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If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?

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If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 19 Feb 2015, 12:27
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If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


For a set of challenging problems on exponent, as well as the OA to this particular question, see:
https://magoosh.com/gmat/2014/challengi ... and-roots/

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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 19 Feb 2015, 14:16
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\(K^{3/2} = 1.5 * K^{5/4}\)
\(K^{6/4} = {3/2} * K^{5/4}\)

\(\frac{K^{6/4}}{K^{5/4}}\) = \({3/2}\)

\(K ^{1/4} = {3/2}\)
\(K = ({3/2})^4\)
\(K = {81/16}\)

The correct answer is E.
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 11 Mar 2015, 22:12
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150 is 50% bigger than 100

\(k^{\frac{3}{2}}\) is 50% bigger than \(k^{\frac{5}{4}}\)

Setting up the equation:

\(k^{\frac{5}{4}} * 150 = 100 * k^{\frac{3}{2}}\)

\(k^{\frac{6}{4} - \frac{5}{4}} = \frac{3}{2}\)

\(k = (\frac{3}{2})^4 = \frac{81}{16}\)

Answer = E
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 02 Jul 2017, 22:11
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\(K^\frac{3}{2}\) = \(1.5* K^\frac{5}{4}\)
\(K^\frac{3}{2}/K^\frac{5}{4}\) = \(\frac{3}{2}\)
\(K^\frac{3}{2}-^\frac{5}{4}\) = \(\frac{3}{2}\)
\(K^\frac{1}{4}\) =\(\frac{3}{2}\)
So, K=\(\frac{81}{16}\)
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 24 Jul 2017, 09:54
Hi,

Is it wrong to consider k^5/4 as K^1? (can we do numerator - denominator for the exponents?)
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 24 Jul 2017, 10:13
ameyaprabhu wrote:
Hi,

Is it wrong to consider k^5/4 as K^1? (can we do numerator - denominator for the exponents?)

Dear ameyaprabhu,

I'm happy to respond. :-)

My friend, I do not understand your question. Are you asking how to make a fraction appear as an exponent using the LaTex math font? Are you asking what it means to have a fraction in the exponent? I don't know whether you are asking a purely mathematical question or whether you are asking a question about this site. Please clarify.

I will also recommend this blog:
Asking Excellent Questions

Mike :-)
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 24 Jul 2017, 10:35
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mikemcgarry wrote:
If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


For a set of challenging problems on exponent, as well as the OA to this particular question, see:
https://magoosh.com/gmat/2014/challengi ... and-roots/


\(k^{3/2} = 1.5(k^{5/4})\)

\(k^{{\frac{3}{2}} - {\frac{5}{4}}} = 1.5\)

\(\frac{3}{2} - \frac{5}{4} = \frac{12-10}{8} = \frac{1}{4}\)

\(k^{1/4} = 1.5\)

\(k = (1.5)^4 = (\frac{3}{2})^4 = \frac{81}{16}\). Ans - E.
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 24 Jul 2017, 17:48
Hi Mike,

While I know K^m/n = nth root of k raised to m, my doubt was more fundamental, in that, I was wondering whether we can simplify the expression do K^(m-n). eg. k^5/4 simply becomes K (but doing so doesn't seem to work for this problem and hence I was questioning my basics)
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 24 Jul 2017, 18:24
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ameyaprabhu wrote:
Hi Mike,

While I know K^m/n = nth root of k raised to m, my doubt was more fundamental, in that, I was wondering whether we can simplify the expression do K^(m-n). eg. k^5/4 simply becomes K (but doing so doesn't seem to work for this problem and hence I was questioning my basics)


Hi,

Remember the fraction rule: \(\frac{a^{m}}{a^{n}} = a^{m-n}\).

Here we have \(k^{m}/k^{n}\), where \(m = 3/2\), and \(n = 5/4\), so we get \(k^{m-n} = k^{3/2 - 5/4} = k^{1/4}\). If it was \(k^5/k^4\), that would be equal to \(k^{5-4} = k^1\). Hope you see the difference.
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 22 Jul 2018, 08:31
mikemcgarry wrote:
If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


For a set of challenging problems on exponent, as well as the OA to this particular question, see:
https://magoosh.com/gmat/2014/challengi ... and-roots/


The expression is:

K^(3/2)=1.5xK^(5/4)

Squaring both sides, we get:
K^3=(1.5)^2 x K^(5/2)

Squaring again,

K^6=(1.5)^4 x K^5

Simplifying the powers of K,

K= (1.5)^4

that gives, K=81/16 on expanding above as fraction.

Answer: E

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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K?  [#permalink]

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New post 22 Jul 2018, 08:37
E.
As k^3/2=1.5*k^5/4
k^6/4-5/4=1.5
k^1/4=1.5 i.e. 3/2
k= 81/16
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Re: If K^(3/2) is 50% bigger than k^(5/4), what is the value of K? &nbs [#permalink] 22 Jul 2018, 08:37
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