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If a, b, and c are integers and ac + b is odd, is b odd?

Given that \(ac + b=odd\), determine whether b is odd.

(1) ac + ab is even --> \(ac+ab=even\). Subtract this equation from the equation above: \(b-ab=odd-even=odd\) --> \(b(1-a)=odd\) --> \(b=odd\). Sufficient.

(2) b + c is odd. Clearly insufficient.

Answer: A.

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A) ac + ab is even
ac+b+ac+ab=odd+even, 2ac+b(1+a)=odd. The first term will be even so the second term must be odd in order to obtain even+odd=odd.
b(1+a)=odd, since an odd number results from odd*odd, both terms must be odd.
Sufficient

B) b + c is odd
B could be even or odd.
Not sufficient
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If a, b, and c are integers and ac + b is odd, is b odd?

(1) ac + ab is even
(2) b + c is odd

Given:
a, b, and c are integers
ac + b is odd

Asked: Is b odd?

ac + b is odd
=> b is odd and ac is even
or b is even and a & c are odd

(1) ac + ab is even
a (c+b) is even => a is even or c+b is even
If a is even => b is odd
If c+b is even => c & b are even Not feasible
or c & b are odd => b is odd
SUFFICIENT

(2) b + c is odd
b is even and c is odd => a is odd
b is odd and c is even => a may or may not be even
NOT SUFFICIENT

IMO A
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