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Re: Median negative??
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25 May 2013, 07:45
sudiptak wrote: nitishmahajan wrote: arvs212 wrote: If set S consists of even number of integers, is the median of set S negative?
1)Exactly half of all elements of set S are positive. 2)The largest negative element of set S is 1.
Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient
plzzz give answers with explanations...thnx IMO E, 1. Is Insuff, as it doesn't tell anything about ve no. ( I mean the range or values) 2. Is also insuff. Lets combine 1 & 2. Lets consider an example here. S = ( 3, 2, 1, 1, 2, 3) ( as we know from st 2. that Largest ve no. is 1 ) In this case the median is 0 and now consider S= ( 3, 2, 1, 2, 3, 4) In this case Median is 1/2 and when S= ( 3, 2, 1, 0, 3, 4) Median = 1/2 Hence 1 & 2 combined also is insuff. Please post OA also. and when S= ( 3, 2, 1, 0, 3, 4) Median = 1/2 this case will not arse when we are comibining stmnt 1 &2 cos, one says half of the numbers are positive. so we can not have the "0" there. so, 1&2 gives the ans. hence C. If we take a set as S: {3,2,1,0,1,2,3,4}.,this contains exactly half +ve integers and the greatest ve integer in 1 ., the median is positive..i.e., (0+1)/2=1/2 And if we consider the set S: {3,2,1,1,2,3}.,this contains exactly half +ve integers and the greatest ve integer is 1.,the median is neither negative nor positive..i.e.,(1+1)/2=0 HEnce the answer should be E..as both answers when combined also didnt provide the solution..



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Re: If set S consists of even number of integers, is the median
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25 May 2013, 07:56
VyshnaviV wrote: If we take a set as S: {3,2,1,0,1,2,3,4}.,this contains exactly half +ve integers and the greatest ve integer in 1 ., the median is positive..i.e., (0+1)/2=1/2 And if we consider the set S: {3,2,1,1,2,3}.,this contains exactly half +ve integers and the greatest ve integer is 1.,the median is neither negative nor positive..i.e.,(1+1)/2=0 HEnce the answer should be E..as both answers when combined also didnt provide the solution.. The question asks whether the median is negative. In both cases you got that the median is NOT negative. Hence when taken together the statements are sufficient to give a definite NO answer to the question. The correct answer is C, not E. Complete solution: ifsetsconsistsofevennumberofintegersisthemedian1434320.html#p1097147Hope it helps.
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Re: If set S consists of even number of integers, is the median
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10 Oct 2014, 23:24
Bunuel, Set 1: 1, 4, 1, 1 Median= 3/2 (exactly half positive integers, and 1 is the highest ve integer) Set 2: 1, 0, 2, 3 Median = 1 (+ve) Shouldn't the solution be E? Bunuel wrote: rlevochkin wrote: mirhaque wrote: SEE ATTACHED E. St. (1) insufficient as we should not forget "0", which is neither positive nor negative. sets can be {1, 1, 0, 2}, the mean is .5, which is negative, or {1,0,2,4} the mean is 1 which is positive. St. (2) is also, insufficient, since the set can look like {1, 0}, the median is the middle number between 1 and 0, which is .5, so negative, ot it can be {1,0, 4,4} with median 2, which is positive putting statements (1) and (2) together does not provide any additional information that can be considered, so Ans. is E. Not so. If set S consists of even number of integers, is the median of set S negative?Set consists of even number of integers > median=sum of two middle integers/2 (1) Exactly half of all elements of set S are positive > either all other are negative or all but one, which at this case must be 0. Not sufficient. (2) The largest negative element of set S is 1 > not sufficient (1)+(2) half positive, biggest negative 1 > median is either (0 + positive)/2=positive (so not negative) or (1 + at least smallest positive integer, which is 1)/2=0 (min value of median in this case) also not negative. Q was is the median negative answer NO. SUFFICIENT Answer C



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Re: If set S consists of even number of integers, is the median
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11 Oct 2014, 04:06
ApoorvaRed9 wrote: Bunuel,
Set 1: 1, 4, 1, 1 Median= 3/2 (exactly half positive integers, and 1 is the highest ve integer)
Set 2: 1, 0, 2, 3 Median = 1 (+ve)
Shouldn't the solution be E?
The median of a set with even terms is the average of two middle terms when arranged in ascending/descending order. So, the median of {4, 1, 1, 1} is (1 + 1)/2 = 0, not 3/2.
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Re: If set S consists of even number of integers, is the median
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03 Aug 2018, 08:43
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