Bunuel wrote:
If x and y are both positive numbers, is x/y > y/x?
(1) 4y/x = 5
(2) x +4 = y
since x and y are both positive... we can cross-multiply without fear of sign.
The question is...x/y > y/x ?
or,
\(x^2 > y^2\) ?
or,
\(x^2/y^2 > 1\) ?
(1) 4y/x = 5 implies y/x = 5/4 (divide by 4)
Squaring both sides...
\(y^2/x^2 = 25/16 >1\)
Sufficient as the original question is reciprocal of this, so answer is "No".
(2)
This is the tricky part. x + 4 = y
Since we know x>0 and y>0 ... hence min value of y is now 4.
since y is always 4 more than x, y^2 will always be larger than x^2.
SufficientHence
Option (D) is correct.
_________________
Regards,
Gladi
“Do. Or do not. There is no try.” - Yoda (The Empire Strikes Back)