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If 1/3 of the total number of marbles in the three bags listed in the

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If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 17 Jun 2016, 05:19
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 17 Jun 2016, 13:56
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9
Bag P : 10.8% of 37 = 4
Bag Q : 66.7% of x = 2x/3
Bag R : 50% of 32 = 16.

Given, 4 + 2x/3 + 16 = 1/3 ( 37+x+32) => x = 9. Hence B.
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 20 Aug 2016, 09:37
FacelessMan wrote:
Bag P : 10.8% of 37 = 4
Bag Q : 66.7% of x = 2x/3
Bag R : 50% of 32 = 16.

Given, 4 + 2x/3 + 16 = 1/3 ( 37+x+32) => x = 9. Hence B.


I have approximated 10.8% as 1/9, which is 11.1%
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New post 21 Aug 2016, 00:17
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This might look like it contains hard calculations, but the thing to notice here is that the number of balls are always going to be integers.

So, 10.8% of 37 will be 4, we know 50% of x is 32 and we can keep 66.7% as 2/3rds. Once you do this, the question can be solved to arrive at ~9 quickly.
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New post 21 Aug 2016, 05:38
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If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Total has to be multiple of 3 since 1/3rd of them are blue and 1st and 3rd bag have total 69 marbles so (69 + x)/3 is blue total hence x also must be divisible by 3

hence narrow down to B) 9 or C) 12

66.67 % is nothing but 2/3 rd (ie 33.33 * 2 ie 1/3 * 2)

so if x is 9 then blue marbles in 2nd bag is 6 (2/3rd of 9 = 6)
or if x is 12 then blue marbles in 3rd bag is 8 (2/3rd of 12 = 8)

do that math : if x = 9 then total = 69 + 9 = 78
and total blue = 16 + 4 + 6 = 26
26/78 = 1/3 -----> fits (most likely that B is the ans)

cross check
if x = 12 then total = 81
total blue = 28
28/81 != 1/3 hence (B)
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New post 13 Jun 2017, 04:45
manlog wrote:
I have approximated 10.8% as 1/9, which is 11.1%


10.8% of 37 -> 10% of 37 = 3.7.

3.7 is a little low and the number of balls must be an integer; can round up to 4.
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 19 Dec 2017, 07:42
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Bunuel wrote:
Image
If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Attachment:
2016-06-17_1618.png


We are given a table with the following information:

Bag P has 37 marbles and 10.8% of those marbles are blue. So there are 0.108(37) = 3.996, or 4, blue marbles in bag P.

Bag Q has X marble and 66.7% of those marbles are blue. Recall that the fraction 2/3 is approximately 66.7%, so there are (2/3)X blue marbles in bag Q.

Bag R has 32 marbles and 50% of those marbles are blue. So, there are 0.5(32) = 16 blue marbles in bag R.

We are also given that 1/3 of the total marbles in the 3 bags are blue. Thus, we can create the following equation:

1/3(37 + X + 32) = 4 + (2/3)X + 16

Multiplying the equation by 3, we have:

37 + X + 32 = 12 + 2X + 48

X + 69 = 2X + 60

X = 9

There are 9 marbles in bag Q.

Answer: B
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 22 Apr 2018, 10:44
Bunuel wrote:
Image
If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Attachment:
2016-06-17_1618.png

No. of blue marbles in each bag is
Bag P: 10.8% of 37 = 4
Bag Q:66.7% of X = 2/3 X
Bag R: 50% of 32 = 16

Total Blue marbles = 4 + 2/3 X + 16 = 20 + 2/3 X

Also Total marbles count = 37 + X + 32 = 69 + X

So, 1/3 (69+ X ) = 20 + 2/3 X
23 + 1/3 X = 20 + 2/3 X
1/3 X = 3
X = 9

Answer B
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New post Updated on: 29 Apr 2018, 03:17
many thanks generis and niks18

yeah working with fractions is easier , also good to know that \(\frac{2}{3}\)= 66% :)

\(4+16+\frac{2}{3}x= \frac{1}{3} (37+32+x)\)

\(20+\frac{2}{3}x = \frac{1}{3}x+23\)

\(\frac{2}{3}x-\frac{1}{3}x = 3\)

\(\frac{1}{3}x =3\)

\(x =9\)


have a great weekend :-)

