Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

29 Aug 2013, 12:31

3

This post received KUDOS

12

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

75% (hard)

Question Stats:

54% (01:07) correct 46% (01:16) wrong based on 295 sessions

HideShow timer Statistics

If a certain culture of bacteria increases by a constant factor of x every y minutes, how long will it take for the culture to increase to ten-thousand times its original size?

1. \(x=10^y\) 2.In two minutes, the culture will increase to one hundred times its original size.

Re: If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

29 Aug 2013, 22:44

1

This post was BOOKMARKED

My take:

We need to find y, when xy=10^4.

1) When x=10^y, y*(10^y)=10^4 or could also be written as y = 10^(4-y) By using substitution, we could say y could be between 3 and 4 (~=3.4). Hence st1 is Sufficient ( And Options B,C,&E could be eliminated)

2) (2)*x=100 i.e. x=50. By substituting value of x in xy=10^4, we could find the time taken. Hence st2 is Sufficient

Re: If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

08 Sep 2013, 04:40

3

This post received KUDOS

bagdbmba wrote:

Hi Bunuel, It'd be really helpful if you could provide an explanation for this problem to help me understand it.

Thanks in advance.

Maybe this will help

from 1 we are given x=10^y, let initial quantity be m

So after y minutes the quantity => m*x =>m*10^y , now we need the new value to be 10,000 times the original => m*10^y=m*1000 => y=4 minutes hence statement 1 is sufficient.

from statement 2

In 2 minutes the culture will increase to 100 times this can be interpreted as follows 1) every 1 minute the quantity is multiplied by 10 or 2) every 2 minutes the quantity is multiplied by 100

Either ways after 4 minutes the quantity will be multiplied by 10,000 hence y=4 minutes

Hence statement 2 is sufficient. therefore the answer is D Hope the solution is clear.
_________________

--It's one thing to get defeated, but another to accept it.

If a certain culture of bacteria increases by a factor of x every y minutes, how long will it take for the culture to increase to 10000 times its original amount ? 1) (x)^1/y = 10 2) In 2 minutes the culture will increase to 100 times its original amount.

Please could you explain an how to solve such questions which involves population increasing by certain factors

If a certain culture of bacteria increases by a factor of x every y minutes, how long will it take for the culture to increase to 10000 times its original amount ? 1) (x)^1/y = 10 2) In 2 minutes the culture will increase to 100 times its original amount.

Please could you explain an how to solve such questions which involves population increasing by certain factors

Stem 1 is interesting..

Consider x=10 and y=1...so Initial bacteria (K) will increase by a factor of 10 in 1 minute...so after 1 minute there will be K+10K=11K...so we can find the time it will take for culture to increase to 10000 times

So after 1 minute, we have 11K After 2 minutes, 11K+110K=121K After 3 minutes= 121K+1210K=1331K After 4 minutes...

Consider \(x=\sqrt{10}\), and y =1/2 or 30 seconds, So after 30 seconds, no. of bacteria will increase by \((10^{1/2})^{2}\) or by a factor of 10...in 1 minute it will increase by factor \(\sqrt{10}\) At 0 seconds=K After 30 seconds= K+10K=11K After 1 minute, by a factor\(\sqrt{10}\) so after 1 minute you will have \(11K+\sqrt{10}*11K\)-----> Now here the problem is the increase every y minute is not the same so this case will not be considered...

So St1 is sufficient

St2 is straight forward...

Can you post the Official Explanation to question.
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

If a certain culture of bacteria increases by a factor of x every y minutes, how long will it take for the culture to increase to 10000 times its original amount ? 1) (x)^1/y = 10 2) In 2 minutes the culture will increase to 100 times its original amount.

Please could you explain an how to solve such questions which involves population increasing by certain factors

Merging topics. Please search before posting. Thank you.

Re: If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

24 Jun 2017, 03:17

Hi... Pls throw more light about the 1st statement... i solved it like this... Initial at time=0, let it be P after y min, xP after 2y min, x^2P after ny min, x^nP

from question x^nP = 10000P x^n=10^4 from statement 1, x=10^y 10^(yn)=10^4 yn=10 2 unknown and 1 equation, not sufficient

Re: If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

25 Jun 2017, 10:51

JJSHHShank wrote:

Hi... Pls throw more light about the 1st statement... i solved it like this... Initial at time=0, let it be P after y min, xP after 2y min, x^2P after ny min, x^nP

from question x^nP = 10000P x^n=10^4 from statement 1, x=10^y 10^(yn)=10^4 yn=10 2 unknown and 1 equation, not sufficient

Thanks in advance

keyword is "by a factor of ", is used commonly to mean the same as "multiplied by" or "divided by." If x is INCREASED by a factor of 4, it becomes 4x. If x is DECREASED by a factor of 4, it becomes x/4. The key word is the direction of change i.e. (increased / decreased) by a factor of. so here from both the points, we can derive that every y minute(s) (the number increases/multiplies by a factor of 10) or in case of (2) we straightaway know that at 2 minutes we have 100, so 10^2 = 100 means that the number became 10 at 1 minute and 100 at 2 minutes. Hope it helps

Re: If a certain culture of bacteria increases by a constant [#permalink]

Show Tags

27 Nov 2017, 05:52

bagdbmba wrote:

If a certain culture of bacteria increases by a constant factor of x every y minutes, how long will it take for the culture to increase to ten-thousand times its original size?

1. \(x=10^y\) 2.In two minutes, the culture will increase to one hundred times its original size.

The question asks "how long it will take for the culture to INCREASE to 10.000x its original size". We need to find "y" minutes. 1. x=10ˆy | If 10.000 = 10ˆ4; When x = 10ˆ4; y=4 minutes; Sufficient 2. 2min: x=100 ; 4 minutes: x=10000