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If x and y are positive integers, what is the remainder when x^y is

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If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 12 Jun 2015, 02:20
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 12 Jun 2015, 02:38
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Bunuel wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?

(1) x = 26
(2) y^x = 1


Kudos for a correct solution.


CONCEPT: Remainder when a number is divided by 10 remains the unit digit of Number

Question Redefined: Find unit digit of x^y?

Statement 1: x = 26

Since y is a positive integer and the cyclicity of any number with unit digit 6 remain 6 always for any positive integer exponent of it

Therefore x^y = 26^y will have Unit digit 6 for any positive Integer value of y

Hence, SUFFICIENT

Statement 2: y^x = 1

i.e. y has unit digit 1 but since the value of x is unknown therefore unit digit of x^y can't be calculated

Hence, NOT SUFFICIENT

Answer: option
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 12 Jun 2015, 02:34
If x and y are positive integers, what is the remainder when x^y is divided by 10?
(1) x = 26
(2) y^x = 1

Stmt 1 - y is not know. In Sufficient.
Stmt 2 - There are two possible solutions available. Lets take x=y=1, then y^x=1.
Lets take x=0 and y=1, then y^x=1.
Two possible solutions, In sufficient.

1+2 -> x=26, then y must be 1 to validate 1^26=1. Remainder is 6. Sufficient.

Ans C.
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 12 Jun 2015, 02:42
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balamoon wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?
(1) x = 26
(2) y^x = 1

Stmt 1 - y is not know. In Sufficient.
Stmt 2 - There are two possible solutions available. Lets take x=y=1, then y^x=1.
Lets take x=0 and y=1, then y^x=1.
Two possible solutions, In sufficient.

1+2 -> x=26, then y must be 1 to validate 1^26=1. Remainder is 6. Sufficient.

Ans C.


Hi Balamoon,

You have made a mistake in evaluating the first statement. The unit digit of x is 6 and y is a positive Integer and by the principle of cyclicity, the number with unit digit 6 will always have unit digit 6 for any positive Integer exponent of the number

Hence the first statement alone answers the question here.

I hope it clears your mistake part in above working.
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 13 Jun 2015, 02:15
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Bunuel wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?

(1) x = 26
(2) y^x = 1


Kudos for a correct solution.



Both x and y are positive integers => Both x and y are not zero.
Keeping this in mind, let us approach the question.


(1) x = 26
Here, the units digit is 6 and 6^(any number) will result in 6 as the units digit.
So, x^y => 6 as units digit => Divided by 10 will give 6 as the remainder. Sufficient.

(2) y^x = 1

Now here we can have two possibilities:
(i) 1^x = 1, where x can be any number. So, x^y = x^1 = x.
We do not get a single remainder when x is divided by 10 as it is dependent on value of x. Not Sufficient
(ii) y^0 = 1 => 0^y = 0.
:!: Here x = 0 is not possible because both x and y are POSITIVE INTEGERS :!:
So option (ii) is not possible, and per (i) y^x = 1 is Not Sufficient


Many people, including me, make a mistake by assuming value of variables to be 0 even when the question explicitly states "positive intergers". DO NOT do that.

Answer is A.


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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 15 Jun 2015, 05:05
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Bunuel wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?

(1) x = 26
(2) y^x = 1


Kudos for a correct solution.


MANHATTAN GMAT OFFICIAL SOLUTION:

(1) SUFFICIENT: The tendency is to deem statement (1) insufficient because we have no information about the value of y. But 26 has a units digit of 6, and remember that 6^(any positive integer) has a units digit of 6 (the pattern is a single-term repeat).

6^1 = 6
6^2 = 36
6^3 = 216
etc.

Thus, 26 raised to ANY positive integer power will also have a units digit of 6 and therefore a remainder of 6 when divided by 10.

(2) INSUFFICIENT: Given that y^x = 1, there are a few possible scenarios:
Attachment:
2015-06-15_1659.png
2015-06-15_1659.png [ 27.94 KiB | Viewed 2805 times ]

However, the question stem tells us that x and y are POSITIVE integers, so we eliminate the first and third scenarios.
Attachment:
2015-06-15_1700.png
2015-06-15_1700.png [ 44.81 KiB | Viewed 2804 times ]


The remaining scenario indicates that y = 1 and x = any positive integer. Without more information about x, we cannot determine the remainder when x^y is divided by 10.

Since statement (1) tells us the value of x and statement (2) indirectly tells us the value of y (y = 1), the temptation might be to combine the information to arrive at an answer of C. This is a common trap on difficult Data Sufficiency problems. It might seem that we need both statements, when one statement alone actually provides enough information.

The correct answer is A.
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 16 Jun 2015, 06:55
Bunuel wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?

(1) x = 26
(2) y^x = 1


Kudos for a correct solution.


Given
X and Y both positive.

Statement 1 :
X = 26

power cycle of 6 is 6, hence x ^ Y will always have unit's digit as 6 irrespective of Y. Henc X^y/10 will always have remainder as 6.

Hence statement 1 is sufficient.

Statement 2 :
y^x = 1
Now X > 0, hence Y = 1.

if Y = 1 and X is anything, then X^Y can be anything
Say x = 10, X^y/10 will give reminder as Zero
say X = 15, X ^Y/10 will give reminder as Five.

Statement 2 is insufficient.

Hence option A
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 17 Jun 2015, 01:03
X and Y = pos int
x^y / 10 = ? REMAINDER

1) 26^1 = 26/20 -> R = 6
26^2 = 676 / 10 -> R=6
26^3 = A large number ending in 6 -> R=6

S.

2) y^x = 1

Y = 1, x could be anything.

I.

A.
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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 07 Mar 2017, 09:50
Rule of cyclisity...
Unit digit is 6 so the power doesn't matter...n the reminder will remain 6.
So option a.

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Re: If x and y are positive integers, what is the remainder when x^y is  [#permalink]

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New post 23 Oct 2018, 05:21
Top Contributor
Bunuel wrote:
If x and y are positive integers, what is the remainder when x^y is divided by 10?

(1) x = 26
(2) y^x = 1


Kudos for a correct solution.


Given: x and y are positive integers

Target question: What is the remainder when x^y is divided by 10?
This is a good candidate for rephrasing the target question.
Notice that 43 divided by 10 leaves remainder 3, and 127 divided by 10 leaves remainder 7, and 618 divided by 10 leaves remainder 8.
So, asking for the remainder when x^y is divided by 10 is the same as asking what the units digit of x^y is. So, .....
REPHRASED target question: What is the units digit of x^y ?

Aside: See the video below for tips on rephrasing the target question

Statement 1: x = 26
IMPORTANT: if y is a positive integer, then 26^y will always have units digit 6.
Notice that 26^1 = 26, and 26^2 = 676, and 26^3 = ????6, 26^4 = ????6, etc.
So, the answer to the REPHRASED target question is the units digit of x^y is 6
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: y^x = 1
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 11 and y = 1 (notice that y^x = 1^11 = 1. In this case, x^y = 11^1 = 11. So, the answer to the REPHRASED target question is the units digit of x^y is 1
Case b: x = 12 and y = 1 (notice that y^x = 1^12 = 1. In this case, x^y = 12^1 = 12. So, the answer to the REPHRASED target question is the units digit of x^y is 2
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

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Re: If x and y are positive integers, what is the remainder when x^y is &nbs [#permalink] 23 Oct 2018, 05:21
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