Originally posted by dave13 on 28 Apr 2018, 06:41.
Last edited by dave13 on 29 Apr 2018, 03:17, edited 1 time in total.
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 28 Apr 2018, 07:20
dave13 wrote:
Bunuel wrote:
Image
If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Attachment:
2016-06-17_1618.png


generis, niks18, pushpitkc, hello :)

here is my unique solution :) two solutions one is incorrect and next one seems more accurate :) unfortunately i cant solve 700 level q under 2 min, takes me more time befire i figure out how the problem can be approached :)

\(4+16+0.67x= \frac{1}{3} (37+32+x)\)

\(20+0.67x =\frac{1}{3}x+23\)

\(20-23 = \frac{1}{3}x-\frac{67}{100}\)

\(-3 = \frac{33}{300}x\)

\(-3 = \frac{11}{100}x\)

the above solution is incorrect, i kept 1/3 as fraction, so i wonder what did i do wrong

in the next solution I converted 1/3 to decimal = 0.33%

\(4+16+0.67x=0.33 (37+32+x)\)

\(20+0.67x = 0.33x+23\)

\(0.67x - 0.33x = 23-20\)

\(3 = 0.34x\)

\(x = 8.8\)

round to the tenth \(8.8\) and get \(9\) :)

have a great weekend :-)


hi dave13

Pls check the calculations in the highlighted part above. How come 37+32 become 23? and when you are opening the bracket then each element of the bracket has to be multiplied by 1/3 or 0.33
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New post 28 Apr 2018, 07:30
niks18 wrote:
dave13 wrote:
Bunuel wrote:
Image
If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Attachment:
2016-06-17_1618.png


generis, niks18, pushpitkc, hello :)

here is my unique solution :) two solutions one is incorrect and next one seems more accurate :) unfortunately i cant solve 700 level q under 2 min, takes me more time befire i figure out how the problem can be approached :)

\(4+16+0.67x= \frac{1}{3} (37+32+x)\)

\(20+0.67x =\frac{1}{3}x+23\)

\(20-23 = \frac{1}{3}x-\frac{67}{100}\)

\(-3 = \frac{33}{300}x\)

\(-3 = \frac{11}{100}x\)

the above solution is incorrect, i kept 1/3 as fraction, so i wonder what did i do wrong

in the next solution I converted 1/3 to decimal = 0.33%

\(4+16+0.67x=0.33 (37+32+x)\)

\(20+0.67x = 0.33x+23\)

\(0.67x - 0.33x = 23-20\)

\(3 = 0.34x\)

\(x = 8.8\)

round to the tenth \(8.8\) and get \(9\) :)

have a great weekend :-)


hi dave13

Pls check the calculations in the highlighted part above. How come 37+32 become 23? and when you are opening the bracket then each element of the bracket has to be multiplied by 1/3 or 0.33


niks18, hello there :)

to answer your question - How come 37+32 become 23?

\(37+32 =69\) so\(\frac{1}{3}*69 =23\) so I get \(23+0,33x\) :)

\(20+0.67x = 0.33x+23\)

isnt it correct ? :?
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If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 28 Apr 2018, 07:34
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dave13 wrote:
Bunuel wrote:
Image
If 1/3 of the total number of marbles in the three bags listed in the table above are blue, how many marbles are there in bag Q?

A) 5
B) 9
C) 12
D) 23
E) 46

Attachment:
2016-06-17_1618.png

generis, niks18, pushpitkc, hello :)

here is my unique solution :) two solutions one is incorrect and next one seems more accurate :) unfortunately i cant solve 700 level q under 2 min, takes me more time befire i figure out how the problem can be approached :)

\(4+16+0.67x= \frac{1}{3} (37+32+x)\)

\(20+0.67x = \frac{1}{3}x+23\)

\(20-23 = \frac{1}{3}x-\frac{67}{100}\)

\(-3 = \frac{33}{300}x\)

\(-3 = \frac{11}{100}x\)

the above solution is incorrect, i kept 1/3 as fraction, so i wonder what did i do wrong


dave13
The equation is correct. The arithmetic is off.

(EDIT As niks18 points out), check your math here:
Quote:
\(20-23 = \frac{1}{3}x-\frac{67}{100}\)

\(-3 = \frac{33}{300}x\)

Try using \(\frac{67}{100}=\frac{2}{3}\)

\(\frac{1}{3}x - \frac{2}{3}x\) = ????

