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If the smaller of 2 consecutive odd integers is a multiple of 5, which

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If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 26 Apr 2019, 06:24
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A
B
C
D
E

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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 26 Apr 2019, 08:44
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Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


The question asks "which of the following could NOT be the sum of these 2 integers"

So, if we find an answer choice that COULD be the sum of the 2 integers, we can ELIMINATE it.

-5 and -3 are two consecutive odd integers in which the smaller value (-5) is a multiple of 5
(-5) + (-3) = -8
ELIMINATE A

5 and 7 are two consecutive odd integers in which the smaller value (5) is a multiple of 5
5 + 7 = 12
ELIMINATE B

25 and 27 are two consecutive odd integers in which the smaller value (25) is a multiple of 5
25 + 27 = 52
ELIMINATE D

125 and 127 are two consecutive odd integers in which the smaller value (125) is a multiple of 5
125 + 127 = 252
ELIMINATE E

By the process of elimination, the correct answer is C

Cheers,
Brent
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 29 Apr 2019, 08:39
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Since all options are even and numbers are consecutive ,they can be found by dividing the options by two and adding and subtracting one.
For eg -12/2 =6,so numbers are 5 and 7.Since the smaller number is multiple of 5 ,condition is satisfied.
if we look at options one by one beginning with A, A and B satisfy.C does not .No need to check further since time is less.
Ans.C
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 29 Apr 2019, 22:22
if we consider option :
10 & 12 ---

smaller no. is a multiple of 5
Sum = 10+12 = 22

so Ans c seems not correct
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 30 Apr 2019, 05:29
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Our smaller integer is an odd multiple of 5, so is equal to 5x where x is odd. Our numbers are consecutive odd numbers, so the other is 5x+2. Their sum is thus 10x + 2, where x is odd. So if the answer is going to be positive (we can look at answer A later if we need to), the tens digit will be odd (since when we find 10x, we're just sticking a 0 on the end of some odd number), and the units digit will be 2. So we can't possibly get 22 as our answer.
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 01 May 2019, 07:03
kiran1989raj wrote:
if we consider option :
10 & 12 ---

smaller no. is a multiple of 5
Sum = 10+12 = 22

so Ans c seems not correct


Question says smallest odd integer so it should end with 5

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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 01 May 2019, 17:16
Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


PS91602.01
Quantitative Review 2020 NEW QUESTION


Since the two integers are consecutive odd integers, the larger integer is 2 more than the smaller integer.

Let’s consider the answer choices.

Choice A: -5 + -3 = -8. This can work.

Choice B: 5 + 7 = 12. This can work.

Choice C: The only way to get the sum of two integers to be 22 when one integer is 2 more than the other is with 10 and 12. However, they are NOT consecutive odd integers. So 22 could NOT be the sum of the 2 consecutive odd integers

Answer: C
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 02 May 2019, 13:35
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let's us take the two numbers as 2k+1 and 2k-1
the sum is 4k
k can be negative or positive integers.
only 22 is not a multiple of 4, rest all are.
hence option C.
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If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post Updated on: 21 May 2019, 19:41
Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


let sum of odd integers=2x+2=2(x+1)
because x and x+2 are odd, x+1 must be even
plugging in option 22=2(x+1),
it can't be sum because x+1=11, an odd number
C

Originally posted by gracie on 02 May 2019, 20:50.
Last edited by gracie on 21 May 2019, 19:41, edited 1 time in total.
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 21 May 2019, 12:21
Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


PS91602.01
Quantitative Review 2020 NEW QUESTION



ANSWER - Let the first odd integer be 2n+1, next would be - 2n+3
adding these two - 2n+1+2n+3 = 4n+4 = 4 (n+1)
So, we can say that solution will be multiple of 4.
Only option C is not multiple of 4, hence the ANSWER.

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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 23 May 2019, 17:59
Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


PS91602.01
Quantitative Review 2020 NEW QUESTION


We can check the answer choices:

-5 + (-3) = -8, so A works.

5 + 7 = 12, so B works

We see that there is no way to get 22.

Answer: C
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which  [#permalink]

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New post 23 May 2019, 18:33
Bunuel wrote:
If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers?

A. –8
B. 12
C. 22
D. 52
E. 252


PS91602.01
Quantitative Review 2020 NEW QUESTION


let odd numbers be x and x+2
Now x=5K

Sum of two odd integers- 2x+2= 2(X+1)

Now let's see if
2(5K+1) = 22 (Option C)

5K + 1= 11
5K=10, K=2.
But if k=2 then x won't be an odd number. So C.
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Re: If the smaller of 2 consecutive odd integers is a multiple of 5, which   [#permalink] 23 May 2019, 18:33
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