It is currently 17 Dec 2017, 13:33

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If x^3y^4 = 5,000, is y = 5? (1) y is a positive integer.

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Intern
Intern
avatar
Joined: 08 Nov 2008
Posts: 29

Kudos [?]: 52 [0], given: 0

If x^3y^4 = 5,000, is y = 5? (1) y is a positive integer. [#permalink]

Show Tags

New post 11 Nov 2008, 19:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x^3y^4 = 5,000, is y = 5?
(1) y is a positive integer.
(2) x is an integer.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Kudos [?]: 52 [0], given: 0

Director
Director
avatar
Joined: 14 Aug 2007
Posts: 726

Kudos [?]: 222 [0], given: 0

Re: x y integer---27 [#permalink]

Show Tags

New post 11 Nov 2008, 19:36
petercao wrote:
If x^3y^4 = 5,000, is y = 5?
(1) y is a positive integer.
(2) x is an integer.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


C.

We need to know that x is an integer and then y is positive integer
then we have
5000 = 5*5*5*5*2*2*2 = 5^4 2^3

[but it can also be that (-5)^4 2^3 thus y can be -5]

Kudos [?]: 222 [0], given: 0

Manager
Manager
avatar
Joined: 15 Oct 2008
Posts: 54

Kudos [?]: 2 [0], given: 0

Re: x y integer---27 [#permalink]

Show Tags

New post 12 Nov 2008, 00:25
alpha_plus_gamma wrote:
petercao wrote:
If x^3y^4 = 5,000, is y = 5?
(1) y is a positive integer.
(2) x is an integer.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


C.

We need to know that x is an integer and then y is positive integer
then we have
5000 = 5*5*5*5*2*2*2 = 5^4 2^3

[but it can also be that (-5)^4 2^3 thus y can be -5]



Why we need to know x is an integer? coz i cannot stimulate the case with x is not integer.

Kudos [?]: 2 [0], given: 0

Director
Director
avatar
Joined: 14 Aug 2007
Posts: 726

Kudos [?]: 222 [0], given: 0

Re: x y integer---27 [#permalink]

Show Tags

New post 12 Nov 2008, 00:40
Natasha0123 wrote:
Why we need to know x is an integer? coz i cannot stimulate the case with x is not integer.


simple case:
y = 1, x = cuberoot(5000)

Kudos [?]: 222 [0], given: 0

Manager
Manager
avatar
Joined: 15 Oct 2008
Posts: 54

Kudos [?]: 2 [0], given: 0

Re: x y integer---27 [#permalink]

Show Tags

New post 12 Nov 2008, 00:42
alpha_plus_gamma wrote:
simple case:
y = 1, x = cuberoot(5000)


I see, I totally forgot cube root, thank you :)

Kudos [?]: 2 [0], given: 0

Intern
Intern
avatar
Joined: 28 Jul 2008
Posts: 30

Kudos [?]: 4 [0], given: 0

Re: x y integer---27 [#permalink]

Show Tags

New post 15 Nov 2008, 03:27
The answer should be A. Even though Y can be both 5 and - 5, based on the question, Y must be 5, because Y must be positive.

Kudos [?]: 4 [0], given: 0

VP
VP
User avatar
Joined: 05 Jul 2008
Posts: 1402

Kudos [?]: 454 [0], given: 1

Re: x y integer---27 [#permalink]

Show Tags

New post 15 Nov 2008, 09:49
Got a C

(1) x^3 Y^4 = 5000

y= +ve integer means x3 is also positive, means x is also positive.

Y can be 5 or any thing because we don't know whether x is integer or not. For example y =10 y^ 4= 10,000 and x^3 =1/2. Hence A & D out

(2) x is integer.

Again similar logic. we dont know anything about Y

Together.

X & Y are +ve integers. X=2, Y=5 Hence C

Kudos [?]: 454 [0], given: 1

Re: x y integer---27   [#permalink] 15 Nov 2008, 09:49
Display posts from previous: Sort by

If x^3y^4 = 5,000, is y = 5? (1) y is a positive integer.

  post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderator: chetan2u



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.