Calculate again and see what you get.

Tip: use fractions with fractions and decimals with decimals. IMO fractions are easier.

Another way to think about setup and solving of the equation . . . (I do not know whether either suggestion will be easier for you - they're just possibilities)

After you replace \(.67\) with \(\frac{2}{3}\)

Change the setup and cross multiply.

(1) Setup: If blue marbles equal \(\frac{1}{3}\) of three bags' total marbles:
\(\frac{Blue}{Total}=\frac{1}{3}\)
\(\frac{16+4+\frac{2}{3}x}{37+32+x}=\frac{1}{3}\)

(2) Solve. Cross multiply.

Just one arithmetic mistake, in other words.

Your second solution is correct. If you use decimals (IMO, harder here!) what you calculated is correct.

Hope that helps.
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Re: If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 28 Apr 2018, 07:37
1
dave13 wrote:
niks18 wrote:
dave13 wrote:
generis, niks18, pushpitkc, hello :)

here is my unique solution :) two solutions one is incorrect and next one seems more accurate :) unfortunately i cant solve 700 level q under 2 min, takes me more time befire i figure out how the problem can be approached :)

\(4+16+0.67x= \frac{1}{3} (37+32+x)\)

\(20+0.67x =\frac{1}{3}x+23\)

\(20-23 = \frac{1}{3}x-\frac{67}{100}\)

\(-3 = \frac{33}{300}x\)

\(-3 = \frac{11}{100}x\)


the above solution is incorrect, i kept 1/3 as fraction, so i wonder what did i do wrong

in the next solution I converted 1/3 to decimal = 0.33%

\(4+16+0.67x=0.33 (37+32+x)\)

\(20+0.67x = 0.33x+23\)

\(0.67x - 0.33x = 23-20\)

\(3 = 0.34x\)

\(x = 8.8\)

round to the tenth \(8.8\) and get \(9\) :)

have a great weekend :-)


hi dave13

Pls check the calculations in the highlighted part above. How come 37+32 become 23? and when you are opening the bracket then each element of the bracket has to be multiplied by 1/3 or 0.33


niks18, hello there :)

to answer your question - How come 37+32 become 23?

\(37+32 =69\) so\(\frac{1}{3}*69 =23\) so I get \(23+0,33x\) :)

\(20+0.67x = 0.33x+23\)

isnt it correct ? :?


hi dave13
yes its correct. :thumbup: my mistake I got confused here. So in your method 1 the mistake is in highlighted part above. kindly check your calculation of 1/3x-67x/100. Rest is ok
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If 1/3 of the total number of marbles in the three bags listed in the  [#permalink]

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New post 20 Sep 2018, 20:24
If we let \(x\) be the number of marbles in Bag \(Q\),

To start, the total of number of marbles in the three bags is \((37+ 32+ x) = 69 + x\) marbles.

Next, we need to find the number of blue marbles in the 3 bags. To do so, we multiply each percentage by the number of marbles in each bag (converting each percentage to decimal as needed):

The number of blue marbles present in each bag would be:

Bag P: \(0.108 \times 37 =3.996\) or \(4\) since we want the nearest whole number marbles
Bag R:\(0.50 \times 32 =\)\(16\) marbles
Bag Q:\(0.667(x) = 0.667x\) marbles or \(\frac{2x}{3}\) marbles (Note that 0.667 is equivalent to 2/3 in fractions)

The prompt states that \(\frac{1}{3}\) of the total marbles equals the total number of blue marbles. We can now form the equation below.

1/3 x Total Number of Marbles = Total Number of Blue Marbles

\(1/3 (69 + x) = (4 + 16 + 2x/3)\)
Distribute \(\frac{1}{3}\) into the parenthesis,
\(23 + \frac{x}{3} = 20 + \frac{2x}{3}\)
\(23 – 20= \frac{2x}{3} – \frac{x}{3}\)
\(3 = \frac{x}{3}\)
\(x = 3(3) = 9\)

Hence, there are 9 marbles in Bag Q. The final answer is .
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If 1/3 of the total number of marbles in the three bags listed in the   [#permalink] 20 Sep 2018, 20:24
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