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If the function Q is defined by the formula Q = 5w/(4x(z^2))

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If the function Q is defined by the formula Q = 5w/(4x(z^2))  [#permalink]

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Updated on: 11 Dec 2012, 02:00
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25% (medium)

Question Stats:

72% (01:42) correct 28% (02:29) wrong based on 238 sessions

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If the function Q is defined by the formula Q = 5w/(4x(z^2)) , by what factor will Q be multiplied if w is quadrupled, x is doubled, and z is tripled?

A. 1/9
B. 2/9
C. 4/9
D. 3/9
E. 2/27

Originally posted by olivite on 04 Jun 2011, 12:33.
Last edited by Bunuel on 11 Dec 2012, 02:00, edited 3 times in total.
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Re: Direct and inverse proportionality  [#permalink]

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04 Jun 2011, 19:09
1
IN the expression Q=5w/4xz^2, substitute the values as mentioned :

So new expression is -> 5 * (4w)/(4 * (2x) * (3z)^2)

= 5 * w/(2x * 9 * z^2)

= (2/9) * 5w/4xz^2

= 2/9 * Q

So Q will be multiplied by the factor 2/9.
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Re: Direct and inverse proportionality  [#permalink]

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06 Jun 2011, 01:34
According to expression Q= 5w/4xz²
now, w'=4w,
x'=2x
z'=3z
Put these values in a same order, we get
Q'= 5(4w)/4(2x)(3z)²
Q'=5w/18xz²
Q'=2/9*(5w/4xz²)
So, Q'= 2/9(Q),q will be a multiple of factor 2/9.
This is the most effective way to solve such question.
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Re: Direct and inverse proportionality  [#permalink]

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11 Jun 2011, 17:32
$$Q = 5W/(4XZ^2)$$

Q1 = $$5(2W)/(4(2X)9X^2)$$ = 2/9 Q

So the factor is 2/9.
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Re: Direct and inverse proportionality  [#permalink]

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22 Feb 2012, 23:49
Hi guys,

I am sorry, but i still did not get this part.

Q'=5w/18xz²
to
Q'=2/9*(5w/4xz²)

Would anyone be able please to elaborate on it? I would really appreciate it.

Serge.
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Re: Direct and inverse proportionality  [#permalink]

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23 Feb 2012, 00:08
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1
SergeNew wrote:
Hi guys,

I am sorry, but i still did not get this part.

Q'=5w/18xz²
to
Q'=2/9*(5w/4xz²)

Would anyone be able please to elaborate on it? I would really appreciate it.

Serge.

If the function Q is defined by the formula Q = 5w/(4x(z^2)), by what factor will Q be multiplied if w is quadrupled, x is doubled, and z is tripled?
A. 1/9
B. 2/9
C. 4/9
D. 3/9
E. 2/27

Given: $$Q=\frac{5w}{4x*z^2}$$.

Now, quadruple $$w$$, so make it $$4w$$; double $$x$$ so make it $$2x$$; triple $$z$$ and substitute these values instead of $$x$$, $$y$$, and $$z$$ in the original equation:

$$\frac{5(4w)}{4(2x)*(3z)^2}=\frac{4*5w}{4*2x*9*z^2}=\frac{4*5w}{18*(4x*z^2)}=\frac{4}{18}*\frac{5w}{4x*z^2}=\frac{2}{9}*\frac{5w}{4x*z^2}$$. Thus Q is multiplied by $$\frac{2}{9}$$.

Else plug-in values for $$x$$, $$y$$, and $$z$$. Let $$x=y=z=1$$ --> $$Q=\frac{5w}{4x*z^2}=\frac{5}{4}$$.

$$4w=4$$, $$2x=2$$ and $$3z=3$$ --> $$\frac{5*4}{4*2*3^2}=\frac{4}{18}*\frac{5}{4}=\frac{2}{9}*\frac{5}{4}$$. Thus Q is multiplied by $$\frac{2}{9}$$.

Hope it's clear.
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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2))  [#permalink]

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10 Dec 2012, 22:16
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$$Q=\frac{{5w}}{{4xz^2}}$$

$$Qmod=\frac{{5(4w)}}{{4(2x)(3z)^2}}$$
$$Qmod=\frac{{20w)}}{{72xz^2}}$$
$$Qmod=\frac{4}{18}*\frac{{5w}}{{4xz^2}}$$
$$Qmod=\frac{4}{18}*Q$$
$$Qmod=\frac{2}{9}*Q$$

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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2))  [#permalink]

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20 Dec 2012, 15:20
Isn't the tag wrong. It doesnt seem like a 700-level question
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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2))  [#permalink]

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25 Feb 2019, 10:34
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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2))   [#permalink] 25 Feb 2019, 10:34
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