
1
Harley1980 wrote:

nopes the answer is correct as i mentioned in the spoiler, the question stem was not correct .

2(l+w) <=258
(l+w) <=129
first case
l+w=129
128,1
127,2
126,3
..
..
65,64
64 such pairs
Second case
l+w=128
127,1
126,2
125,3
..
..
65,63
64,64
64 such pairs

for (l+w)=127 and 126 we will get 63 such pairs for each .
finally for (l+w)=3 and 2 we will get only 1 pair.

so SUM = $$\frac{(1+64)}{2} * 2*64$$ = 64*65 = Answer D
Math Expert
Joined: 02 Aug 2009
Posts: 7954
How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 18:59
Lucky2783 wrote:
Harley1980 wrote:

nopes the answer is correct as i mentioned in the spoiler, the question stem was not correct .

2(l+w) <=258
(l+w) <=129
first case
l+w=129
128,1
127,2
126,3
..
..
65,64
64 such pairs
Second case
l+w=128
127,1
126,2
125,3
..
..
65,63
64,64
64 such pairs

for (l+w)=127 and 126 we will get 63 such pairs for each .
finally for (l+w)=3 and 2 we will get only 1 pair.

so SUM = $$\frac{(1+64)}{2} * 2*64$$ = 64*65 = Answer D

hi ,
how can the answer be correct if the question itself is wrong?

if the question says not more than 258 , then 64 is added to 4096 and answer becomes 4160 D...
_________________
Director
Joined: 07 Aug 2011
Posts: 502
GMAT 1: 630 Q49 V27
Re: How many rectangles can be formed such that their perimeter is less  [#permalink]

### Show Tags

04 Apr 2015, 19:06
chetan2u wrote:
hi ,
how can the answer be correct if the question itself is wrong?

if the question says not more than 258 , then 64 is added to 4096 and answer becomes 4160 D...

Agree . Everyone has solved the question correctly.
+1 Kudos .
Math Expert
Joined: 02 Sep 2009
Posts: 58320
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

05 Apr 2015, 04:55
Lucky2783 wrote:
How many unique rectangles can be formed such that their perimeter of not more than 258 and integers for the length of each sides ?

a) 129
b) 65
c) 4158
d) 4160
e) None of the above.

Apologies, adding exact question and correct options.

_________________
Intern
Joined: 11 Apr 2013
Posts: 12
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

12 Apr 2015, 22:46
1
quite a few good explanations above there but can someone enlighten me how can we solve this question in less than 2 min?? any recomended short-cuts for this one ???
Senior Manager
Joined: 29 Jun 2017
Posts: 424
GPA: 4
WE: Engineering (Transportation)
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

15 Sep 2017, 08:56
2(L+B) =258
L+B=129
combinations can be
128- 1
127-1,2
.
.
.
65-1,2,3,4.........64
64-1,2,3............64
63-1,2,3..........63
.
.
2-1
1-0

=> total possibility => 2x sum of integers from 1-64
=> 2x 64x65/2
=> 64x65 => 4160

OPTION D
_________________
Give Kudos for correct answer and/or if you like the solution.
Intern
Joined: 14 Sep 2017
Posts: 4
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

15 Sep 2017, 10:29
anshul2014 wrote:
quite a few good explanations above there but can someone enlighten me how can we solve this question in less than 2 min?? any recomended short-cuts for this one ???

I know, it's too late now but still here you go.

Now, neither of them can be zero. So, let's give them 1 each from 129. It reduces to

This is a distribution question now. We will have many scenarios where length and breadth values will interchange which are repeated solutions. We will have to have those cases. But, there will be scenarios where interchanging the values of length and breadth won't affect as in when they are equal (talking about squares ). How many squares will be formed. Since, they will be equal, their sum will be even. So, we have a total of 64 such square cases.

Total repeated rectangles formed = [C(127+2, 2) + 64]/2 = 4160.

The Variable : I change but remain constant
_________________
Problems in life have easy solutions. Its YOU who make them difficult!
Intern
Joined: 14 Sep 2017
Posts: 4
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

15 Sep 2017, 10:30
The.Variable wrote:
anshul2014 wrote:
quite a few good explanations above there but can someone enlighten me how can we solve this question in less than 2 min?? any recomended short-cuts for this one ???

I know, it's too late now but still here you go.

Now, neither of them can be zero. So, let's give them 1 each from 129. It reduces to

This is a distribution question now. We will have many scenarios where length and breadth values will interchange which are repeated solutions. We will have to have those cases. But, there will be scenarios where interchanging the values of length and breadth won't affect as in when they are equal (talking about squares ). How many squares will be formed. Since, they will be equal, their sum will be even. So, we have a total of 64 such square cases.

Total repeated rectangles formed = [C(127+2, 2) + 64]/2 = 4160.

The Variable : I change but remain constant

Edit: Read: We will have to remove such cases.

The Variable : I change but remain constant
_________________
Problems in life have easy solutions. Its YOU who make them difficult!
Non-Human User
Joined: 09 Sep 2013
Posts: 13143
Re: How many unique rectangles are possible that have a perimeter of not m  [#permalink]

### Show Tags

03 Nov 2018, 04:10
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: How many unique rectangles are possible that have a perimeter of not m   [#permalink] 03 Nov 2018, 04:10
Display posts from previous: Sort by