|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
fitzpratik
04 Dec 2018, 06:04
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (01:30) correct
13%
(01:19)
wrong
based on 51
sessions
History
Date
Time
Result
Not Attempted Yet
If distinct numbers x,y, z and p are chosen from the numbers -2,2,1/2,-1/3, what is the largest possible value of the expression :
\(\frac{x^2*y}{(z-p)}\)
A. 26/4
B. 34/5
C. 38/5
D. 48/5
E. 52/5
\(\frac{x^2*y}{(z-p)}\)
A. 26/4
B. 34/5
C. 38/5
D. 48/5
E. 52/5
MayankSingh
Joined: 08 Jan 2018
Last visit: 20 Dec 2024
Posts: 289
Own Kudos:
Given Kudos: 249
Location: India
Concentration: Operations, General Management
Schools: McDonough '25 (A) Marshall '25 (D) Tepper '25 (WA$) Kenan-Flagler '25 (A) ISB '25 (WL) IIMC '25 (A) Owen '26 (A$$$$)
GMAT 1: 640 Q48 V27
GMAT 2: 730 Q51 V38
GPA: 3.9
WE:Project Management (Manufacturing)
Products:
Schools: McDonough '25 (A) Marshall '25 (D) Tepper '25 (WA$) Kenan-Flagler '25 (A) ISB '25 (WL) IIMC '25 (A) Owen '26 (A$$$$)
GMAT 2: 730 Q51 V38
Posts: 289
Kudos:
277
04 Dec 2018, 06:37
Kudos
Bookmarks
fitzpratik
Soln:- Given option to choose- [-2, 2, 1/2, -1/3]
Objective maximise- \(\frac{x^2*y}{(z-p)}\)
=> Maximise x^2*y & minimise (z-p)
Minimum (z-p)= {1/2-1/3}= 5/6
Max x^2*y= (-2)^2*2=8
Req value= 8/(5/6)= 48/5
06 Dec 2018, 03:50
Kudos
Bookmarks
fitzpratik
We have 4 values and 4 distinct unknowns so each will take exactly one value of the 4.
Maximise: \(\frac{x^2*y}{(z-p)}\)
Note that to maximise this, first we need to ensure that overall sign should be positive. Also, the numerator should have as large an absolute value as possible and the denominator should as small an absolute value as possible.
So x and y both should have absolute value of 2. One of them could be -2 and other 2 depending on what sign we get from the denominator.
Now z - p should be as small as possible so z and p should be as close to each other as possible. The distance between 1/2 and - 1/3 will be smallest.
\(\frac{x^2*y}{(z-p)} = \frac{(-2)^2*2}{(1/2 - (-1/3))} = \frac{8}{5/6} = \frac{48}{5}\)
Answer (D)
