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If Rebeca drives to work at x mph she will be one minute late, but if [#permalink]
Expert Reply
To make the math easier, we can replace the given values with rounder numbers, as follows:

fskilnik@GMATH wrote:
GMATH practice exercise (Quant Class 19)

If Rebeca drives to work at x mph she will be one hour late, but if she drives at y mph she will be one hour early. How far (in miles) does Rebeca drive to work?

(1) x and y differ by 10 miles per hour.
(2) y is 50% greater than x.


Since Rebeca arrives 1 hour late when traveling at the lower speed and 1 hour early when traveling at the higher speed, the time at the lower speed must be 2 hours greater than the time at the higher speed.

Statement 1:
Case 1: x = 10 mph and y = 20 mph
Since the rate ratio = 10:20 = 1:2, the time ratio = 2:1 = 4:2, implying 4 hours at the lower speed and 2 hours at the higher speed.
Since the trip takes 4 hours when traveling at the lower speed of 10 mph, the distance = 10*4 = 40 miles.

Case 2: x = 20 mph and y = 30 mph
Since the rate ratio = 20:30 = 2:3, the time ratio = 3:2 = 6:4, implying 6 hours at the lower speed and 4 hours at the higher speed.
Since the trip takes 6 hours when traveling at the lower speed of 20 mph, the distance = 20*6 = 120 miles.

Since the distance can be different values, INSUFFICIENT.

Statement 2:
Case 2 also satisfies Statement 2.
In Case 2, the distance = 120 miles.

Case 3: x = 2 mph and y = 3 mph
Since the rate ratio = 2:3, the time ratio = 3:2 = 6:4, implying 6 hours at the lower speed and 4 hours at the higher speed.
Since the trip takes 6 hours when traveling at the lower speed of 2 mph, the distance = 2*6 = 12 miles.

Since the distance can be different values, INSUFFICIENT.

Statements combined:
Only Case 2 satisfies both statements.
In Case 2, the distance = 120 miles.
SUFFICIENT.


Originally posted by GMATGuruNY on 14 Feb 2019, 20:49.
Last edited by GMATGuruNY on 15 Feb 2019, 05:54, edited 1 time in total.
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Re: If Rebeca drives to work at x mph she will be one minute late, but if [#permalink]
Took 3 minutes.

Rephrase---> x(t+1/60) = d and y(t-1/60)=d
(x-y)t = -1/60(x+y)
SO we need x y and t to find d the distance.

1. Insufficient as x-y = 7 does not solve the rephrased stem.
2. 1.1x=y gives a ratio. No info on time insuficient.
C----> 1.1x= y . Substituting in stem, we get t = 21/60.
This way we can find x and y as well. D can be found out. Sufficient.
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Re: If Rebeca drives to work at x mph she will be one minute late, but if [#permalink]
Expert Reply
Hi there, chetan2u and GMATGuruNY !

Thanks for your comments on improving the "calculations-related" issue.

We all know that Data Sufficiency is related to the uniqueness (and viability) of potential answers, but "friendly numbers" (as called by Chetan) are always welcomed.

Regards,
Fabio.
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Re: If Rebeca drives to work at x mph she will be one minute late, but if [#permalink]
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