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If x=8y+11 then which of the following cannot be a divisor

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If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post Updated on: 03 Oct 2013, 01:07
8
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

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If x=8y+11 then which of the following cannot be a divisor of x. (y is a whole number)?

(A)3
(B)5
(C)7
(D)12

Originally posted by guerrero25 on 02 Oct 2013, 19:13.
Last edited by Bunuel on 03 Oct 2013, 01:07, edited 1 time in total.
Added the OA.
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 02 Oct 2013, 19:47
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I think the answer is Option D "12".

Reasoning :-

A quick way to approach this problem is to see the x=8y + 11 equation & trying to quickly substituting values for "y"; If you plug in y=-1, -2, 3 you can easily see they are respectively divisible by 3, 5 & 7. But in each case, the final value of "x" will be odd due to the addition of 11 to a multiple of 8 (due to 8y). Hence, you can never have an even divisor for "x".

Thus option D (12) is the one that can not be a possible divisor for x. In hindsight, you can see that this boils down to a simple remainder problem, one where you can easily guess the answer based on the fact that x will always be "odd" and hence not divisible by an even number.

Hope it helps! :)
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 02 Oct 2013, 21:49
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guerrero25 wrote:
If x=8y+11 then which of the following cannot be a divisor of x.(y is a whole number)?
(A)3
(B)5
(C)7
(D)12

No OA available



I think D.

X =8y + 11. will always be a odd number as 8y is always even and 11 is odd, and sum of even and odd integer is odd. Now an odd integer cannot be perfectly divisible an even number. Of all the options only 12 is an even number.
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 03 Oct 2013, 08:20
guerrero25 wrote:
If x=8y+11 then which of the following cannot be a divisor of x. (y is a whole number)?

(A)3
(B)5
(C)7
(D)12


I think its D.
Since x = 8y+11 and y is a whole number, y must be even since 8y = even
Therefore even + odd = odd
Since x is odd, you cannot have an even divisor of x. 12 is the only even number on the list
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 22 Aug 2014, 02:37
You can find the solution by eliminating the choices.

Multiples of 8: 0,8,16,24,32,40,48,56,64,72,80...
(1) Plug in 2 for y, then 8*2 + 11 = 27 which is divisible by 3 --> out
(2) Plug in 3 for y, then 8*3 + 11 = 35 which is divisible by 5 --> out
(3) Plug in 10 for y, then 8*10 + 11 = 91 which is divisible by 7 --> out

Only answer left is D.
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 20 Aug 2016, 05:25
This question is incomplete. Where is option E?))
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 20 Aug 2016, 05:37
X=8y+11.
X=odd.
Even integers cant divide odd numbers.
Only 12 is odd among the answer choices.
D

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If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 20 Aug 2016, 05:40
Konstantin1983 wrote:
This question is incomplete. Where is option E?))


How does that matter if we have the answer in one of the options given? :-D
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 20 Aug 2016, 06:01
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abhimahna wrote:
Konstantin1983 wrote:
This question is incomplete. Where is option E?))


How does that matter if we have the answer in one of the options given? :-D

This increases the probability to guess this question correct :-D :-D :-D
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Re: If x=8y+11 then which of the following cannot be a divisor  [#permalink]

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New post 04 Feb 2019, 20:22
guerrero25 wrote:
If x=8y+11 then which of the following cannot be a divisor of x. (y is a whole number)?

(A)3
(B)5
(C)7
(D)12


x = 8y+11

Start plugging in values for y at 0,1,2,3,4,5,6,7

x = 11,19,27,35,43,51,59

Except 12 all 3 gets consumed by x

D
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Re: If x=8y+11 then which of the following cannot be a divisor   [#permalink] 04 Feb 2019, 20:22
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