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Bunuel
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WizakoBaskar
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Balajikarthick1990
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Concept:

If X is an integer with "n" digits, and is not a perfect power of 10, then it will have n-1 leading zeros.

If x is a perfect power of 10 (10^1, 10^2, 10^3 etc), then 1/x will have n-2 leading zeros.


(1) N is between 91 and 100 inclusive

Case 1: 90 to 99 are 2 digits numbers, .'. 2-1 = 1 trailing zero
Case 2: 100 is a perfect power of 10 (10^2) and is 3 digits, .'. 3-2 = 1 trailing zero

Sufficient.

(2) Stmt 2 is same as Case 1 above; 97,98,99 which are 2 digit non-perfect powers of 10s .'. 2-1 = 1 trailing zero.

Sufficient.

Hence: D
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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