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If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is

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If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is  [#permalink]

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New post 01 Aug 2017, 01:03
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If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is  [#permalink]

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New post 01 Aug 2017, 01:10
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Bunuel wrote:
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?


A. 1/2
B. 1
C. 5
D. 32
E. 64


Since n is a non-negative integer n can take 0,1,2,3,4,5

Greatest value in a fraction means n should be smallest i.e. 0
\(1/2^0\) = 1

B
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Re: If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is  [#permalink]

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New post 01 Aug 2017, 01:15
n is a non-negative integer = N is 0 and all positive integer

0<10n<1,000,000 means Power n can have max value as 5 which will give 100,000

and n can have minimum value as 0 which will make 10n = 1.

So n can be 0,1,2,3,4 and 5

So what value can be taken to make 1/2n (Power N)as max value. So minimum can be taken to make 1/2n max ..which is Zero can be taken.

So Answer will be 1/1 = 1 == Option (B)
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If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is  [#permalink]

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New post 05 Aug 2017, 09:07
Bunuel wrote:
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?


A. 1/2
B. 1
C. 5
D. 32
E. 64


\(0 < 10^n < 1,000,000\)

0 < 10^n < 10^6

So, n could be 0,1,2,3,4,5 since n is a non-negative integer.

The greatest value of \(\frac{1}{2^n}\) could be achieved if 2^n is the smallest, i.e. for n = 0 at which the fraction becomes 1/2^0
or 1/1 = 1.

Ans B) 1
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Re: If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is  [#permalink]

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Re: If 0 < 10^n < 1,000,000, where n is a non-negative integer, what is   [#permalink] 02 Sep 2018, 07:53
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