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22 Aug 2003, 22:46
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If N is an integer ,and N^2 is divisible by 72, what is the largest integer that MUST divide N is ?
1.6
2.12
3.24
4.36
5.48
An explanation for the answer would be very helpful.
Thanks
Praetorian
1.6
2.12
3.24
4.36
5.48
An explanation for the answer would be very helpful.
Thanks
Praetorian
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22 Aug 2003, 22:59
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AkamaiBrah
praetorian123
If N is an integer ,and N^2 is divisible by 72, what is the largest integer that MUST divide N is ?
1.6
2.12
3.24
4.36
5.48
An explanation for the answer would be very helpful.
Thanks
Praetorian
1.6
2.12
3.24
4.36
5.48
An explanation for the answer would be very helpful.
Thanks
Praetorian
Is the answer 12?
Yes, the answer is 12, i would be very grateful if you can explain.
23 Aug 2003, 03:16
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72=(2^2)*(3^2)*2
N^2=x*72=x*(2^2)*(3^2)*2, x integer... N integer, so x=2*y^2, y integer... N=2*3*2*y, y integer... the largest number that MUST divide N is 2*3*2=12
N^2=x*72=x*(2^2)*(3^2)*2, x integer... N integer, so x=2*y^2, y integer... N=2*3*2*y, y integer... the largest number that MUST divide N is 2*3*2=12
