olifurlong
If a rectangular region has perimeter \(P\) inches and area \(A\) square inches, is the region square?
(1) \(P = \frac{4}{3}*A\)
(2) \(P = 4\sqrt{A}\)
Let the rectangular region have sides \(x\) and \(y\).
--> \(Perimeter = P = 2(x+y)\)
--> \(Area = A = xy\)
Question: Is \(x = y\) ?(1) \(P = \frac{4}{3}*A\)\(2(x+y) = (\frac{4}{3})xy\)
\(\frac{x+y}{xy} = \frac{4}{6} = \frac{2}{3}\)
\(\frac{1}{x} + \frac{1}{y} = \frac{4}{6} = \frac{2}{3}\)
So we have that the sum of two values equals \(\frac{2}{3}\)
If \(\frac{1}{x} = \frac{1}{y} = \frac{1}{3}\), then the answer is YES
If \(\frac{1}{x} = \frac{1}{6}\) and \(\frac{1}{y} =\frac{3}{6}\), then the answer is NO
Two different answers --> INSUFFICIENT
(2) \(P = 4\sqrt{A}\)\(2(x + y) = 4\sqrt{xy}\)
\(x + y = 2\sqrt{xy}\)
\(x + y - 2\sqrt{xy} = 0\)
\((\sqrt{x} - \sqrt{y})^2 = 0\)
\(\sqrt{x} - \sqrt{y} = 0\)
\(\sqrt{x} = \sqrt{y}\)
\(x = y\)
--> SUFFICIENT
In statement 2; if all we have proved is x=y , then it could be a rhombus too right? Without knowing if the angles are 90 degrees, how can we be certain?