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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A.
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30 Nov 2014, 16:15
Exercise raises 7x/3 + a = 8 and a > 8
And express 3x/7 according to request.
One suggestion is to form 3x/7, from equal 7x/3 + a = 8
In the last ogualdad, clearing 7x/3, is:
7x/3 = 8 - a
Here we can form in the ladi left 3x/7 equality, simply multiply the ogualdad by 9/49, so must
(9/49)(7x/3) = (9/49) (8 - a)
Simplifying on the left side of the equality is:
7x/3 = (9/49) (8 - a)
It is requested.
Answer E
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Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A.
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31 Jan 2015, 13:01
1
Hi All,
This question can be solved by TESTing VALUES, although it does come with a "twist" that will require that you think about which type of values would make the math easy to deal with.
We're told that 7X/3 + A = 8 and that A > 8. We're asked for the value of 3X/7.
Since A > 8......7X/3 will have to be NEGATIVE.
To eliminate the fraction, I'm going to TEST... X = -3
7(-3)/3 = -7 -7 + A = 8 A = 15
So, with X = -3 and A = 15, the answer to the question is 3(-3)/7 = -9/7
Answer A: 1/15 + 1/8 is positive. NOT a match Answer B: 1/8 - 1/15 is positive. NOT a match Answer C: 1/8 - 15 is TOO negative. NOT a match Answer D: (3/7)(8-15) = (3/7)(-7) = -3 NOT a match Answer E: (9/49)(8-15) = (9/49)(-7) = -9/7 This IS a MATCH
Re: If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A.
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01 Feb 2015, 03:17
thorinoakenshield wrote:
Hi,
Thank you.
After 7x/3 = 8 - a, why can we not take the reciprocal of both sides?
TO
Bunuel: You mean why don't we write 3/(7x) = 1/(8-a) ? What does it give?
Yes. Will this be mathematically illegal? I am sorry if the question sounds very basic.
TO
The question asks to find the value of 3x/7 in terms of a, not the value of 3/(7x). You should read questions more carefully. Also, I think you need to brush up fundamentals and only then to attempt questions. Here are the books you might find helpful: best-gmat-math-prep-books-reviews-recommendations-77291.html _________________
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73% (02:04) correct 
