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If the number 12341234B1234A, in which A and B represent digits, is di
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18 Mar 2015, 22:54
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If the number 12341234B1234A, in which A and B represent digits, is divisible by 6, then what is the maximum value of A−B? a) 9 b) 8 c) 7 d) 6 e) 5
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If the number 12341234B1234A, in which A and B represent digits, is di
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18 Mar 2015, 23:32
All number should be divisible by 3 and 2. We can see that sum of digits without A and B is already divisible by 3, so we should care that sum of A and B is divisible by 3
We should highest/lowest A  lowest/highest B. Maximum possibility is 9, so let's start testing from it
Picking: A=0 and B=9, it is divisible by 2 (because even) and divisible by 3 (sum is divisible by 3)
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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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23 Dec 2015, 18:29
tricky one, as I tried to make some assumptions which were way too unnecessary. clearly if A=0, then the number is divisible by 2. to be divisible by 3, B can be 0, 3, 6, 9. maximum value of B is 9, so 09=9. note that A can't be 9, because in this case, the number would not be divisible by 2, and thus, not divisible by 6. good question.



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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29 Sep 2016, 13:39
Bunuel VeritasPrepKarishmaWhere am I going wrong? a+b+30 should be divisible by 6. This means a+b should be divisible by 6. So, possibilities of a+b can be 6,12,18 Max difference between a and b can be (60) = 6 Please assist.



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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06 Oct 2016, 23:53
chetan2u Can you please help me with the above query ^^ Thank you in advance.



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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07 Oct 2016, 08:14
Keats wrote: chetan2u Can you please help me with the above query ^^ Thank you in advance. Hi a+b+30 is div by 6... Where you are going wrong is that a+b+30 should be div by 3... So a+b can be 9, 12, 15 ,18 etc.. But we are looking at ab.... Since a and b are single digit number, ab can be max 9.... if we take a as 0, the number 1234...... will be EVEN and then b can take max value of 9 and still be div by 3.. A number div by 2 and 3 will be div by 6.. So ab=09=9 A
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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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04 Nov 2016, 10:11



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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29 Jul 2018, 09:46
Three times sum of 1+2+3+4 =10*3=30 Now, the expression becomes 30+A+B.What we want is a number divisible by 6( which as per divisibility rule should be divisible by both 2 and 3), ending with an even number or zero. So, by hit and trial our number can be 30+0+9= 39 Hence, 90 = 9. It can be maximum difference.Hence A.



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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31 Jul 2018, 10:54
If number divisible by 6 Sum of digits divisible by 3 and should be even.
1+2+3+... A + B should be divisible by 3
A+B should be divisible by 3
and B is even.
Max AB 
B is 0 A is 9 Answer should be 9
A is Answer



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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08 Aug 2018, 03:15
ynaikavde wrote: If the number 12341234B1234A, in which A and B represent digits, is divisible by 6, then what is the maximum value of A−B?
a) 9 b) 8 c) 7 d) 6 e) 5 Responding to a pm: A and B can take values from 0 to 9. We need them to be as far apart as possible so get the maximum value of A  B since absolute values show distance between the two. The maximum distance between them can be 9 (if one of them is 9 and other is 0) and the minimum distance between them would be 0 if both A and B must take the same values. Let's find out. Divisibility by 6  The number would be divisible by both 2 and 3. To be divisible by 2, the number's units digit should be 0/2/4/6/8  value of A To be divisible by 3, the sum of all digits should be divisible by 3. 1+2+3+4+1+2+3+4+1+2+3+4+A+B = 30 + A + B (or we can make groups of multiples of 3 and keep ignoring them) Since 30 is divisible by 3, we need A + B to be divisible by 3 too. If A = 0, B can be 9 which makes A + B divisible by 3. Hence A should be 0 and B should be 9. Answer (A)
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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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06 Oct 2018, 02:00
A lot of people have taken the max value of A as 9, which is incorrect as the last digit needs to be even to be divisible by 2, thus A will be 0 and B will be 9, as posted by Karishma.



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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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23 Jan 2019, 04:50
Solution:Given: The number is 12341234B1234A, in which A and B are digits. To find: The maximum value of A−B? Approach: Here A and B can take the value from 0 to 9 and also the number must be divisible by 6. If the number has to be divisible by 6 it has to be divisible by both ‘2’ and ‘3’ also. Divisibility test for 2: The unit digit has to be an even number i.e.; 0/2/4/6/8. Divisibility test for 3: The sum of the digits of the number must be divisible by 3. Let’s add the digits of the given number: \(1+ 2+3+4+1+2+3+4+B+1+2+3+4+A=30+A+B\) Here we can see that 30 is divisible by “3” therefore “A+B” should be also divisible by “3”. As we need the maximum difference of A−B; let's substitute A = 0 and B = 9; where we get the maximum difference and ‘A + B’ is also divisible by 3. Hence A should be ‘0’ and B should be ‘9’. The correct answer option is B.
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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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27 Jan 2019, 09:52
ynaikavde wrote: If the number 12341234B1234A, in which A and B represent digits, is divisible by 6, then what is the maximum value of A−B?
a) 9 b) 8 c) 7 d) 6 e) 5 A number divisible by 6 must be divisible by the two prime factors of 6, which are 2 and 3. Since 12341234B1234A is divisible by 6, the number must be even (divisible by 2), and the sum of its digits must be a number divisible by 3. Summing the digits, we have 30 + B + A. We know that A must be an even number, so it can be any of 0, 2, 4, 6, 8. Additionally, we want the absolute value of the difference of A and B to be as large as possible. So let’s let A be as small as possible, so A = 0. This means that B must be as large as possible and still satisfy that (30 + A + B) is divisible by 3. So if A = 0, then the largest possible value for B would be 9. Thus, with A = 0 and B = 9, the maximum value of A  B is 9. Answer: A
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Re: If the number 12341234B1234A, in which A and B represent digits, is di
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