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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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11 Nov 2008, 16:28
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 1/a+ 1/8 B. 1/8  1/a C. 1/8a D. 3/7(8 – a) E. 9/49 (8 – a)
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Last edited by Bunuel on 05 Oct 2013, 04:59, edited 1 time in total.
Edited the question, added the OA and moved to PS forum.



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11 Nov 2008, 18:01
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gorden wrote: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=
A. 1/a+ 1/8 B. 1/8  1/a C. 1/8a D. 3/7(8 – a) E. 9/49 (8 – a) E. assuming that the original eqn (7x/3) + a = 8 7x + 3a = 24 7x = 24 3a x = (24  3a )/7 = 3(8 a)/7 i.e 3x/7 = 9(8a)/49



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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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05 Oct 2013, 04:29
Hi,
Can anyone help me with this one. I got stuck at  x=(243a)/7 => x= 3(8a)/7
how do we get to 3x/7 ?



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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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05 Oct 2013, 05:03
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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30 Nov 2014, 16:15
Exercise raises 7x/3 + a = 8 and a > 8
And express 3x/7 according to request.
One suggestion is to form 3x/7, from equal 7x/3 + a = 8
In the last ogualdad, clearing 7x/3, is:
7x/3 = 8  a
Here we can form in the ladi left 3x/7 equality, simply multiply the ogualdad by 9/49, so must
(9/49)(7x/3) = (9/49) (8  a)
Simplifying on the left side of the equality is:
7x/3 = (9/49) (8  a)
It is requested.
Answer E
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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30 Nov 2014, 22:18
gorden wrote: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=
A. 1/a+ 1/8 B. 1/8  1/a C. 1/8a D. 3/7(8 – a) E. 9/49 (8 – a) What's the need to specifically say a > 8 ? Would it make any difference?
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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30 Jan 2015, 23:17
Bunuel wrote: Mansi12 wrote: Hi,
Can anyone help me with this one. I got stuck at  x=(243a)/7 => x= 3(8a)/7
how do we get to 3x/7 ? If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 1/a+ 1/8 B. 1/8  1/a C. 1/8a D. 3/7(8 – a) E. 9/49 (8 – a) \(\frac{7x}{3} + a = 8\) > \(\frac{7x}{3}= 8a\). Now, multiply both sides by \(\frac{3}{7}*\frac{3}{7}\) in order to get \(\frac{3x}{7}\) on the LHS: \(\frac{3}{7}*\frac{3}{7}*\frac{7x}{3}=\frac{3}{7}*\frac{3}{7}( 8a)\). \(\frac{3}{7}*x=\frac{9}{49}( 8a)\). Answer: E. Hope it helps. Hi,
Thank you.
After 7x/3 = 8  a, why can we not take the reciprocal of both sides?
TO



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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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31 Jan 2015, 04:28
thorinoakenshield wrote: Bunuel wrote: Mansi12 wrote: Hi,
Can anyone help me with this one. I got stuck at  x=(243a)/7 => x= 3(8a)/7
how do we get to 3x/7 ? If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 1/a+ 1/8 B. 1/8  1/a C. 1/8a D. 3/7(8 – a) E. 9/49 (8 – a) \(\frac{7x}{3} + a = 8\) > \(\frac{7x}{3}= 8a\). Now, multiply both sides by \(\frac{3}{7}*\frac{3}{7}\) in order to get \(\frac{3x}{7}\) on the LHS: \(\frac{3}{7}*\frac{3}{7}*\frac{7x}{3}=\frac{3}{7}*\frac{3}{7}( 8a)\). \(\frac{3}{7}*x=\frac{9}{49}( 8a)\). Answer: E. Hope it helps. Hi,
Thank you.
After 7x/3 = 8  a, why can we not take the reciprocal of both sides?
TOYou mean why don't we write 3/(7x) = 1/(8a) ? What does it give?
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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31 Jan 2015, 13:01
Hi All, This question can be solved by TESTing VALUES, although it does come with a "twist" that will require that you think about which type of values would make the math easy to deal with. We're told that 7X/3 + A = 8 and that A > 8. We're asked for the value of 3X/7. Since A > 8......7X/3 will have to be NEGATIVE. To eliminate the fraction, I'm going to TEST... X = 3 7(3)/3 = 7 7 + A = 8 A = 15 So, with X = 3 and A = 15, the answer to the question is 3(3)/7 = 9/7 Answer A: 1/15 + 1/8 is positive. NOT a match Answer B: 1/8  1/15 is positive. NOT a match Answer C: 1/8  15 is TOO negative. NOT a match Answer D: (3/7)(815) = (3/7)(7) = 3 NOT a match Answer E: (9/49)(815) = (9/49)(7) = 9/7 This IS a MATCH Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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31 Jan 2015, 15:47
Hi,
Thank you.
After 7x/3 = 8  a, why can we not take the reciprocal of both sides?
TO
Bunuel: You mean why don't we write 3/(7x) = 1/(8a) ? What does it give?
Yes. Will this be mathematically illegal? I am sorry if the question sounds very basic.
TO



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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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01 Feb 2015, 03:17



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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. [#permalink]
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15 Nov 2017, 10:54
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Please spend some time to write the answer choices correctly. 9/49 (8 – a) can be misread as \(\frac{9}{49(8a)}\) and is not the same as \(\frac{9}{49} * (8a)\).
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A.
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